This set of Aptitude Questions and Answers (MCQs) focuses on “Odd Days”.

1. How many odd days are there in the month of July?

a) 3

b) 2

c) 1

d) 0

View Answer

Explanation: The month July has 31 days.

Number of odd days can be obtained by dividing the number of days in the respective month by number of days in the week (i.e., 7). The obtained remainder is considered as the number of odd days.

The month July has 31%7 = 3 odd days.

2. Find the number of odd days in 125 years?

a) 1

b) 6

c) 4

d) 2

View Answer

Explanation: 125 years have 31 leap years and 94 ordinary years.

A Leap year will have 2 odd days and an ordinary year will have 1 odd day.

Number of odd days = 31 * 2 + 94 * 1 = 62 + 94 = 156.

156 / 7 remainder = 2

So, the number of odd days in 125 years = 2.

3. Find the number of odd days in the year 2002.

a) 2

b) 0

c) 1

d) 3

View Answer

Explanation: The year 2002 is an ordinary year. It has 365 days.

Ordinary year has 52 weeks + 1 odd day.

The year 2002 has 1 odd day.

4. Find the number of odd days for 5 years i.e., from 2001 to 2005.

a) 5

b) 6

c) 4

d) 3

View Answer

Explanation: The years 2001, 2002, 2003 and 2005 are ordinary years.

Every ordinary year will have one odd day.

The year 2004 is leap year. It has 2 odd days.

So, 1 + 1 + 1 + 2 + 1 = 6 odd days.

5. How many odd days are there in the month of April?

a) 0

b) 3

c) 1

d) 2

View Answer

Explanation: The month April has 30 days.

Number of odd days can be obtained by dividing the number of days in the respective month with number of days in the week (i.e., 7) = 30 / 7 = 2 remainder.

The obtained remainder is the number of odd days.

The month April has 2 odd days.

6. How many odd days are there in 25 years?

a) 1

b) 2

c) 3

d) 0

View Answer

Explanation: 25 years have 6 leap years and 19 ordinary years.

Leap years will have 2 odd days and ordinary years will have 1 odd day.

6 * 2 + 19 * 1 = 31

Remainder of 31 / 7 = 3.

Number of odd days in 25 years = 3.

7. How many odd days does the year 1948 have?

a) 3

b) 1

c) 0

d) 2

View Answer

Explanation: The year 1948 is a leap year. Leap year has 2 odd days.

Here, the number of odd days are as follows:

January has 3 odd days.

February has 2 odd days.

March has 3 odd days.

April has 2 odd days.

May has 3 odd days.

June has 2 odd days.

July has 3 odd days.

August has 3 odd days.

September has 2 odd days.

October has 3 odd days.

November has 2 odd days.

December has 3 odd days.

Total number of odd days = 30.

Remainder = 30 / 7 = 2.

8. Find the number of odd days from 1990 to 2000.

a) 0

b) 2

c) 3

d) 1

View Answer

Explanation: From 1990 to 2000, there are 3 leap years and 7 ordinary years.

The years 1992, 1996 and 2000 are leap years.

The years 1990, 1991, 1993, 1994, 1995, 1997 and 1999 are ordinary years.

A leap year has 2 odd days and an ordinary year has 1 odd day.

So, 3 * 2 + 8 * 1 ⟹ 6 + 8 = 14

Remainder of 14 / 7 = 0.

9. How many odd days are there in 19^{th} century i.e., from 1800 to 1899?

a) 4

b) 6

c) 3

d) 0

View Answer

Explanation: From 1800 to 1899, there are 25 leap years and 75 ordinary years.

Leap year will have 2 odd days.

Ordinary years will have 1 odd day.

25 * 2 + 75 * 1 = 50 + 75 = 125

125 / 7 = 6 odd days.

10. Find the number of odd days of the years 1942 and 1948.

a) 2 and 1

b) 1 and 1

c) 2 and 2

d) 1 and 2

View Answer

Explanation: The year 1942 is an ordinary year.It has 1 odd day.

The year 1948 is a leap year. It has 2 odd days.

So, the year 1942 has 1 odd day and 1948 has 2 odd days.

11. How many odd days are there in the year 1988 and 1989?

a) 3 and 2

b) 1 and 2

c) 2 and 1

d) 0 and 1

View Answer

Explanation: The year 1988 is a leap year. It has 366 days and the year 1989 is an ordinary year. It has 365 days.

Number of odd days can be obtained by dividing the number of days in the respective year by number of days in a week (i.e., 7).

The obtained remainder is the number of odd days – 366%7 the remainder is 2.

365%7 the remainder is 1.

The Year 1988 has 2 odd days and the year 1989 has 1 odd day.

12. Find the number of odd days from 1900 to 1917, excluding the year 1908?

a) 1

b) 0

c) 3

d) 4

View Answer

Explanation: 1900, 1904, 1908, 1912, and 1916 are the leap year.

We have to exclude the year 1908. So, there are 4 leap years and 13 ordinary years.

4 * 2 + 13 * 1 = 21 ⟹ 0 odd days.

13. How many odd days are there in the month of February in 1992 and in May, 1943?

a) 1 and 3

b) 0 and 1

c) 1 and 2

d) 3 and 0

View Answer

Explanation: The year 1992 is a leap year. So, February will have 29 days then, 29%4 = 1 odd day.

May has 31 days so, 31%4 = 3 odd days.

14. Find the number of odd days for 15 years i.e., from 2007 to 2021?

a) 6

b) 3

c) 4

d) 5

View Answer

Explanation: The years 2008, 2012, 2016 and 2020 are leap years. So, every leap year will have 2 odd days.

The years 2007, 2009, 2010, 2011, 2013, 2014, 2015, 2017, 2018, 2019 and 2021 are ordinary years. So, every year will have one odd day.

4 * 2 + 11 * 1 = 8 + 11 = 19 ⟹ 2 weeks + 5odd days.

15. There are 2 odd days in the year 1994.

a) True

b) False

View Answer

Explanation: The answer is False.

The year 1994 is an ordinary year. It will have 365 days.

So, 365%7 = 1 odd day.

16. How many odd days are there in 20^{th} (1901 to 2000) and 21^{st} (2001 to 2020) century?

a) 1 and 1

b) 2 and 3

c) 3 and 5

d) 6 and 4

View Answer

Explanation: There are 25 leap years and 75 ordinary years in 20

^{th}century.

25 * 2 + 75 * 1 = 50 + 75 ⟹ 125 = 17 weeks + 6 odd days.

In 21

^{st}i.e., from 2001 to 2020 there are 5 leap years and 15 ordinary years.

5 * 2 + 15 * 1 = 25 ⟹ 3 weeks + 4 odd days.

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