This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Image Parameters”.

1. A network is said to be symmetrical if the relation between A and D is?

a) A = D

b) A = 2 D

c) A = 3 D

d) A = 4 D

View Answer

Explanation: We know V

_{1}=AV

_{2}-BI

_{2}and I

_{1}=CV

_{2}-DI

_{2}. If the network is symmetrical, then the relation between A and D is A = D.

2. The relation between Z_{11} and Z_{12} if the network is symmetrical is?

a) Z_{11} = 2 Z_{12}

b) Z_{11} = Z_{12}

c) Z_{11} = 3 Z_{12}

d) Z_{11} = 4 Z_{12}

View Answer

Explanation: For a network to be symmetrical A=D. So the relation between Z

_{11}and Z

_{12}for the network is symmetrical is Z

_{11}= Z

_{12}.

3. The relation between Z_{12} and Z_{11} and B and C parameters if the network is symmetrical is?

a) Z_{11} = Z_{12} = B/C

b) Z_{11} = Z_{12} = C/B

c) Z_{11} = Z_{12} =√(B/C)

d) Z_{11} = Z_{12} = √(C/B)

View Answer

Explanation: For symmetrical network, A=D. On substituting this we get the relation between Z

_{12}and Z

_{11}and B and C parameters if the network is symmetrical is

Z

_{11}= Z

_{12}=√(B/C).

4. Determine the transmission parameter A in the circuit shown below.

a) 3/4

b) 4/3

c) 5/6

d) 6/5

View Answer

Explanation: We know V

_{1}=AV

_{2}-BI

_{2}and I

_{1}=CV

_{2}-DI

_{2}. A=(V

_{1}/V

_{2}) |I

_{2}=0. On solving we get the transmission parameter A as A = 6/5.

5. Determine the transmission parameter B in the circuit shown in question 4.

a) 17/5

b) 5/17

c) 13/5

d) 5/13

View Answer

Explanation: The transmission parameter B is -V

_{1}/I

_{2}|V

_{2}=0. On short cicuiting the port 2, from the circuit we get -I

_{2}= (5/17)V

_{1}=> -V

_{1}/I

_{2}= 17/5. On substituting we get B = 17/5.

6. Determine the transmission parameter C in the circuit shown in question 4.

a) 2/5

b) 1/5

c) 4/5

d) 3/5

View Answer

Explanation: The transmission parameter C is I

_{1}/V

_{2}|I

_{2}=0. This parameter is obtained by open circuiting the port 2. So we get V

_{2}= 5I

_{1}=> I

_{1}/V

_{2}= 1/5. On substituting, we get C = 1/5.

7. Determine the transmission parameter D in the circuit shown in question 4.

a) 3/5

b) 4/5

c) 7/5

d) 2/5

View Answer

Explanation: The transmission parameter D is -I

_{1}/I

_{2}|V

_{2}=0. This is obtained by short circuiting the port 2. We get I

_{1}= (7/17)V

_{1}and -I

_{2}= (5/17)V

_{1}. On solving, we get -I

_{1}/I

_{2}= 7/5. On substituting we get D = 7/5.

8. The value of Z_{11} in the circuit shown in question 4 is?

a) 1.8

b) 2.8

c) 3.8

d) 4.8

View Answer

Explanation: The relation between Z

_{11}and ABCD parameters is Z

_{11}=√(AB/CD). We know A = 6/5, B = 17/5, C = 1/5, D = 7/5. On substituting, Z

_{11}= √((6/5×17/5)/(1/5×7/5))=3.8Ω.

9. The value of Z_{12} in the circuit shown in question 4 is?

a) 1.1

b) 2.2

c) 3.3

d) 4.4

View Answer

Explanation: The relation between Z

_{12}and ABCD parameters is Z

_{12}=√(BD/AC). We got B = 17/5, D = 7/5, A = 6/5, C = 1/5. On substituting Z

_{12}=√(BD/AC) = √((17/5×7/5)/(6/5×1/5))=4.4Ω.

10. Determine the value of Ø in the circuit shown in question 4.

a) 0.25

b) 0.5

c) 0.75

d) 1

View Answer

Explanation: Ø is called image transfer constant and it is also used to describe reciprocal networks and this parameter is obtained from the voltage and current ratios. We know Ø= tanh

^{-1}√(BC/AD) = tanh

^{-1}√(17/42)=0.75.

**Sanfoundry Global Education & Learning Series – Network Theory.**

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