This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Supermesh Analysis”.
1. Consider the circuit shown below. Find the current I1 (A).
a) 1
b) 1.33
c) 1.66
d) 2
View Answer
Explanation: Applying Super mesh analysis, the equations will be I2-I1=2 -10+2I1+I2+4=0. On solving the above equations, I1=1.33A.
2. Consider the circuit shown below. Find the current I2 (A).
a) 1.33
b) 2.33
c) 3.33
d) 4.33
View Answer
Explanation: Applying Super mesh analysis, the equations will be I2-I1=2
-10+2I1+I2+4=0. On solving the above equations, I2=3.33A.
3.Consider the circuit shown below. Find the current I1 (A).
a) -1
b) -2
c) -3
d) -4
View Answer
Explanation: Applying Super mesh analysis, the equations will be I1+I1+10+I2+I2=0. I1+I2=-5. I2-I1=1. On solving, I1=-3A.
4. Consider the circuit shown below. Find the current I2 (A).
a) -2
b) -1
c) 2
d) 1
View Answer
Explanation: Applying Super mesh analysis, the equations will be I1+I1+10+I2+I2=0. I1+I2=-5. I2-I1=1. On solving, I2=-2A.
5. Find the power (W) supplied by the voltage source in the following figure.
a) 0
b) 1
c) 2
d) 3
View Answer
Explanation: I3-I2=2. As I2=-2A, I3=0A. Th term power is the product of voltage and current. So, power supplied by source = 10×0=0W.
6. Find the current i1 in the circuit shown below.
a) 8
b) 9
c) 10
d) 11
View Answer
Explanation: The current in the first loop is equal to 10A. So the current i1 in the circuit is i1 = 10A.
7. Find the current i2 in the circuit shown below.
a) 6.27
b) 7.27
c) 8.27
d) 9.27
View Answer
Explanation: For 2nd loop, 10 + 2(i2-i3) + 3(i2-i1) = 0. For 3rd loop, i3 + 2(i3-i2)=10. As i1=10A, On solving above equations, we get i2=7.27A.
8. Find the current i3 in the circuit shown below.
a) 8.18
b) 9.18
c) 10.18
d) 8.8
View Answer
Explanation: For 2nd loop, 10 + 2(i2-i3) + 3(i2-i1) = 0. For 3rd loop, i3 + 2(i3-i2)=10. As i1=10A, On solving above equations, we get i3=8.18A.
9. Find the current I1 in the circuit shown below.
a) 8
b) -8
c) 9
d) -9
View Answer
Explanation: Applying Super Mesh analysis, (10+5)I1 – 10(I2) – 5(I3) = 50. 2(I2) + I3 + 5(I3-I1) + 10(I2-I1) = 0. I2 – I3 = 2. On solving above equations, we get I1=-8A.
10. Find the current I2 in the circuit shown below.
a) 5.3
b) -5.3
c) 7.3
d) -7.3
View Answer
Explanation: Applying Super Mesh analysis, (10+5)I1-10(I2)-5(I3) = 50. 2(I2) + I3 + 5(I3-I1) + 10(I2-I1) = 0. I2 – I3 = 2. On solving above equations, we get I2=-7.3A.
Sanfoundry Global Education & Learning Series – Network Theory.
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