Network Theory Questions and Answers – Parallel Resonance

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Parallel Resonance”.

1. For the circuit shown below, determine its resonant frequency.
The resonant frequency is 7.12 for the circuit
a) 6.12
b) 7.12
c) 8.12
d) 9.12
View Answer

Answer: b
Explanation: The resonant frequency of the circuit is fr = 1/(2π√LC). Given L = 5H and C = 100uf. On substituting the given values in the equation we get resonant frequency = 1/(2π√(5×100×10-6)) = 7.12 Hz.

2. Find the quality factor of the following circuit.
The resonant frequency is 7.12 for the circuit
a) 2.24
b) 3.34
c) 4.44
d) 5.54
View Answer

Answer: a
Explanation: The quality factor of the circuit is Q = XL/R = 2πfrL/R. Given f = 7.12 Hz and L = 5H and R = 100. On substituting the given values in the equation we get the quality factor = (6.28×7.12×5)/100 = 2.24.

3. Find the bandwidth of the circuit shown below.
The resonant frequency is 7.12 for the circuit
a) 1
b) 2
c) 3
d) 4
View Answer

Answer: c
Explanation: The bandwidth of the circuit is BW = fr/Q. we obtained fr = 7.12 Hz and Q = 2.24. On substituting the given values in the equation we get the bandwidth = 7.12/2.24 = 3.178Hz.
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4. The magnification in resonance considering the voltage across inductor is?
a) V/VL
b) VL/V
c) V x VL
d) VL
View Answer

Answer: b
Explanation: The ratio of voltage across inductor to the voltage applied at resonance can be defined as magnification. The magnification in resonance considering the voltage across inductor is Q = VL/V.

5. Considering the voltage across the capacitor, the magnification in resonance is?
a) VC
b) V x VC
c) VC/V
d) V/VC
View Answer

Answer: c
Explanation: The ratio of voltage across capacitor to the voltage applied at resonance can be defined as magnification. Considering the voltage across the capacitor, the magnification in resonance is Q = VC/V.
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6. The value of ωr in parallel resonant circuit is?
a) 1/(2√LC)
b) 1/√LC
c) 1/(π√LC)
d) 1/(2π√LC)
View Answer

Answer: b
Explanation: Basically parallel resonance occurs when XL = XL. The frequency at which the resonance occurs is called the resonant frequency. The value of ωr in parallel resonant circuit is ωr = 1/√LC.

7. The expression of resonant frequency for parallel resonant circuit is?
a) 1/(2π√LC)
b) 1/(π√LC)
c) 1/(2√LC)
d) 1/√LC
View Answer

Answer: a
Explanation: The condition for resonance occurs when XL = XL. The expression of resonant frequency for parallel resonant circuit is fr = 1/(2π√LC).

8. Find the resonant frequency in the ideal parallel LC circuit shown in the figure.
Find the resonant frequency in the ideal parallel LC circuit shown
a) 7.118
b) 71.18
c) 711.8
d) 7118
View Answer

Answer: d
Explanation: The expression for resonant frequency is fr = 1/(2π√LC). Given L = 50mH and C = 0.01uF. On substituting the given values in the equation we get the resonant frequency = 1/(2π√(50×10-3)×0.01×10-6))=7117.6 Hz.

9. If the value of Q of the circuit is high, then its effect on bandwidth is?
a) large bandwidth
b) small bandwidth
c) no effect on bandwidth
d) first increases and then decreases
View Answer

Answer: b
Explanation: If the value of Q of the circuit is high, then small bandwidth because bandwidth is inversely proportional to the quality factor.
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10. If in a circuit, if Q value is decreased then it will cause?
a) small bandwidth
b) no effect on bandwidth
c) first increases and then decreases
d) large bandwidth
View Answer

Answer: d
Explanation: If in a circuit, if the Q value is decreased then bandwidth increases and the bandwidth do not decrease.

Sanfoundry Global Education & Learning Series – Network Theory.

To practice all areas of Network Theory, here is complete set of 1000+ Multiple Choice Questions and Answers.

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