This set of Basic Electrical Engineering Multiple Choice Questions & Answers (MCQs) focuses on “Ohm’s Law for a Magnetic Circuit”.

1. Ohm’s law for magnetic circuits is _________

a) F=ϕS

b) F=ϕ/S

c) F=ϕ^{2}S

d) F=ϕ/S^{2}

View Answer

Explanation: Ohm’s law for magnetic circuits states that the MMF is directly proportional to the magnetic flux where reluctance is the constant of proportionality.

2. What happens to the MMF when the magnetic flux decreases?

a) Increases

b) Decreases

c) Remains constant

d) Becomes zero

View Answer

Explanation: Ohm’s law for magnetic circuit’s states that the MMF is directly proportional to the magnetic flux hence as the magnetic flux decreases, the MMF also decreases.

3. Calculate the MMF when the magnetic flux is 5Wb and the reluctance is 3A/Wb.

a) 10At

b) 10N

c) 15N

d) 15At

View Answer

Explanation: We know that:

F=ϕS

Substituting the given values from the question, we get MMF= 15At.

4. A ring having a cross-sectional area of 500 mm^{2}, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the flux density of the ring.

a) 1.6T

b) 2.6T

c) 3.6T

d) 4.6T

View Answer

Explanation: From the given question:

Flux density= 800*10

^{-6}/500*10

^{6}=1.6 Wb/m

^{2}.

5. A ring having a cross-sectional area of 500 mm^{2}, a circumference of and ϕ=800microWb 400 mm has a coil of 200 turns wound around it. Calculate the reluctance.

a) 1.68 * 10^{-4}A/Wb

b) 1.68 * 10^{4} A/Wb

c) 1.68 * 10^{6} A/Wb

d) 1.68 * 10^{-6}A/Wb

View Answer

Explanation: From the given question:

Flux density= 800*10

^{-6}/500*10

^{6}=1.6 Wb/m

^{2}.

Reluctance= 0.4/(380*4*pi*10

^{-7}*10

^{-4}*5)=1.68 * 10

^{6}A/Wb.

6. A ring having a cross-sectional area of 500 mm2, a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetomotive force.

a) 1442At

b) 1342At

c) 1432At

d) 1344At

View Answer

Explanation: We know that:

F=ϕS

Substituting the given values from the question, we get F= 1342At.

7. A ring having a cross-sectional area of 500 mm2 , a circumference of 400 mm and ϕ=800microWb has a coil of 200 turns wound around it. Calculate the magnetising current.

a) 6.7A

b) 7.7A

c) 7.6

d) 6.1A

View Answer

Explanation: We know that:

F=ϕS

Substituting the given values from the question, we get F= 1342At.

The magnetic current is:

I=F/N

Substituting the values from the question, we get I=6.7A.

8. Can we apply Kirchhoff’s was to magnetic circuits?

a) Yes

b) No

c) Depends on the circuit

d) Insufficient information provided

View Answer

Explanation: Magnetic circuits have an equivalent to the potential difference of electric circuits. This is the magnetic potential difference which allows us to apply Kirchhoff’s laws to magnetic circuit analysis.

9. What is MMF?

a) Magnetic Machine Force

b) Magnetomotive Force

c) Magnetic Motion Force

d) Magnetomotion Force

View Answer

Explanation: MMF stands for magnetomotive force. It is the sum of the magnetizing forces along a circuit.

10. The equivalent of the current I in magnetic ohm’s law is?

a) Flux

b) Reluctance

c) MMF

d) Resistance

View Answer

Explanation: The equivalent of current in magnetic ohm’s law is flux as:

V=IR is equivalent to F=ϕS.

**Sanfoundry Global Education & Learning Series – Basic Electrical Engineering.**

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