Alligation or Mixture Questions and Answers

This set of Aptitude Questions and Answers (MCQs) focuses on “Alligation or Mixture”. These questions are beneficial for various competitive exams, placement interviews, and entrance tests.

1. 5 liters of water is mixed in x liters of milk. If the water is 20% of the mixture, find the value of x.
a) 5 liters
b) 25 liters
c) 10 liters
d) 20 liters
View Answer

Answer: d
Explanation: The quantity of milk is x liters.
The quantity of water is 5 liters
Water is 20% of the final solution
20% of the solution is 5 liters
100% of the solution = 100 / 20 * 5 = 25
The quantity of milk = 25 – 5 = 20 liters.

2. A solution contains 20% of mixture p and 50% of mixture q. If the quantity of r is 18 liters, find the quantity of the entire mixture.
a) 30 liters
b) 45 liters
c) 60 liters
d) 90 liters
View Answer

Answer: c
Explanation: The percentage of mixture r = 100 – (20 + 50) = 100 – 70 = 30%
30% of the solution is 18 liters.
100 % of the mixture = 18 / 30 * 100 = 60 liters.

3. A solution containing 50% of milk is mixed with another mixture containing x% of milk in equal proportions. The mixture so formed contains 45% of milk. Find the value of x.
a) 10
b) 20
c) 30
d) 40
View Answer

Answer: d
Explanation: The mixtures are mixed in equal proportions.
Let the quantity of both the mixtures be 100 liters initially.
The volume of milk from the first mixture = 50% of 100 = 50 liters
The volume of milk from the second mixture = x% of 100 = x liters
The volume of milk in the newly formed mixture = 45% of 200 = x + 50
X + 50 = 45% of 200 = 90
X + 50 = 90, x = 90 – 50 = 40
X = 40
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4. A solution containing 55% of milk is mixed with another mixture containing x% of milk in equal proportions. The mixture so formed contains 75% of milk. Find the value of x.
a) 55
b) 65
c) 85
d) 95
View Answer

Answer: d
Explanation: The mixtures are mixed in equal proportions.
Let the quantity of both the mixtures be 100 liters initially.
The volume of milk from the first mixture = 55% of 100 = 55 liters
The volume of milk from the second mixture = x% of 100 = x liters
The volume of milk in the newly formed mixture = 75% of 200 = x + 55
75% of 200 = x + 55 = 150 = x + 55, x = 150 – 55 = 95
X = 95

5. A solution containing 35% of oil is mixed with another mixture containing x% of oil in a ratio 2 : 3. If the mixture so formed contains 20% of oil, find the value of x.
a) 10
b) 15
c) 20
d) 25
View Answer

Answer: a
Explanation: The mixtures are mixed in a ratio 2 : 3.
Let the quantities of mixture mixed be 200 liters and 300 liters, respectively.
The amount of oil in first mixture = 35% = 35% of 200 = 70 liters
The amount of oil in the second mixture = x% = x% of 300 = 3x
The mixture formed by mixing the two given mixtures contains 20% of oil = 20% of 500 = 100 liters
100 liters = 70 liters + 3x
3x = 30, x = 10

6. A mixture containing 50% of water is mixed with another mixture x% of water in the ratio 4 : 5. If the percentage of water in the new mixture is 40%, find the value of x.
a) 30
b) 32
c) 34
d) 40
View Answer

Answer: b
Explanation: The mixtures are mixed in a ratio 4 : 5.
Let the quantities of the mixture mixed be 400 liters and 500 liters, respectively.
The percentage of water in first mixture = 50% = 50% of 400 = 200 liters
The quantity of water in the second mixture = x% of 500 = 5x
The quantity of water in the final mixture = 40% of 900 = 360 liters
5x + 200 liters = 360 liters
5x = 360 – 200 = 160 liters
X = 160 / 5 = 32
X = 32

7. A mixture containing 35% acid is mixed in another liquid containing x% acid in a ratio 3 : 2. If the percentage of acid in the final solution is 30%, find the value of x.
a) 17.5
b) 22.5
c) 25.5
d) 27.5
View Answer

Answer: b
Explanation: The mixtures are mixed in a ratio 3 : 2.
Let the quantity of the mixtures mixed be 300 liters and 200 liters, respectively.
The quantity of acid in the first mixture = 35% of 300 = 105 liters
The quantity of acid in the second mixture = x% of 200 = 2x
The quantity of acid in the final mixture = 30% of 500 = 150 liters
2x + 105 liters = 150 liters, 2x = 45 liters, x = 45 / 2 = 22.5
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8. A mixture containing 70% of water is mixed in another mixture containing x% of water in the ratio 1 : 10. If the percentage of water in the mixture so formed is 20%, find the value of x.
a) 15
b) 20
c) 25
d) 30
View Answer

Answer: a
Explanation: The mixtures are mixed in a ratio 1 : 10.
Let the mixtures mixed be 100 liters and 1000 liters.
The quantity of water in the first mixture = 70% of 100 = 70 liters
The quantity of water in the second mixture = x% of 1000 = 10x
The quantity of water in the final mixture = 20% of 1100 = 220
70 + 10x = 220, 10x = 150, x = 15

9. A mixture containing 65% of ethanol is mixed with another mixture containing x% of ethanol in the ratio 8 : 13. If the percentage of ethanol in the final mixture is 50%, find the value of x.
a) 40.76
b) 42.67
c) 44.76
d) 46.67
View Answer

Answer: a
Explanation: The mixtures are mixed in a ratio 8 : 13.
Let the quantities of mixture mixed be 800 liters and 1300 liters, respectively.
The quantity of ethanol in the first mixture = 65% of 800 = 520 liters
The quantity of ethanol in the second mixture = x% of 1300 = 13x
The quantity of ethanol in the final mixture = 50% of 2100 = 1050
13x + 520 = 1050, 13x = 530, x = 530 / 13 = 40.76
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10. A mixture containing 45% of oil is mixed with another mixture containing x% of oil in a ratio 3 : 5. If the quantity of oil in the final mixture is 50% of the mixture, find the value of x.
a) 51
b) 52
c) 53
d) 55
View Answer

Answer: c
Explanation: The mixtures are mixed in a ratio 3 : 5.
Let the quantities of the mixture mixed be 300 liters and 500 liters, respectively.
The amount of oil in the first mixture = 45% of 300 = 135 liters
The quantity of oil in the second mixture = x% of 500 = 5x
The quantity of oil in the final mixture = 50% of 800 = 400 liters
5x + 135 = 400, 5 = 400 – 135 = 265, x = 265 / 5 = 53
X = 53

11. A solution containing 95% of oil is mixed with another mixture containing x% of oil in a ratio 3 : 2. If the mixture so formed contains 60% of oil, find the value of x.
a) 7.5
b) 10
c) 12.5
d) 15
View Answer

Answer: a
Explanation: The mixtures are mixed in a ratio 3 : 2.
Let the quantities of mixture mixed be 300 liters and 200 liters, respectively.
The amount of oil in first mixture = 95% = 95% of 300 = 285 liters
The amount of oil in the second mixture = x% = x% of 200 = 2x
The mixture formed by mixing the two given mixtures contains 60% of oil = 60% of 500 = 300 liters
300 liters = 285 liters + 2x
2x = 15, x = 7.5

12. A mixture containing 30% of water is mixed with another mixture x% of water in the ratio 5 : 2. If the percentage of water in the new mixture is 30%, find the value of x.
a) 20
b) 30
c) 40
d) 50
View Answer

Answer: b
Explanation: The mixtures are mixed in a ratio 5 : 2.
Let the quantities of the mixture mixed be 500 liters and 200 liters, respectively.
The percentage of water in first mixture = 30% = 30% of 500 = 150 liters
The quantity of water in the second mixture = x% of 200 = 2x
The quantity of water in the final mixture = 30% of 700 = 210 liters
2x + 150 liters = 210 liters
2x = 210 – 150 = 60 liters
X = 60 / 2 = 30
X = 30

13. A mixture containing 75% acid is mixed in another liquid containing x% acid in a ratio 1 : 3. If the percentage of acid in the final solution is 37.5%, find the value of x.
a) 17
b) 22
c) 25
d) 27
View Answer

Answer: c
Explanation: The mixtures are mixed in a ratio 1 : 3.
Let the quantity of the mixtures mixed be 100 liters and 300 liters, respectively.
The quantity of acid in the first mixture = 75% of 100 = 75 liters
The quantity of acid in the second mixture = x% of 300 = 3x
The quantity of acid in the final mixture = 37.5% of 400 = 150 liters
3x + 75 liters = 150 liters, 3x = 75 liters, x = 75 / 3 = 25

14. A mixture containing 10% of water is mixed in another mixture containing x% of water in the ratio 2 : 3. If the percentage of water in the mixture so formed is 22%, find the value of x.
a) 15
b) 20
c) 25
d) 30
View Answer

Answer: d
Explanation: The mixtures are mixed in a ratio 2 : 3.
Let the mixtures mixed be 200 liters and 300 liters.
The quantity of water in the first mixture = 10% of 200 = 20 liters
The quantity of water in the second mixture = x% of 300 = 3x
The quantity of water in the final mixture = 22% of 500 = 110
20 + 3x = 110, 3x = 90, x = 30

15. A mixture containing 25% of ethanol is mixed with another mixture containing x% of ethanol in the ratio 7 : 8. If the percentage of ethanol in the final mixture is 17%, find the value of x.
a) 5
b) 7
c) 10
d) 13
View Answer

Answer: c
Explanation: The mixtures are mixed in a ratio 7 : 8.
Let the quantities of mixture mixed be 700 liters and 800 liters, respectively.
The quantity of ethanol in the first mixture = 25% of 700 = 175 liters
The quantity of ethanol in the second mixture = x% of 800 = 8x
The quantity of ethanol in the final mixture = 17% of 1500 = 255 liters
8x + 175 = 255, 8x = 80, x = 80 / 8 = 10

More Aptitude Questions and Answers on Alligation or Mixture:

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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