This set of Aptitude Questions and Answers (MCQs) focuses on “Simplification Word Problems”. These questions are beneficial for various competitive exams, placement interviews, and entrance tests.
1. The cost of 5 bags and 3 boxes is Rs.520 and the cost of 4 bags and 3 boxes is Rs.440. What is the value of one bag?
a) Rs.80
b) Rs.75
c) Rs.85
d) Rs.70
View Answer
Explanation: Let the cost of one bag and one box be Rs. x and Rs. y respectively.
Given, 5x + 3y = 520 …… (i)
and 4x + 3y = 440 …… (ii)
Subtracting (ii) from (i), we get, x = 80.
Hence, the cost of one bag is Rs.80.
2. A board 8 ft. 8 inches long is divided into 4 equal parts. What is the length of each part?
a) 32 inches
b) 26 inches
c) 24 inches
d) 28 inches
View Answer
Explanation: We know that 1 ft = 12 inches.
Given, 8 ft. 8 inches = (8*12 + 8) inches = 104 inches.
4 equal parts = 104/4 = 26 inches.
Hence, the length of each part is 26 inches.
3. Sham went to a shop to buy 40 kg of rice. He buys two varieties of rice which cost him Rs.12 and Rs.15 per kg. He spends a total of Rs.552. What was the quantity of rice bought which cost him Rs.15 per kg?
a) 12
b) 16
c) 24
d) 28
View Answer
Explanation: Let the quantity of rice bought at Rs.15 per kg be x kg, then the quantity of rice bought at Rs.12 per kg will be (40-x) kg.
By data, 15x + 12(40-x) = 552 🡪 x = 24.
Hence, the quantity of rice bought at Rs.15 per kg is 24 kg.
4. A girl was asked to multiply a certain number by 63, but she multiplied it by 36 and got her answer less than the correct answer by 1215. Find the number to be multiplied.
a) 52
b) 42
c) 48
d) 45
View Answer
Explanation: Let the required number be x.
By data, 63x – 36x = 1215 🡪 x = 45.
Hence, the number to be multiplied is 45.
5. A man owns 1/3 of the market research bureau business and sells 1/2 of his shares for Rs.55000. What is the value of business?
a) Rs.330000
b) Rs.300000
c) Rs.270000
d) Rs.320000
View Answer
Explanation: Let the total value of business be Rs.x.
Then, \(\frac{1}{3} \, of \, \frac{1}{2}\) of x=55000 🡪 \(\frac{1}{3}*\frac{1}{2}\)*x=55000 🡪 x = Rs.330000.
6. A man spends 2/7th of his salary on house rent, 5/12th of his salary on food and 1/6th of his salary on conveyance. If he has Rs.2200 left with him. Find his expenditure on food.
a) Rs.7500
b) Rs.7000
c) Rs.6500
d) Rs.6800
View Answer
Explanation: Let the monthly salary be Rs.x.
Part of the salary left = x-\(\Big(\frac{2}{7}-\frac{5}{12}-\frac{1}{6}\Big)x=\frac{11x}{84}\).
Then, \(\frac{11x}{84}\)=2200 🡪 x = 16800.
Hence, expenditure on food = \(\frac{5}{12}\)*16800=Rs.7000.
7. A fourth of Ajay’s marks in Mathematics exceeds a fourth of his marks in English by 10. If he got 280 marks in the two subjects together, how many marks he got in mathematics?
a) 120
b) 150
c) 160
d) 180
View Answer
Explanation: Let Ajay’s marks in mathematics and English be x and y respectively.
Then, \(\frac{1}{4}\) x – \(\frac{1}{4}\)y=10 🡪 x-y=40 …… (i)
x+y=280…… (ii)
Solving (i) and (ii), we get, x = 160 and y = 120.
Therefore, Ajay’s marks in mathematics is 160.
8. If 1/8th of a pencil is black, 1/4th of the remaining is white and the remaining 5.25 cm is grey, find the total length of the pencil.
a) 6 cm
b) 12 cm
c) 10 cm
d) 8 cm
View Answer
Explanation: Let the total length of the pencil be x cm.
Black part = (x/8) cm. Remaining part = (x – x/8) = (7x/8) cm.
White part = \(\frac{1}{4}*\frac{7x}{8}=\frac{7x}{32}\) cm. Remaining part = \(\frac{7x}{8}-\frac{7x}{32}=\frac{21x}{32}\)cm.
\(\frac{21x}{32}\)=5.25 🡪 x = 8 cm
Hence, the total length of the pencil is 8 cm.
9. A tin of oil was 3/5 full. When 5 bottles of oil were taken out and 2 bottles of oil were poured into it, it was 1/2 full. How many bottles of oil can the tin contain?
a) 30
b) 35
c) 40
d) 25
View Answer
Explanation: Let x bottles can fill the tin completely.
Then, \(\frac{3x}{5}-\frac{1x}{2}\)=5-2 🡪 \(\frac{x}{10}\)=3 🡪 x = 30.
Required number of bottles = 30.
10. The cost of 6 rings and 2 bangles is Rs.60000. What is the cost of 3 bangles and 9 rings?
a) Rs.100000
b) Rs.90000
c) Rs.85000
d) Rs.75000
View Answer
Explanation: Given, 6R + 2B = 60000 🡪 \(\frac{3}{2}\) (6R+2B)=\(\frac{3}{2}\)*60000.
9R+3B=90000.
Therefore, the cost of 3 bangles and 9 rings is Rs.90000.
More Aptitude Questions and Answers on Simplification Word Problems:
- Simplification Word Problems Questions (Set 2)
- Simplification Word Problems Questions (Set 3)
- Simplification Word Problems Questions (Set 4)
To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.
