# Network Theory Questions and Answers – Transmission(ABCD) Parameters

This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Transmission(ABCD) Parameters”.

1.In the circuit shown below, find the transmission parameter A.

a) 6/5
b) 5/6
c) 3/4
d) 4/3

Explanation: Open circuiting b-b, V1 = 6 I1, V2 = 5I1. On solving V1/V2 = 6/5. On substituting we get A = V1/V2=6/5.

2. In the circuit shown below, find the transmission parameter C.

a) 4/5
b) 3/5
c) 2/5
d) 1/5

Explanation: C = I1/V2|I2=0. By open circuiting b-b we get V2 = 5 I1 => I1/V2 = 1/5. On substituting we get C = I1/V2=1/5 Ω.

3. In the circuit shown below, find the transmission parameter B.

a) 15/5
b) 17/5
c) 19/5
d) 21/5

Explanation: The transmission parameter B is given by B = -V1/I2|V2=0. Short circuiting b-b, -I2 = 5/17 V1 => -V1/I2 = 17/5. On substituting we get B=17/5 Ω.

4. In the circuit shown below, find the transmission parameter D.

a) 1/5
b) 3/5
c) 7/5
d) 9/5

Explanation: D is a transmission parameter and is given by D = -I1/I2 |V2=0. Short circuiting b-b, I1 = 7/17 V1 and-I2 = 5/17 V1. So we get I1/I2 = 7/5. So D=7/5.

5. The hybrid parameter h11 is called?
a) short circuit input impedance
b) short circuit forward current gain
c) open circuit reverse voltage gain

Explanation: h11=V1/I1 |V2=0. So the hybrid parameter h11 is called short circuit input impedance.
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6. The hybrid parameter h21 is called?
b) open circuit reverse voltage gain
c) short circuit forward current gain
d) short circuit input impedance

Explanation: h21=I2/I1 |V2=0. So the hybrid parameter h21 is called short circuit forward current gain.

7. In the circuit shown below, find the h-parameter h11.

a) 1
b) 2
c) 3
d) 4

Explanation: h11=V1/I1 |V2=0. So short circuiting b-b, V1 = I1((2||2)+1) = 2I1 => V1/I1 = 2. On substituting we get h11 = V1/I1 = 2Ω.

8. In the circuit shown below, find the h-parameter h21.

a) 1
b) -1
c) 1/2
d) -1/2

Explanation: Short circuiting b-b, h21 = I2/I1 when V2=0 and -I2 = I1/2 => I2/I1 = -1/2. So h21 = -1/2.

9. In the circuit shown below, find the h-parameter h12.

a) 1/2
b) -1/2
c) 1
d) -1

Explanation: Open circuiting a-a we get V1=Iy×2 and
Iy=I2/2 and V2=Ix×4 and Ix=I2/2. On solving and substituting, we get h12 = V1/V2=1/2.

10. In the circuit shown below, find the h-parameter h22.

a) 1
b) 2
c) 1/2
d) 3/2

Explanation: Open circuiting a-a we get V1=Iy×2 and Iy=I2/2 and V2=Ix×4 and Ix=I2/2. On solving and substituting, we get h22 =I2/V2=1/2 Ω.

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