# Basic Electrical Engineering Questions and Answers – Resistance and Capacitance in Series

«
»

This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Resistance and Capacitance in Series”.

1. If in an alternating current circuit, resistance is 5 ohm, capacitive reactance is 12 ohm, what is the impedance?
a) 5 ohm
b) 10 ohm
c) 12 ohm
d) 13 ohm

Explanation: R=5Ω, XC=12Ω
Z2=R2+XC2 Substituting the values we get,
Z2 = 52 + 122
Z2 = 169
Z=13 Ω.

2. If in an alternating current circuit, impedance is 26 ohm, capacitive reactance is 24 ohm, what is the resistance?
a) 25 ohm
b) 10 ohm
c) 12 ohm
d) 23 ohm

Explanation: Z=26Ω, XC=24Ω
Z2=R2+XC2 Substituting the values we get,
262 = R2 + 242
676 = R2 + 576
R2 = 100
R=10 Ω.

3. If in an alternating current circuit, capacitance of 30 µF is connected to a supply of 200V,50Hz. Find the current in the circuit.
a) 1.38 A
b) 1.89 A
c) 1.74 A
d) 0.89 A

Explanation: XC=1/(2πfC)=106.1
I=V/XC=200/106.1=1.89 A.
Note: Join free Sanfoundry classes at Telegram or Youtube

4. If in an alternating current circuit, capacitance C is connected to a supply of 200V,50Hz. Current in the circuit is 1.89 A. Find the capacitance C.
a) 30 µF
b) 20 µF
c) 10 µF
d) 15 µF

Explanation: XC= V/I = 200/1.89 = 106.1 Ω. XC=1/(2πfC) Substituting the values we get C = 30 µF.

5. In ac circuit, resistance 5 ohm is connected with capacitor having capacitive reactance 12 ohm. Supply of 260 V is connected to the circuit. Calculate the current in the circuit.
a) 40 A
b) 10 A
c) 20 A
d) 30 A

Explanation: Z2=R2+XC2 Substituting the values we get Z2 = 52 + 122
Z2 = 169
Z=13 Ω.
I=V/Z = 260/13=20 A.
Take Basic Electrical Engineering Mock Tests - Chapterwise!
Start the Test Now: Chapter 1, 2, 3, 4, 5, 6, 7, 8, 9, 10

6. In ac circuit, resistance 5 ohm is connected with capacitor having capacitive reactance 12 ohm. Supply of 260 V is connected to the circuit. Calculate the voltage across resistance.
a) 300 V
b) 200 V
c) 240 V
d) 100 V

Explanation: Z2=R2+XC2 Substituting the values we get
Z2 = 52 + 122
Z2 = 169
Z=13 Ω.
I = V/Z = 260/13=20 A.
VR=iR=20*5=100 V.

7. In ac circuit, resistance 5 ohm is connected with a capacitor having capacitive reactance 12 ohm. Supply of 260 V is connected to the circuit. Calculate the voltage across a capacitor.
a) 300 V
b) 200 V
c) 240 V
d) 100 V

Explanation: Z2=R2+XC2 Substituting the values we get
Z2 = 52 + 122
Z2 = 169
Z=13 Ω.
I = V/Z = 260/13=20 A.
VC=iXC=20*12=240 V.

Sanfoundry Global Education & Learning Series – Basic Electrical Engineering.

To practice all areas of Basic Electrical Engineering, here is complete set of 1000+ Multiple Choice Questions and Answers. 