# Engineering Drawing Questions and Answers – Methods of Constructing Parallel Scale Nomographs

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This set of Engineering Drawing Multiple Choice Questions & Answers (MCQs) focuses on “Methods of Constructing Parallel Scale Nomographs”.

1. For the equation Z = X*Y which type of scale is most preferred?
a) Natural scale
b) Logarithmic scale
c) Linear scale
d) Uniform scale

Explanation: We have scales classified as linear and non-linear scales. The non-linear scales are also called as logarithmic scales. Z = X+Y or Z = X-Y are the standard forms, but Z = X*Y, need to be converted into standard form by applying log on both sides, thus transformed into logZ = logX+logY. This requires a logarithmic scale.

2. In case Z = X+Y and Z = X-Y type of equations natural scales are used during nomograph.
a) True
b) False

Explanation: Z = X+Y or Z = X-Y are the standard forms for the three parallel scale nomographs, hence linear scales are used. The linear scales are also known as uniform scales or natural scales.

3. While plotting into parallel scales, the direction of negative values of a variable is ___________ the direction of positive values of the variable.
a) Perpendicular to
b) Opposite to
c) Same as
d) 45 inclined to

Explanation: When plotting parallel scales nomographs, negative values need to be laid opposite to that of positive values of the variables.
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4. For the function having variables with the negative sign, has ___________ scale.
a) Natural scale
b) Logarithmic scale
c) Linear scale
d) Inverted scale

Explanation: When plotting parallel scales nomographs, negative sign variables has an inverted scale and the origins are in alignment.

5. For plotting Z = X-Y, which variable(s) has an inverted scale?
a) Z
b) X
c) Y
d) X, Y

Explanation: When plotting parallel scales nomographs, negative sign variables have an inverted scale and the origins are in alignment. In equation Z = X-Y, variable Y has a negative sign hence it has an inverted scale.
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6. For the equation Z = 2(X+Y), find the functional modulus of X. If the length of the scale is L = 10cm and the values are as follows

 X 0 1 2 3 4 5 Y 0 2 4 6 8 10 Z 0 6 12 18 24 30

a) 2
b) 1
c) 3
d) 4

Explanation: Functional modulus of X is calculated as L/(f(Xmax)-f(Xmin)), here L = 10, f(Xmax) = 5, and f(Xmin) = 0. Hence mX = 10/(5-0) = 2.

7. For the equation Z = 2(X+Y), find the functional modulus of Y. If the length of the scale is L = 10cm and the values are as follows.

 X 0 1 2 3 4 5 Y 0 2 4 6 8 10 Z 0 6 12 18 24 30

a) 2
b) 1
c) 3
d) 4

Explanation: Functional modulus of Y is calculated as L/(f(Ymax)-f(Ymin)), here L = 10, f(Ymax) = 10, and f(Ymin) = 0. Hence mY = 10/(10-0) = 1.

8. For the equation Z = 2(X+Y), find the scale modulus of X. If the length of the scale is L = 10cm and the values are as follows.

 X 0 1 2 3 4 5 Y 0 2 4 6 8 10 Z 0 6 12 18 24 30

a) 2
b) 1
c) 3
d) 4

Explanation: Scale modulus of X is calculated as [L/(f(Xmax)-f(Xmin))]*2, where 2 is constant coefficient of the given function , here L = 10, f(Xmax) = 5, and f(Xmin) = 0. Hence MX = [10/(5-0) ]*2 = 4.

9. For the equation Z = 2(X+Y), find the scale modulus of Y. If the length of the scale is L = 10cm and the values are as follows.

 X 0 1 2 3 4 5 Y 0 2 4 6 8 10 Z 0 6 12 18 24 30

a) 2
b) 1
c) 3
d) 4

Explanation: Scale modulus of Y is calculated as [L/(f(Ymax)-f(Ymin))]*2, where 2 is constant coefficient of the given function , here L = 10, f(Ymax) = 10, and f(Ymin) = 0. Hence MY = [10/(10-0)]*2 = 2.

10. If the mX = 2 and mY = 1, and find the value of functional modulus of Z.
a) 1/2
b) 2/3
c) 3/2
d) 2/1

Explanation: The function modulus of mZ = (mX+mY)/(mX*mY), here mX = 2 and mY = 1. Hence functional modulus of Z = 1*2/(1+2) = 2/3.

11. If the mZ = 2/3, and find the value of scale length of Z, from the following Z values.

 X 0 1 2 3 4 5 Y 0 2 4 6 8 10 Z 0 6 12 18 24 30

a) 10cm
b) 20cm
c) 15cm
d) 35cm

Explanation: The length of the scale is calculated as mZ*[f(Zmax)-f(Xmin)], where f(Zmax) = 30, [f(Xmin)] = 0, mZ = 2/3, hence scale length for variable Z = 2*(30-0)/3 = 20cm.

12. We need to select a suitable length of the scale for a good fit of the nomograph in the given space.
a) True
b) False

Explanation: In plotting the functions, we need to find function and scale modulus. To find them we need to fix a suitable scale length that fits in the given space given.

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