This set of Manufacturing Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Miller Indices”.

1. Pattern of atoms arranged in hexagonal closed packing is given by

a) AAAAA

b) ABABAB

c) ABCABC

d) AABBAA

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Explanation: Hexagonal close packing repeats its arrangement in consecutive way. Pattern of atoms arranged in hexagonal closed packing is given by ABABAB.

2. Pattern of atoms arranged in a face centered closed packing is given by

a) AAAAA

b) ABABAB

c) ABCABC

d) AABBAA

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Explanation: Face centered close packing repeats its arrangement after two different arrangements. Pattern of atoms arrangement in face centered closed packing is given by ABCABC.

3. Planar density of face centered cubic in (111) with side ‘a’ plane is given by

a) 2.31/a ^{2}

b) 2.31/a ^{3}

c) 2.31/a ^{4}

d) 2.31/a ^{5}

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Explanation: Number of effective atoms=2. Use planar density=number of effective atom / area. Planar density of face centered cubic in (111) with side ‘a’ plane is given by 2.31/a

^{2}.

4. Planar density of face centered cubic in (111) plane with side ‘a’ is given by

a) 1/a^{2}

b) 2/a^{2}

c) 3/a^{4}

d) 4/a^{5}

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Explanation: Number of effective atoms=2. Use planar density=number of effective atom / area. Planar density of face centered cubic in (111) plane with side ‘a’ is given by 2/a

^{2}.

5. Planar density of body centered cubic in (100) with side ‘a’ plane is given by

a) 1/a^{3}

b) 2/a^{2}

c) 3/a^{4}

d) 1/a^{2}

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Explanation: Number of effective atoms=1. Area= a

^{2}Use planar density=number of effective atom / area. Planar density of body centered cubic in (100) with side ‘a’ plane is given by 1/a

^{2}.

6. Planar density of body centered cubic in (110) with side ‘a’ plane is given by

a) 4/a^{2}

b) 3.141/a^{2}

c)1.1414/a^{4}

d) 4/a^{3}

View Answer

Explanation: Number of effective atoms=2. Area= √2a

^{2}.Use planar density=number of effective atom / area. Planar density of body centered cubic in (110) with side ‘a’ plane is given by 1.1414/a

^{4}.

7. Planar density of simple cubic in (110) with side ‘a’ plane is given by

a) 0.508/a^{2}

b) 0.707/a^{3}

c) 0.707/a^{4}

d) 0.707/a^{5}

View Answer

Explanation: Number of effective atoms=1. area=√2a

^{2}Use planar density=number of effective atom / area. Planar density of simple cubic in (110) with side ‘a’ plane is given by 0.707/a

^{3}.

8. Planar density of simple cubic in (111) with side ‘a’ plane is given by

a) 2.31/a^{2}

b) 2.31/a^{3}

c) 1.31/a^{2}

d) 3.31/a^{2}

View Answer

Explanation: Number of effective atoms=0.5.area=.866a

^{2}Use planar density=number of effective atom / area. Planar density of simple cubic in (111) with side ‘a’ plane is given by 2.31/a

^{2}.

9. Braggs law of diffraction is given by which of the following equation? Symbols have usual meanings.

a) 2d sinθ=λ

b) 2d=nλ

c) 2d=nλ sinθ

d) 2d sinθ=nλ

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Explanation: It can be derived from the basic wave reflecting diagram incident at angle θ. λ is used to denote the wavelength of the wave.

10. Powder crystal method is used to determine crystal structures

a) True

b) False

View Answer

Explanation: This is an experimental technique, used to determine crystal structure for high symmetrical crystals.

**Sanfoundry Global Education & Learning Series – Manufacturing Engineering.**

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