This set of Network Theory Multiple Choice Questions & Answers (MCQs) focuses on “Series Equalizer”.

1. The value of attenuation D is equal to?

a) log_{10} (N)

b) 10 log_{10} (N)

c) 20 log_{10} (N)

d) 40 log_{10} (N)

View Answer

Explanation: The value of attenuation D is equal to log

_{10}(N). Attenuation D = log

_{10}(N) where N is input to output power ratio of the load.

2. The value of N in terms of attenuation D is?

a) antilog(D)

b) antilog(D/10)

c) antilog(D/20)

d) antilog(D/40)

View Answer

Explanation: The value of N in terms of attenuation D is antilog(D/10). N = antilog(D/10) where D is attenuation in decibels.

3. The input to output power ratio of the load (N) is the ratio of the________ to the __________

a) Maximum power delivered to the load when the equalizer is not present, power delivered to the load when equalizer is present

b) Power delivered to the load when equalizer is present, maximum power delivered to the load when the equalizer is not present

c) Maximum power delivered to the load when the equalizer is present, power delivered to the load when equalizer is not present

d) Power delivered to the load when equalizer is not present, maximum power delivered to the load when the equalizer is present

View Answer

Explanation: The input to output power ratio of the load (N) is the ratio of the maximum power delivered to the load when the equalizer is not present to the power delivered to the load when equalizer is present.

4. The N is defined as?

a) output power/ input power

b) input power/ output power

c) output power at inductor/ input power

d) output power at capacitor/ input power

View Answer

Explanation: The N is defined as the ratio of input power to the output power. N =P

_{i}/P

_{l}where P

_{i}is input power and P

_{l}is output power.

5. The expression of input power of a series equalizer is?

a) V_{max}^{2}/R_{o}

b) V_{max}^{2}/2R_{o}

c) V_{max}^{2}/3R_{o}

d) V_{max}^{2}/4R_{o}

View Answer

Explanation: The expression of input power of a series equalizer is P

_{i}=(V

_{max}/2R

_{o})

^{2}R

_{o}=V

_{max}

^{2}/4R

_{o}.

6. The expression of current flowing in a series equalizer is?

a) V_{max}/√((R_{o})^{2}+(X_{1})^{2})

b) V_{max}/√((2R_{o})^{2}+(X_{1})^{2} )

c) V_{max}/√((2R_{o})^{2}+(2X_{1})^{2} )

d) V_{max}/√((R_{o})^{2}+(2X_{1})^{2} )

View Answer

Explanation: When the equalizer is connected, the expression of current flowing in a series equalizer is I

_{1}= V

_{max}/√((2R

_{o})

^{2}+(2X

_{1})

^{2}) where V

_{max}is voltage applied to the network and R

_{o}is resistance of the load as well as source and 2X

_{1}is the reactance of the equalizer.

7. What is the power at the load of a series equalizer?

a) [ V_{max}^{2}/(R_{o}^{2}+X_{1}^{2} )]R_{o}

b) [ V_{max}^{2}/(2(R_{o}^{2}+X_{1}^{2}))]R_{o}

c) [ V_{max}^{2}/(3(R_{o}^{2}+X_{1}^{2}))]R_{o}

d) [ V_{max}^{2}/(4(R_{o}^{2}+X_{1}^{2}))]R_{o}

View Answer

Explanation: The power at the load of a series equalizer is P=(V

_{max}/√((2R

_{o})

^{2}+(2X

_{1})

^{2}))

^{2}R

_{o}=[V

_{max}

^{2}/(4(R

_{o}

^{2}+X

_{1}

^{2}))]R

_{o}.

8. Determine the value of N in the series equalizer.

a) 1+ X_{1}^{2}/R_{o}^{2}

b) X_{1}^{2}/R_{o}^{2}

c) 1+ R_{o}^{2}/X_{1}^{2}

d) R_{o}^{2}/X_{1}^{2}

View Answer

Explanation: The N is defined as the ratio of input power to the output power.

N=P

_{i}/P

_{l}=(V

_{max}

^{2}/4R

_{o})/[V

_{max}

^{2}/(4(R

_{o}

^{2}+X

_{1}

^{2}))]R

_{o}=1+X

_{1}

^{2}/R

_{o}

^{2}.

9. The expression of N in a full series equalizer considering Z_{1} as inductor and Z_{2} as capacitor is?

a) R_{o}^{2}/(ωL_{1})^{2}

b) 1+ R_{o}^{2}/(ωL_{1})^{2}

c) (ω^{2} L_{1}^{2})/R_{o}^{2}

d) 1+ (ω^{2} L_{1}^{2})/R_{o}^{2}

View Answer

Explanation: The expression of N in a full series equalizer considering Z

_{1}as inductor and Z

_{2}as capacitor is N = 1 + X

_{1}

^{2}/R

_{o}

^{2}= 1+ (ω

^{2}L

_{1}

^{2})/R

_{o}

^{2}.

10. The expression of N in a full series equalizer considering Z_{1} as capacitor and Z_{2} as inductor is?

a) 1+ (ω^{2} L_{1}^{2})/R_{o}^{2}

b) (ω^{2} L_{1}^{2})/R_{o}^{2}

c) 1+ R_{o}^{2}/(ωL_{1})^{2}

d) R_{o}^{2}/(ωL_{1})^{2}

View Answer

Explanation: The expression of N in a full series equalizer considering Z

_{1}as capacitor and Z

_{2}as inductor is N = 1+ R

_{o}

^{2}/X

_{2}

^{2}= 1+R

_{o}

^{2}/(ωL

_{1})

^{2}.

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