# Engineering Drawing Questions and Answers – Drawing Regular Polygons & Simple Curves – 1

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This set of Engineering Drawing Multiple Choice Questions & Answers (MCQs) focuses on “Drawing Regular Polygons & Simple Curves – 1”.

1. A Ogee curve is a ___________
a) semi ellipse
b) continuous double curve with convex and concave
c) freehand curve which connects two parallel lines
d) semi hyperbola

Explanation: An ogee curve or a reverse curve is a combination of two same curves in which the second curve has a reverse shape to that of the first curve. Any curve or line or mould consists of a continuous double curve with the upper part convex and lower part concave, like ‘’S’’.

2. Given are the steps to construct an equilateral triangle, when the length of side is given. Using, T-square, set-squares only. Arrange the steps.
i. The both 2 lines meet at C. ABC is required triangle
ii. With a T-square, draw a line AB with given length
iii. With 30o-60o set-squares, draw a line making 60o with AB at A
iv. With 30o-60o set-squares, draw a line making 60o with AB at B
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Here gives the simple procedure since T-square and 30o-60o set-squares. And also required triangle is equilateral triangle. The interior angles are 60o, 60o, 60o (180o /3 = 60o). Set- squares are used for purpose of 60o.

3. Given are the steps to construct an equilateral triangle, with help of a compass, when the length of a side is given. Arrange the steps.
i. Draw a line AB with given length
ii. Draw lines joining C with A and B
iii. ABC is required equilateral triangle
iv. With centers A and B and radius equal to AB, draw arcs cutting each other at C
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Here gives the simple procedure to construct an equilateral triangle. Since we used compass we can construct any type of triangle but with set-squares it is not possible to construct any type of triangles such as isosceles, scalene etc.
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4. Given are the steps to construct an equilateral triangle when the altitude of a triangle is given. Using, T-square, set-squares only. Arrange the steps.
i. Join R, Q; T, Q. Q, R, T is the required triangle
ii. With a T-square, draw a line AB of any length
iii. From a point P on AB draw a perpendicular PQ of given altitude length
iv. With 30o-60o set-squares, draw a line making 30o with PQ at Q on both sides cutting at R, T
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Here gives the simple procedure since T-square and 30o-60o set-squares. The interior angles are 60o, 60o, 60o (180o /3 = 60o). Altitude divides the sides of equilateral triangle equally. Set- squares are used for purpose of 30o.

5. Given are the steps to construct an equilateral triangle, with help of a compass, when the length of altitude is given. Arrange the steps.
i. Draw a line AB of any length. At any point P on AB, draw a perpendicular PQ equal to altitude length given
ii. Draw bisectors of CE and CF to intersect AB at R and T respectively.QRT is required triangle
iii. With center Q and any radius, draw an arc intersecting PQ at C
iv. With center C and the same radius, draw arcs cutting the 1st arc at E and F
a) i, iii, iv, ii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: This is the particular procedure used for only constructing an equilateral triangle using arcs when altitude is given since we used similar radius arcs to get 30o on both sides of a line. Here we also bisected arc using the same procedure from bisecting lines.

6. How many pairs of parallel lines are there in regular Hexagon?
a) 2
b) 3
c) 6
d) 1

Explanation: Hexagon is a closed figure which has six sides, six corners. Given is regular hexagon which means it has equal interior angles and equal side lengths. So, there will be 3 pair of parallel lines in a regular hexagon. 7. Given are the steps to construct a square when the length of a side is given. Using, T-square, set-squares only. Arrange the steps.
i. Repeat the previous step and join A, B, C and D to form a square
ii. With a T-square, draw a line AB with given length.
iii. At A and B, draw verticals AE and BF
iv. With 45o set-squares, draw a line making 45o with AB at A cuts BF at C
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Square is closed figure with equal sides and equal interior angles which is 90o. In the above steps, it is given the procedure to draw a square using set-squares. 45o set-square is used since 90/2 = 45.

8. How many pairs of parallel lines are there in a regular pentagon?
a) 0
b) 1
c) 2
d) 5

Explanation: Pentagon is a closed figure which has five sides, five corners. Given is regular pentagon which means it has equal interior angles and equal side lengths. Since five is odd number so, there exists angles 36o, 72o, 108o, 144o, 180o with sides to horizontal.

9. Given are the steps to construct a square using a compass when the length of the side is given. Arrange the steps.
i. Join A, B, C and D to form a square
ii. At A with radius AB draw an arc, cut the AE at D
iii. Draw a line AB with given length. At A draw a perpendicular AE to AB using arcs
iv. With centers B and D and the same radius, draw arcs intersecting at C
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Here we just used simple techniques like drawing perpendiculars using arcs and then used the compass to locate the fourth point. Using the compass it is easier to draw different types of closed figures than using set-squares.

10. Given are the steps to construct regular polygon of any number of sides. Arrange the steps.
i. Draw the perpendicular bisector of AB to cut the line AP in 4 and the arc AP in 6
ii. The midpoint of 4 and 6 gives 5 and extension of that line along the equidistant points 7, 8, etc gives the centers for different polygons with that number of sides and the radius is AN (N is from 4, 5, 6, 7, so on to N)
iii. Join A and P. With center B and radius AB, draw the quadrant AP
iv. Draw a line AB of given length. At B, draw a line BP perpendicular and equal to AB
a) i, iv, ii, iii
b) iii, ii, iv, i
c) iv, iii, i, ii
d) ii, iii, iv, i

Explanation: Given here is the method for drawing regular polygons of a different number of sides of any length. This includes finding a line where all the centers for regular polygons lies and then with radius taking any end of 1st drawn line to center and then completing circle at last, cutting the circle with the same length of initial line. Thus we acquire polygons.

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