This set of Engineering Drawing Multiple Choice Questions & Answers (MCQs) focuses on “Projection of Points in Second Quadrant”.

1. A point is in 2^{nd} quadrant 20 units away from the horizontal plane and 10 units away from the vertical plane. Orthographic projection is drawn. What is the distance from point of front view to reference line, top view point to reference line?

a) 20, 10

b) 10, 20

c) 0, 20

d) 10, 0

View Answer

Explanation: Given object is point placed in 2

^{nd}quadrant the top view gives the distance from vertical plane (10) and front view gives the distance from horizontal plane (20) both are placed overlapped in orthographic projection since the object is placed in the 2nd quadrant.

2. A point is in 2^{nd} quadrant 15 units away from the vertical plane and 10 units away from the horizontal plane. Orthographic projection is drawn. What is the distance from point of front view to reference line, top view point to reference line?

a) 15, 10

b) 10, 15

c) 0, 15

d) 10, 0

View Answer

Explanation: Given object is point the top view gives the distance from vertical plane (15) and front view gives the distance from horizontal plane (10) both are placed overlapped in orthographic projection since the planes need to rotate to draw projection as the object is placed in the 2nd quadrant.

3. A point is in 2^{nd} quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of top view?

a) 5

b) 2

c) 7

d) 8

View Answer

Explanation: As the point is in 2

^{nd}quadrant while drawing the projections the planes should rotate along the hinges such that the plane with top view overlaps the front view. So the distance between them is difference of distances from respective planes that is 5 (15-10) here.

4. A point is in 2^{nd} quadrant, 15 units away from the vertical plane, 10 units away from the horizontal plane and 8 units away from the profile plane. Orthographic projection is drawn. What is the distance from point of front view to point of side view?

a) 25

b) 23

c) 18

d) 5

View Answer

Explanation: Side view is obtained by turning the profile plane along the hinge with vertical parallel to vertical plane. Side view and front view have same distance from reference line. Sum of distances from the point to vertical plane and profile plane gives the following that is 15+8 = 23 units.

5. A point in 2^{nd} quadrant is 15 cm away from both the horizontal plane and vertical plane and orthographic projections are drawn. The distance between the points formed by front view and top view is _________

a) 0

b) 30

c) 15

d) 15+ distance from a profile

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. While drawing orthographic projections the front view and top view overlaps and also the distance of point is same from planes of projections so the distance between them is zero.

6. A point in 2^{nd} quadrant is 10 units away from the horizontal plane and 13 units away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and front view.

a) 10

b) 13

c) 20

d) 26

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. The distance from side view to vertical reference is 13 and distance from front view to profile plane is 13. Sum is 13+13= 26.

7. A point in 2^{nd} quadrant is 25 units away from both the horizontal plane and profile plane and 15 units away from the vertical plane. Orthographic projections are drawn find the distance from side view and front view.

a) 25

b) 15

c) 30

d) 40

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. The distance from side view to vertical reference is 15 and distance from front view to profile plane is 25. Sum is 15+25 =40.

8. A point in 2^{nd} quadrant is 12 units away from the horizontal plane and vertical plane and 13 units away from both the profile plane. Orthographic projections are drawn find the distance from side view and front view.

a) 13

b) 26

c) 25

d) 24

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The front view and side view lie parallel to the horizontal plane when orthographic projections are drawn. The distance from side view to vertical reference is 12 and distance from front view to profile plane is 13. Sum 12 + 13 =25.

9. A point in 2^{nd} quadrant is 15 units away from the horizontal plane and 10 units away from both the vertical plane and profile plane. Orthographic projections are drawn find the distance from side view and top view.

a) 25

b) 20.6

c) 25.49

d) 15.8

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. Since here distance from side view and top view is asked for that we need the distance between the front view and side view (10+10); front view and top view (10-15) and these lines which form perpendicular to each other gives needed distance, answer is √(20

^{2}+5

^{2}) = 20.6 units.

10. A point in 2^{nd} quadrant is 25 units away from both the horizontal plane and profile plane 15 units away from the vertical plane. Orthographic projections are drawn find the distance from the side view and top view.

a) 40

b) 50.99

c) 33.54

d) 41.23

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. Since here distance from side view and top view is asked for that we need the distance between the front view and side view (25+15); front view and top view (25-15) and these lines which form perpendicular to each other gives needed distance, answer is √(40

^{2}+10

^{2}) = 41.23units.

11. A point in 2^{nd} quadrant is 12 units away from the horizontal plane and vertical plane 13 units away from both the profile plane. Orthographic projections are drawn find the distance from the side view and top view.

a) 25.6

b) 25

c) 17.69

d) 13

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. Since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+13); front view and top view (12-12) and these lines which form perpendicular to each other gives needed distance, answer is √(25

^{2}+0

^{2}) = 25units.

12. A point in 2^{nd} quadrant is 10 cm away from the vertical plane and 15 cm away from the horizontal plane, orthographic projections are drawn. What is the distance from a side view of point to line of vertical reference?

a) 10

b) 15

c) 25

d) Can’t found

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The distance from the side view of point to line of vertical reference will be the distance from the point to the vertical plane in plane of projection that is as given 10 cm.

13. A point is in 2^{nd} quadrant which is 5 meters away from horizontal and 3 meters away from profile plane. Orthographic projections are drawn. What is the distance from the top view to xy reference line?

a) 5

b) 3

c) 8

d) Can’t found

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The xy reference line is between the vertical plane and horizontal plane but distance from a vertical point is not given in question so we can’t found some given information.

14. A point is in 2^{nd} quadrant which is 7 meters away from horizontal and 2 meters away from profile plane. Orthographic projections are drawn. What is the distance from the front view to xy reference line?

a) 7

b) 2

c) 5

d) 9

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The distance from front view is given by distance between point and horizontal plane here it is given 7 meters. And distance from vertical reference will be 2 meters.

15. A point is in 2^{nd} quadrant which is 8 meters away from vertical and 6 meters away from profile plane. Orthographic projections are drawn. What is the distance from the side view to vertical reference line?

a) 8

b) 6

c) 2

d) Can’t found

View Answer

Explanation: Given the point is in 2

^{nd}quadrant. The distance from the side view is given by distance between point and vertical plane here it is given 8 meters. And the distance from front view will be 6 meters.

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