This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Quality Factor”.

1. Quality factor is also known as _________

a) Voltage magnification

b) Current magnification

c) Resistance magnification

d) Impedance magnification

View Answer

Explanation: Quality factor is also known as voltage magnification because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.

2. At resonance condition, the voltage across the capacitor and inductor is _________ the source voltage.

a) Greater than

b) Less than

c) Equal to

d) Much less than

View Answer

Explanation: In the resonance condition, the voltage across the capacitor and inductor is greater than the source voltage because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.

3. What is the voltage across the capacitor when the source voltage is 100V and the Q factor is 10?

a) 100V

b) 10V

c) 1000V

d) 0V

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{C}/V

_{S}where V

_{C}is capacitive voltage and V

_{S}is source voltage.

10=V

_{C}/100

V

_{C}=1000 V.

4. Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.

a) 10

b) 20

c) 30

d) 40

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{C}/V

_{S}where V

_{C}is capacitive voltage and V

_{S}is source voltage. Q=1000/100 = 10 V.

5. Find the source voltage when the voltage across the capacitor is 1000V and the Q factor is 10.

a) 10V

b) 200V

c) 100V

d) 90V

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{C}/V

_{S}where V

_{C}is capacitive voltage and V

_{S}is source voltage. 10=1000/V

_{S}

V

_{S}=100 V.

6. What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?

a) 100V

b) 20V

c) 2000V

d) 0V

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{L}/V

_{S}where V

_{L}is inductive voltage and V

_{S}is source voltage. 10=V

_{L}/200 => V

_{L}= 2000 V.

7. Find the Q factor when the voltage across the inductor is 2000V and the source voltage is 100V.

a) 10

b) 20

c) 30

d) 40

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{L}/V

_{S}where V

_{L}is inductive voltage and V

_{S}is source voltage. Q=2000/100=20.

8. Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.

a) 10V

b) 200V

c) 100V

d) 90V

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.

Q=V

_{L}/V

_{S}where V

_{L}is inductive voltage and V

_{S}is source voltage.

20=2000/V

_{S}

V

_{S}=100 V.

9. What happens to the voltage across the capacitor when the Q factor increases?

a) Increases

b) Decreases

c) Remains the same

d) Becomes zero

View Answer

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Hence as the Q factor increases, the voltage across the capacitor also increases.

10. What happens to the voltage across the inductor when the Q factor decreases?

a) Increases

b) Decreases

c) Remains the same

d) Becomes zero

View Answer

Explanation: We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. Hence as the Q factor decreases, the voltage across the inductor also decreases.

**Sanfoundry Global Education & Learning Series – Basic Electrical Engineering.**

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