Logarithms Questions and Answers – Set 3

This set of Aptitude Questions and Answers (MCQs) focuses on “Logarithms – Set 3”.

1. What will be the sum of all the values of w which satisfy 2log7|w+9| = log72401?
a) -58
b) 40
c) -18
d) 18
View Answer

Answer: c
Explanation: Given,
2log7|w+9| = log72401
➩ 2log7|w+9| = log774
➩ 2log7|w+9| = 4
➩ log7|w + 9| = 2
➩ |w + 9| = 72 = 49
➩ w + 9 = 49 or w + 9 = -49
➩ w = 40 or -58
Thus, the required sum is 40 – 58 = -18.

2. Four natural numbers p, q, r, and s are less than 1000 such that logpq = 7 / 5 and logrs = 4 / 3. Now that s – q is given as 497 what will be the value of p + r?
a) 157
b) 165
c) 125
d) 139
View Answer

Answer: a
Explanation: Given,
p, q, r and s are natural numbers less than 1000.
➩ q = p7/5
➩ only possible value of p would be 25.
➩ Thus, q = 27
➩ s = r4/3 and s – q = 497 this gives s = 625.
➩ r = s3/4 this gives r = 125
➩ p + r = 32 + 125 = 157

3. What will be the value of log 0.242424….?
a) -0.9956
b) -0.6154
c) -0.5881
d) -1.3412
View Answer

Answer: b
Explanation: Given,
log 0.242424 ……
➩ log 24 / 99
➩ log ((8 * 3) / (9 * 11))
➩ log ((23 * 3) / (32 * 11))
➩ ((3log2 + log3) / (2log3 + log11))
➩ 3log2 + log3 – 2log3 – log11
➩ (3 * 0.3010) + 0.4771 – (2 * 0.4771) – (1.0413)
➩ 0.9030 – 0.4771 – 1.0413
➩ -0.6154
advertisement
advertisement

4. Which value of a would satisfy the expression log9a + log27√a = (log4911) / (log73)?
a) 113 / 4
b) 73 / 2
c) 39 / 11
d) 527 / 7
View Answer

Answer: a
Explanation: LHS
log9a + log27√a
➩ \(\frac {1}{2}\) log3a + 1 / 6 log3a
➩ (2 / 3) log3a
➩ (2 / 3) (log a / log3)
RHS
(log4911) / (log73)
➩ ((1 / 2 log711) / log73)
➩ (1 / 2) ((log11 / log7) * (log7 / log3))
➩ (1 / 2) (log11 / log3)
On equating LHS and RHS
➩ (2 / 3) (log a / log3) = (1 / 2) (log11 / log3)
➩ (2 / 3) log a = (1 / 2) log 11
➩ a = (3 / 4) log 11
➩ a = 113/4

5. What will be the number of digits in the number 620?
a) 30
b) 32
c) 16
d) 15
View Answer

Answer: c
Explanation: Given,
620
⇒ log (620)
⇒ 20 log 6
⇒ 20 log (3 * 2)
⇒ 20 (log 3 + log 2)
⇒ 20 (0.4771 + 0.3010)
⇒ 20 * 0.7781
⇒ 15.562
Thus, the number of digits would be 15 + 1 = 16.

6. Which of the following values of z would not satisfy (log5z)2 + log5z (5 / z) = 1?
a) 1
b) 5
c) 1 / 25
d) 10
View Answer

Answer: d
Explanation: Given,
(log5z)2 + log5z (5 / z) = 1
➩ (log5z)2 + ((1 – log5z) / (1 + log5z)) = 1
Let log5z = a.
➩ a2 + ((1 – a) / (1 + a)) = 1
➩ a3 + a2 + 1 – a = 1 + a
➩ a3 + a2 – 2a = 0
Thus, a = 0, 1, -2.
log5z = 0, 1, -2
➩ z = 1, 5, 1 / 25
Thus, any value of z apart from 1, 5 and 1 / 25 will not satisfy the given expression.

7. What will be the value of logy441 if the value of logy147 = A and logy63 = B?
a) 2 (A + B) / 3
b) 2A + B / 6
c) A + B / 5
d) A2 + B2 / 3
View Answer

Answer: a
Explanation: Given,
logy441
➩ logy441 = logy (49 * 9)
➩ logy441 = logy49 + logy9
➩ logy441 = 2 logy7 + 2 logy3
➩ let logy7 = Q and logy3 = R
➩ logy441 = 2Q + 2R
Also, logy147 = A and logy63 = B
➩ R + 2Q = A and 2R + Q = B
➩ 2Q + 2R = 2 (A + B) / 3
advertisement

8. What will be the value of log23 * log32 * log34 * log43 * log56 * log65?
a) 27
b) 3
c) 1
d) 9
View Answer

Answer: c
Explanation: Given,
log23 * log32 * log34 * log43 * log56 * log65
➩ (log3 / log2) * (log2 / log3) * (log4 / log3) * (log3 / log4) * (log6 / log5) * (log5 / log6)
On grouping gives,
➩ [(log3 / log2) * (log2 / log3)] * [(log4 / log3) * (log3 / log4)] * [(log6 / log5) * (log5 / log6)]
➩ 1 * 1 * 1
➩ 1

9. What will be the value of log 9 / 8 + log 3 / 4 – log 27 / 32?
a) 5
b) 10
c) 1
d) 0
View Answer

Answer: d
Explanation: Given,
log 9 / 8 + log 3 / 4 – log 27 / 32
➩ log 32 / 23 + log 3 / 22 – log 33 / 25
➩ 2log 3 / 3 log2 + log 3 / 2 log 2 – 3 log 3 / 5 log 2
➩ log 1
➩ 0
advertisement

10. Which of the following values of t would satisfy the expression log10(25 – t) – log24 = log10t – 2 log105?
a) 5
b) 10
c) 8
d) 12
View Answer

Answer: a
Explanation: Given,
log10(25 – t) – log24 = log10t – 2 log105
LHS
➩ log10(25 – t) – log24
➩ log10(25 – t) – log222
➩ log10(25 – t) – 2
➩ log10(25 – t) – log10 100
➩ log10((25 – t) / 100)
RHS
➩ log10t – 2 log105
➩ log10t – log1052
➩ log10t – log1025
➩ log10(t / 25)
On equating RHS and LHS gives,
➩ t / 25 = 25 – t / 100
➩ t = 25 – t / 4
➩ 4t = 25 – t
➩ 5t = 25
➩ t = 5

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

advertisement
advertisement
Subscribe to our Newsletters (Subject-wise). Participate in the Sanfoundry Certification contest to get free Certificate of Merit. Join our social networks below and stay updated with latest contests, videos, internships and jobs!

Youtube | Telegram | LinkedIn | Instagram | Facebook | Twitter | Pinterest
Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

Subscribe to his free Masterclasses at Youtube & discussions at Telegram SanfoundryClasses.