This set of Aptitude Questions and Answers (MCQs) focuses on “Three People”.
1. The ages of 3 brothers are in a ratio 3:5:11. If the difference between the ages of the youngest and the eldest brother is 24 years, find the total of their ages.
a) 49 years
b) 50 years
c) 51 years
d) 52 years
View Answer
Explanation: Let their ages be in relation to a constant term x.
The ages of the brother = 3x, 5x and 11x respectively.
The difference between the ages of the youngest and the eldest brother = 11x – 3x = 8x
The difference = 24 years (given)
8x = 24 years
X = 24 / 8 = 3 years
The sum of their ages = 3x + 5x + 11x = 19x
19x = 19 * 3 = 51 years
2. The ages of 3 employees of a company are in a ratio 1 / 2 : 2 / 8 : 3 / 4. If the total of their ages is 120, find their individual ages in ascending order.
a) 40, 20, 60
b) 20, 30, 70
c) 30, 40, 50
d) 20, 40, 60
View Answer
Explanation: The ratio of the ages of employees = 1 / 2 : 2 / 8 : 3 / 4.
Multiplying each ratio by 8:
1 / 2 * 8 : 2 / 8 * 8 : 3 / 4 * 8
4 : 2 : 6
Using a constant x in terms of the ratio = 4x, 2x and 6x
4x + 2x + 6x = 12x
12x = 120 given
X = 10
4x = 40, 2x = 20 and 6x = 60
Their ages are 40, 20, 60
Their ages in ascending order = 20, 40, 60
3. The ages of 3 people are x, y and z. It is known that 20% of x is equal to 40% of y and 50% of z. If the total of their ages is 190, find the age of the youngest person.
a) 30
b) 40
c) 50
d) 35
View Answer
Explanation: 20% of x = 40% of y = 50% of z
20 * x / 100 = 40 * y / 100 = 50 * z / 100
x / 5 = 2y / 5 = z / 2
Multiplying all sides by \(\frac {1}{2}\)
x / 10 = 2y / 10 = z / 4
x / 10 = y / 5 = z / 4
The ratio of their ages = 10 : 5 : 4
The sum of their ages = 190 (given)
Assuming a constant r.
10r + 5r + 4r = 190
19r = 190
R = 10
Minimum age of them = 4r = 4 * 10 = 40
4. There are 3 members in a family. What can be the age of the eldest person if the age of three members is in ap with a common difference of 18 months. It is known that the sum of their ages is 58 years 6 months.
a) 18 years
b) 19 years
c) 21 years
d) 22 years
View Answer
Explanation: Let the age of the youngest person be x.
The age of the 3 members will be x, x + 1.5 and x + 3 years
Total of their ages = x + x + x + 1.5 + 3 years = 3x + 4.5 years
3x + 4.5 years = 58.5 years
3x = 58.5 – 4.5 = 54 years
X = 54 / 3 = 18 years
The age of the eldest person = 18 + 3 = 21 years.
5. Ages of 3 individuals are in a ratio 3 : 1.5 : 4 / 3. If the sum of their ages is 70 years, find their individual ages.
a) 36, 17, 17
b) 17, 19, 34
c) 20, 25, 25
d) 36, 18, 16
View Answer
Explanation: The ratio of their ages = 3 : 1.5 : 4 / 3
Multiplying all sides by 3 and 2 simultaneously.
3 * 2 * 3 : 1.5 * 2 * 3 : 4 / 3 * 2 * 3
18: 9: 8
Taking a constant x, expressing all the terms in relation to x.
18x, 9x, 8x
The total of their ages = 70 (given)
18x + 9x + 8x = 70
35x = 70
X = 2
Their respective days = 18x = 18 * 2, 9x = 9 * 2, 8x = 8 * 2
36, 18, 16 years.
6. There are 3 members in a family with ages in a ratio 3 : 4 : 5. If the difference between the ages of the eldest and the youngest is 14 years, find the age of the middle child after 25 years.
a) 28 years
b) 55 years
c) 53 years
d) 49 years
View Answer
Explanation: The ratio = 3 : 4 : 5
Using a constant x and representing their age in terms of x.
3x, 4x, 5x
The difference between the ages of the youngest and the eldest child = 14 years
5x – 3x = 2x = 14 years
2x = 14 years, x = 14 / 2 = 7 years
Present age of the middle child = 4x = 4 * 7 = 28 years
Age after 25 years = 28 + 25 = 53 years.
7. There are 5 members in a family. If their ages are in a series with equal gaps, find the age of the eldest person. It is known that the sum of their ages is 120 years, and no one is younger than 20 years and older than 30 years.
a) 26 years
b) 27 years
c) 28 years
d) 30 years
View Answer
Explanation: The only possible AP where minimum value is 20 and maximum value is 28 with 5 terms and a common difference 2 is, 20, 22, 24, 26 and 28. Thus, the age of the eldest person is 28 years.
8. There are 3 members in a family named a, b and c. A is twice as old as b, b is thrice as old as c. If the difference between the ages of a and c is 40 years, find the age of the youngest member after 11 years.
a) 16 years
b) 17 years
c) 18 years
d) 19 years
View Answer
Explanation: The youngest among them is c (as per the question)
Age of a, b and c are in a ratio 6 : 3 : 1 as a = 2b and b = 3c
Taking a constant x and expressing the ratio in terms of x, 6x, 3x, x.
The difference between the eldest and the youngest is 40 year.
6x – x = 40 years
5x = 40, x = 8 years
Age of the youngest member c is x = 8 years
Age of c after 11 years = 8 + 11 = 19 years
9. In an office there are 3 employees in a department named a, b and c. a is 120% of b and b is 50% of c. If they all started working at an age of 20 years, find the experience of a. It is known the total of their ages is 92 years.
a) 10 years
b) 12 years
c) 15 years
d) 20 years
View Answer
Explanation: Let the age of a, b and c be x, y and z.
B = 50% of c = 0.5c
A = 120% of b = 120 * 0.5c / 100 = 0.8c
X + y + z = 92 (given)
0.5c + 0.8c + c = 92
2.3c = 92
C = 40 years
A = 0.8 c = 32
It is known that all of them started working at an age of 20 years.
Experience of a = 32 – 20 = 12 years.
10. Out of 3 students a, b and c, a is 18 years old if the ages of the b and c are in a ratio 2 : 3 and the ratio of age of a and b is 6 : 5, find the average age of all the 3 students.
a) 16.5 years
b) 17.5 years
c) 18.5 years
d) 19.5 years
View Answer
Explanation: The ratio of ages of a and b is 6 : 5.
The ratio of ages of b and c is 2 : 3.
The age of a is 18 (given).
Age of b = 18 / 6 * 5 = 15 years
Age of c = 15 / 2 * 3 = 22.5 years
The total of their ages = 15 + 18 + 22.5 = 55.5 years
Average of their age = 55.5 / 3 = 18.5 years.
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