This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Kirchhoff’s Current Law”.

1. Find the value of v if v1=20V and value of current source is 6A.

a) 10V

b) 12V

c) 14V

d) 16V

View Answer

Explanation: The current through the 10 ohm resistor=v1/10=2A.Applying KCL at node 1: i5=i10+i2. i2=6-2=4A.

Thus the drop in the 2 ohm resistor = 4×2 = 8V.

v1=20V; hence v2=20-v across 2 ohm resistor=20-8=12V

v2=v since they are connected in parallel.

v=12V.

2. Calculate the current A.

a) 5A

b) 10A

c) 15A

d) 20A

View Answer

Explanation: KCl states that the total current leaving the junction is equal to the current entering it. In this case, the current entering the junction is 5A+10A=15A.

3. Calculate the current across the 20 ohm resistor.

a) 20A

b) 1A

c) 0.67A

d) 0.33A

View Answer

Explanation: Assume lower terminal of 20 ohm at 0V and upper terminal at V volt and applying KCL, we get V/10 +V/20 =1. V=20/3V So current through 20 ohm = V/20 = (20/3)/20 =1/3=0.33V.

4. Calculate the value of I3, if I1= 2A and I2=3A.

a) -5A

b) 5A

c) 1A

d) -1A

View Answer

Explanation: According to KCl, I1+I2+I3=0. Hence I3=-(I1+I2)=-5A.

5. Find the value of i2, i4 and i5 if i1=3A, i3=1A and i6=1A.

a) 2,-1,2

b) 4,-2,4

c) 2,1,2

d) 4,2,4

View Answer

Explanation: At junction a: i1-i3-i2=0. i2=2A.

At junction b: i4+i2-i6=0. i4=-1A.

At junction c: i3-i5-i4=0. i5=2A.

6. What is the value of current if a 50C charge flows in a conductor over a period of 5 seconds?

a) 5A

b) 10A

c) 15A

d) 20A

View Answer

Explanation: Current=Charge/Time. Here charge = 50c and time = 5seconds, so current = 50/5 = 10A.

7. KCL deals with the conservation of?

a) Momentum

b) Mass

c) Potential Energy

d) Charge

View Answer

Explanation: KCL states that the amount of charge entering a junction is equal to the amount of charge leaving it, hence it is the conservation of charge.

8. KCL is applied at _________

a) Loop

b) Node

c) Both loop and node

d) Neither loop nor node

View Answer

Explanation: KCL states that the amount of charge leaving a node is equal to the amount of charge entering it, hence it is applied at nodes.

9. KCL can be applied for __________

a) Planar networks

b) Non-planar networks

c) Both planar and non-planar

d) Neither planar nor non-planar

View Answer

Explanation: KCL is applied for different nodes of a network whether it is planar or non-planar.

10. What is the value of the current I?

a) 8A

b) 7A

c) 6A

d) 5A

View Answer

Explanation: At the junction, I-2+3-4-5=0. Hence I=8A.

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