This set of Aptitude Questions and Answers (MCQs) focuses on “Quadrilaterals – Set 2”.
1. The diagonal of a quadrilateral is 18 cm and the perpendiculars dropped on it from the remaining opposite vertices are 8 cm and 14 cm. What will be the area (in sq. cm) of this quadrilateral?
a) 208
b) 180
c) 198
d) 218
View Answer
Explanation: Given,
d = 18 cm, h1 = 8cm, h2 = 14 cm
Area = (1 / 2) * d * (h1 + h2)
= (1 / 2) * 18 * (8 + 14)
= (1 / 2) * 18 * (22)
= 198 cm2
2. What will be the area of the square shaped field if one of its diagonals is 11 m long?
a) 60.5 m2
b) 66.2 m2
c) 72.6 m2
d) 57.8 m2
View Answer
Explanation: Given,
d = 11m
Area of square = \(\frac {1}{2}\) (d)2
= \(\frac {1}{2}\) * 112
= 60.5 m2
3. What is the area (in sq. m) of a rhomboid field whose side is 12 m and altitude is 14 m?
a) 136
b) 168
c) 152
d) 179
View Answer
Explanation: Given,
l = 12 m, d = 14 m
Area of rhombus = length of side * altitude
Area = l * d
= 12m * 14m
= 168 m2
4. If the length of one diagonal of a rhombus is 7 cm, its side is 8 cm and altitude is 10 cm. What will be the value of the other diagonal of this rhombus in cm?
a) 11.42
b) 12.45
c) 10.56
d) 11.89
View Answer
Explanation: Given,
l = 8 cm, h = 10 cm, d1 = 7 cm, d2 = x cm
Area of rhombus = I * h = d1 * d2
➩ 8 * 10 = 7 * x
➩ 80 = 7 * x
➩ 80 / 7 = x
➩ x = 11.42 cm
5. What will be the area of a trapezoid field having altitude 12 m and the length of opposite parallel sides as 8 m and 10 m?
a) 133 m2
b) 120 m2
c) 108 m2
d) 90 m2
View Answer
Explanation: Given,
h = 12 m, a = 8 m, b = 10 m
Area of trapezium = (1 / 2) * (a + b) * h
= (1 / 2) * (8 + 10) * 12
= (1 / 2) * (18) * 12
= 108 m2
6. A kite is having smaller diagonal as 7 cm and longer diagonal as 11 cm. Which of the following options represents the correct value of the area of this kite?
a) 35.4 cm2
b) 29.5 cm2
c) 27.5 cm2
d) 38.5 cm2
View Answer
Explanation: Given,
p = 11 cm, q = 7 cm
Area of kite = (p * q) / 2
Area = (11 * 7) / 2
= 77 / 2
= 38.5 cm2
7. If the sides of a square are reduced to half, then, the new area is how times the original area of this square?
a) 1 / 4
b) 1 / 2
c) 2
d) 4
View Answer
Explanation: Let the original side = x
Original area = x2
New side = x / 2
New area = (x / 2)2
= x2 / 4
Thus, on comparing new area is \(\frac {1}{4}\) of original area.
8. A square field is having side as 10 m long. This field can be divided into how many small square portions each having side as 0.5 m?
a) 600
b) 500
c) 400
d) 300
View Answer
Explanation: Given,
A = 10 m, a = 0.5 m
Area of bigger field = A * A
= 10 * 10
= 100 m2
Area of each small portion = a * a
= 0.5 * 0.5 = 0.25 m2
Number of small portions possible = 100 / 0.25 = 400.
9. If the height of a trapezium is 17 cm and the sum of its parallel sides is 21 cm, then, what will be the area (in sq. cm) of the trapezium?
a) 140.6
b) 178.5
c) 168.3
d) 192.4
View Answer
Explanation: Given,
H = 17 cm, a + b = 21 cm
Area of trapezium = (1 / 2) * h * (a + b)
= (1 / 2) * 17 * 21
= 178.5 cm2
10. The length of the diagonal of a rectangle is 5 cm and the length is 4 cm, then, what will be the area (in sq. cm) of this rectangle?
a) 12
b) 14
c) 18
d) 15
View Answer
Explanation: Given,
d = 5 cm, l = 4 cm
Area of rectangle = l * (d2 – l2)1/2
= 4 * (52 – 42)1/2
= 4 * (25 – 16)1/2
= 4 * (9)1/2
= 4 * 3
= 12 cm2
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