This set of Engineering Drawing Multiple Choice Questions & Answers (MCQs) focuses on “Projection of Points in First Quadrant”.

a) single point, two points

b) two points, single point

c) single point, single point

d) two points, two points

View Answer

Explanation: Here given the two points such that the joining line is perpendicular to profile plane in 1st quadrant asked side view and top view. The views in any quadrant will remain same but the relative positions in projection will change accordingly the quadrant.

2. A point is 5 units away from the vertical plane and 4 units away from profile plane and 3 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is _____________

a) 7 units

b) 8 units

c) 9 units

d) 5 units

View Answer

Explanation: Since the point is 3 units away from the horizontal plane the distance from the point to xy reference line will be 3 units. And then the point is at distance of 5 units from the vertical plane the distance from reference line and point will be 5, sum is 8.

3. A point is 8 units away from the vertical plane and 2 units away from profile plane and 4 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and front view of point is _______________

a) 12 units

b) 6 units

c) 10 units

d) 8 units

View Answer

Explanation: Since the point is 2 units away from the profile plane the distance from the point to reference line will be 2 units. And then the point is at distance of 8 units from the vertical plane the distance from reference line and point will be 8, sum is 10.

4. A point is 2 units away from the vertical plane and 3 units away from profile plane and 7 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and side view of point is ______________

a) 10

b) 5

c) 9

d) 7

View Answer

Explanation: Since the point is 3 units away from the profile plane the distance from the point to reference line will be 3 units. And then the point is at distance of 2 units from the profile plane the distance from reference line and point will be 2 units, sum is 5.

a) 29 units

b) 21 units

c) 32 units

d) 11 units

View Answer

Explanation: Since the point is 12 units away from the profile plane the distance from the point to reference line will be 12 units. And then the point is at distance of 20 units from profile plane the distance from reference line and point will be 20 units, sum is 32.

6. A point is 2 units away from the vertical plane and 3 units away from profile plane and 7 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the shortest distance from top view and side view of point is _____________

a) 10.29

b) 5.14

c) 9

d) 7

View Answer

Explanation: Since here distance from side view and top view is asked for that we need the distance between the front view and side view (3+2); front view and top view (7+2)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(5

^{2}+9

^{2}) =10.29 units.

7. If a point P is placed in between the projection planes. The distance from side view to reference line towards front view and the distance between top view and reference line towards top view will be same.

a) True

b) False

View Answer

Explanation: The projection will be drawn by turning the other planes parallel to vertical plane in clockwise direction along the lines of intersecting of planes. And so as we fold again the planes at respective reference lines and then drawing perpendiculars to the planes at those points the point of intersection gives the point P.

8. A point is 20 units away from the vertical plane and 12 units away from profile plane and 9 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the side view and top view of point is ________________

a) 29 units

b) 21 units

c) 35.8 units

d) 17.9 units

View Answer

Explanation: Since here distance from side view and top view is asked for that we need the distance between the front view and side view (12+9); front view and top view (9+20)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(21

^{2}+29

^{2}) = 35.80 units.

a) 15

b) 10

c) 32.5

d) 18.02 units

View Answer

Explanation: Since here distance from side view and top view is asked for that we need the distance between the front view and side view (5+5); front view and top view (10+5)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √(10

^{2}+15

^{2}) = 18.02 units.

10. A point is 15 units away from the vertical plane and 12 units away from profile plane and horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is ______________

a) 27

b) 15

c) 12

d) 24

View Answer

Explanation: Since the point is 12 units away from the horizontal plane the distance from the point to xy reference line will be 12 units. And then the point is at distance of 15 units from the vertical plane the distance from reference line and point will be 15, sum is 27.

11. A point is 12 units away from the vertical plane and profile plane 15 units away from horizontal plane in 1st quadrant then the projections are drawn on paper the distance between the front view and side view of point is ________________

a) 27

b) 15

c) 12

d) 24

View Answer

Explanation: Since the point is 12 units away from the profile plane the distance from the point to xy reference line will be 12 units. And then the point is at distance of 12 units from the profile plane the distance from reference line and point will be 12, sum is 24.

12. A point is 7 units away from the vertical plane and horizontal plane 9 units away from profile plane in 1st quadrant then the projections are drawn on paper the distance between the front view and top view of point is _____________

a) 27

b) 15

c) 16

d) 14

View Answer

Explanation: Since the point is 7 units away from the horizontal plane the distance from the point to xy reference line will be 7 units. And then the point is at distance of 7 units from the vertical plane the distance from reference line and point will be 7, sum is 14 units.

13. A point is 16 units away from the vertical plane and horizontal plane 4 units away from profile plane in 1st quadrant then the projections are drawn on paper the distance between the side view and top view of point is ______________

a) 37.73 units

b) 32.98 units

c) 16

d) 8

View Answer

Explanation: Since here distance from side view and top view is asked for that we need the distance between the front view and side view (4+16); front view and top view (16+16)and these lines which form perpendicular to each other gives needed distance, answer is square root of squares of both the distances √20

^{2}+32

^{2}) = 37.73 units.

**Sanfoundry Global Education & Learning Series – Engineering Drawing.**

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