This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Bandwidth”.

1.The SI unit for bandwidth is?

a) Hz

b) Watt

c) kHz

d) kW

View Answer

Explanation: The SI unit for bandwidth is Hz. Hertz is the SI unit because bandwidth is basically frequency and the unit for frequency is Hz.

2. At bandwidth frequency range, the value of the current I is?

a) I=Im/2

b) I=Im^{2}

c) I=Im

d) I=Im/√2

View Answer

Explanation: At the bandwidth frequency range, the value of the current is equal to the maximum value of current divided by √2.

3. At bandwidth frequency range, the value of the voltage V is?

a) V=Vm/2

b) V=Vm^{2}

c) V=Vm

d) V=Vm/√2

View Answer

Explanation: At the bandwidth frequency range, the value of the voltage is equal to the maximum value of voltage divided by √2.

4. At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum current to flow.

a) 33.33

b) 66.67

c) 50

d) 70.7

View Answer

Explanation: At resonance, bandwidth includes the frequency range that allows 70.2 percent of the maximum current to flow. This is because at the bandwidth frequency range, the value of the current is equal to the maximum value of current divided by √2.

5. At resonance, bandwidth includes the frequency range that allows _____ percent of the maximum voltage to flow.

a) 33.33

b) 66.67

c) 50

d) 70.7

View Answer

Explanation: At resonance, bandwidth includes the frequency range that allows 70.2 percent of the maximum voltage to flow. This is because at the bandwidth frequency range, the value of the voltage is equal to the maximum value of voltage divided by √2.

6. Find the value of current when the maximum value of current is 50A in the bandwidth range.

a) 56.65A

b) 35.36A

c) 45.34A

d) 78.76A

View Answer

Explanation: At the bandwidth frequency range, the value of the current is equal to the maximum value of current divided by √2. Hence I =50/√2= 35.36A.

7. Find the value of voltage when the maximum value of voltage is 100V.

a) 56.65A

b) 35.36A

c) 45.34A

d) 70.72A

View Answer

Explanation: At the bandwidth frequency range, the value of the voltage is equal to the maximum value of voltage divided by √2. Hence V =100/√2= 70.72V.

8. If the resonant frequency in a series RLC circuit is 50kHz along with a bandwidth of 5kHz, find the quality factor.

a) 5

b) 50

c) 10

d) 500

View Answer

Explanation: We know that Quality factor is equal to the resonant frequency divided by the bandwidth. Substituting the values from the given question, we get Q=10.

9. What happens to the bandwidth frequency range when the quality factor increases?

a) Increases

b) Decreases

c) Remains the same

d) Becomes zero

View Answer

Explanation: The bandwidth frequency range decreases as the Q factor increases because the bandwidth is inversely proportional to the Q factor.

10. Find the bandwidth when the resonant frequency is 50kHz and the Q factor is 10.

a) 5kHz

b) 50kHz

c) 10kHz

d) 500kHz

View Answer

Explanation: We know that Quality factor is equal to the resonant frequency divided by the bandwidth. Substituting the values from the given question, we get BW= 5kHz.

**Sanfoundry Global Education & Learning Series – Basic Electrical Engineering.**

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