# Basic Electrical Engineering Questions and Answers – Quality Factor

«
»

This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Quality Factor”.

1. Quality factor is also known as _________
a) Voltage magnification
b) Current magnification
c) Resistance magnification
d) Impedance magnification

Explanation: Quality factor is also known as voltage magnification because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.

2. At resonance condition, the voltage across the capacitor and inductor is _________ the source voltage.
a) Greater than
b) Less than
c) Equal to
d) Much less than

Explanation: In the resonance condition, the voltage across the capacitor and inductor is greater than the source voltage because the voltage across the capacitor or inductor in resonance condition is equal to Q times the source voltage.

3. What is the voltage across the capacitor when the source voltage is 100V and the Q factor is 10?
a) 100V
b) 10V
c) 1000V
d) 0V

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VC/VS where VC is capacitive voltage and VS is source voltage.
10=VC/100
VC=1000 V.
Sanfoundry Certification Contest of the Month is Live. 100+ Subjects. Participate Now!

4. Find the Q factor when the voltage across the capacitor is 1000V and the source voltage is 100V.
a) 10
b) 20
c) 30
d) 40

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VC/VS where VC is capacitive voltage and VS is source voltage. Q=1000/100 = 10 V.

5. Find the source voltage when the voltage across the capacitor is 1000V and the Q factor is 10.
a) 10V
b) 200V
c) 100V
d) 90V

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VC/VS where VC is capacitive voltage and VS is source voltage. 10=1000/VS
VS=100 V.

6. What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?
a) 100V
b) 20V
c) 2000V
d) 0V

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VL/VS where VL is inductive voltage and VS is source voltage. 10=VL/200 => VL = 2000 V.

7. Find the Q factor when the voltage across the inductor is 2000V and the source voltage is 100V.
a) 10
b) 20
c) 30
d) 40

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VL/VS where VL is inductive voltage and VS is source voltage. Q=2000/100=20.

8. Find the source voltage when the voltage across the inductor is 2000V and the Q factor is 20.
a) 10V
b) 200V
c) 100V
d) 90V

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage.
Q=VL/VS where VL is inductive voltage and VS is source voltage.
20=2000/VS
VS=100 V.

9. What happens to the voltage across the capacitor when the Q factor increases?
a) Increases
b) Decreases
c) Remains the same
d) Becomes zero

Explanation: We know that voltage across the capacitor in resonance condition is equal to Q times the source voltage. Hence as the Q factor increases, the voltage across the capacitor also increases.

10. What happens to the voltage across the inductor when the Q factor decreases?
a) Increases
b) Decreases
c) Remains the same
d) Becomes zero

Explanation: We know that voltage across the inductor in resonance condition is equal to Q times the source voltage. Hence as the Q factor decreases, the voltage across the inductor also decreases.

Sanfoundry Global Education & Learning Series – Basic Electrical Engineering.

To practice all areas of Basic Electrical Engineering, here is complete set of 1000+ Multiple Choice Questions and Answers. 