This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Norton’s Theorem”.

1. Find the current flowing between terminals A and B of the circuit shown below.

a) 1

b) 2

c) 3

d) 4

View Answer

Explanation: The magnitude of the current in the Norton’s equivalent circuit is equal to the current passing through the short circuited terminals that is I=20/5=4A.

2. Find the equivalent resistance between terminals A and B of the circuit shown below.

a) 0.33

b) 3.33

c) 33.3

d) 333

View Answer

Explanation: Norton’s resistance is equal to the parallel combination of both the 5Ω and 10Ω resistors that is R = (5×10)/15 = 3.33Ω.

3. Find the current through 6Ω resistor in the circuit shown above.

a) 1

b) 1.43

c) 2

d) 2.43

View Answer

Explanation: The current passing through the 6Ω resistor and the voltage across it due to Norton’s equivalent circuit is I = 4×3.33/(6+3.33) = 1.43A.

4. Find the voltage drop across 6Ω resistor in the circuit shown above.

a) 6.58

b) 7.58

c) 8.58

d) 9.58

View Answer

Explanation: The voltage across the 6Ω resistor is V = 1.43×6 = 8.58V. So the current and voltage have same values both in the original circuit and Norton’s equivalent circuit.

5. Find the current flowing between terminals A and B.

a) 1

b) 2

c) 3

d) 4

View Answer

Explanation: Short circuiting terminals A and B, 20-10(I

_{1})=0, I

_{1}=2A. 10-5(I

_{2}), I

_{2}=2A. Current flowing through terminals A and B= 2+2 = 4A.

6. Find the equivalent resistance between terminals A and B

a) 3

b) 3.03

c) 3.33

d) 3.63

View Answer

Explanation: The resistance at terminals AB is the parallel combination of the 10Ω resistor and the 5Ω resistor => R = ((10×5))/(10+5) = 3.33Ω.

7. Find the current flowing between terminals A and B obtained in the equivalent Nortan’s circuit.

a) 8

b) 9

c) 10

d) 11

View Answer

Explanation: To solve for Norton’s current we have to find the current passing through the terminals A and B. Short circuiting the terminals a and b, I=100/((6×10)/(6+10)+(15×8)/(15+8))=11.16 ≅ 11A.

8. Find the equivalent resistance between terminals A and B obtained in the equivalent Nortan’s circuit.

a) 8

b) 9

c) 10

d) 11

View Answer

Explanation: The resistance at terminals AB is the parallel combination of the 10Ω resistor and the 6Ω resistor and parallel combination of the 15Ω resistor and the 8Ω resistor => R=(10×6)/(10+6)+(15×8)/(15+8)=8.96≅9Ω.

9. Find the current through 5Ω resistor in the circuit shown above.

a) 7

b) 8

c) 9

d) 10

View Answer

Explanation: To solve for Norton’s current we have to find the current passing through the terminals A and B. Short circuiting the terminals a and b I=11.16×8.96/(5+8.96) = 7.16A.

10. Find the voltage drop across 5Ω resistor in the circuit shown above.

a) 33

b) 34

c) 35

d) 36

View Answer

Explanation: The voltage drop across 5Ω resistor in the circuit is the product of current and resistance => V = 5×7.16 = 35.8 ≅ 36V.

**Sanfoundry Global Education & Learning Series – Network Theory.**

To practice all areas of Network Theory, __here is complete set of 1000+ Multiple Choice Questions and Answers__.