This set of Aptitude Questions and Answers (MCQs) focuses on “Alligation or Mixture”. These questions are beneficial for various competitive exams, placement interviews, and entrance tests.

1. 5 liters of water is mixed in x liters of milk. If the water is 20% of the mixture, find the value of x.

a) 5 liters

b) 25 liters

c) 10 liters

d) 20 liters

View Answer

Explanation: The quantity of milk is x liters.

The quantity of water is 5 liters

Water is 20% of the final solution

20% of the solution is 5 liters

100% of the solution = 100 / 20 * 5 = 25

The quantity of milk = 25 – 5 = 20 liters.

2. A solution contains 20% of mixture p and 50% of mixture q. If the quantity of r is 18 liters, find the quantity of the entire mixture.

a) 30 liters

b) 45 liters

c) 60 liters

d) 90 liters

View Answer

Explanation: The percentage of mixture r = 100 – (20 + 50) = 100 – 70 = 30%

30% of the solution is 18 liters.

100 % of the mixture = 18 / 30 * 100 = 60 liters.

3. A solution containing 50% of milk is mixed with another mixture containing x% of milk in equal proportions. The mixture so formed contains 45% of milk. Find the value of x.

a) 10

b) 20

c) 30

d) 40

View Answer

Explanation: The mixtures are mixed in equal proportions.

Let the quantity of both the mixtures be 100 liters initially.

The volume of milk from the first mixture = 50% of 100 = 50 liters

The volume of milk from the second mixture = x% of 100 = x liters

The volume of milk in the newly formed mixture = 45% of 200 = x + 50

X + 50 = 45% of 200 = 90

X + 50 = 90, x = 90 – 50 = 40

X = 40

4. A solution containing 55% of milk is mixed with another mixture containing x% of milk in equal proportions. The mixture so formed contains 75% of milk. Find the value of x.

a) 55

b) 65

c) 85

d) 95

View Answer

Explanation: The mixtures are mixed in equal proportions.

Let the quantity of both the mixtures be 100 liters initially.

The volume of milk from the first mixture = 55% of 100 = 55 liters

The volume of milk from the second mixture = x% of 100 = x liters

The volume of milk in the newly formed mixture = 75% of 200 = x + 55

75% of 200 = x + 55 = 150 = x + 55, x = 150 – 55 = 95

X = 95

5. A solution containing 35% of oil is mixed with another mixture containing x% of oil in a ratio 2 : 3. If the mixture so formed contains 20% of oil, find the value of x.

a) 10

b) 15

c) 20

d) 25

View Answer

Explanation: The mixtures are mixed in a ratio 2 : 3.

Let the quantities of mixture mixed be 200 liters and 300 liters, respectively.

The amount of oil in first mixture = 35% = 35% of 200 = 70 liters

The amount of oil in the second mixture = x% = x% of 300 = 3x

The mixture formed by mixing the two given mixtures contains 20% of oil = 20% of 500 = 100 liters

100 liters = 70 liters + 3x

3x = 30, x = 10

6. A mixture containing 50% of water is mixed with another mixture x% of water in the ratio 4 : 5. If the percentage of water in the new mixture is 40%, find the value of x.

a) 30

b) 32

c) 34

d) 40

View Answer

Explanation: The mixtures are mixed in a ratio 4 : 5.

Let the quantities of the mixture mixed be 400 liters and 500 liters, respectively.

The percentage of water in first mixture = 50% = 50% of 400 = 200 liters

The quantity of water in the second mixture = x% of 500 = 5x

The quantity of water in the final mixture = 40% of 900 = 360 liters

5x + 200 liters = 360 liters

5x = 360 – 200 = 160 liters

X = 160 / 5 = 32

X = 32

7. A mixture containing 35% acid is mixed in another liquid containing x% acid in a ratio 3 : 2. If the percentage of acid in the final solution is 30%, find the value of x.

a) 17.5

b) 22.5

c) 25.5

d) 27.5

View Answer

Explanation: The mixtures are mixed in a ratio 3 : 2.

Let the quantity of the mixtures mixed be 300 liters and 200 liters, respectively.

The quantity of acid in the first mixture = 35% of 300 = 105 liters

The quantity of acid in the second mixture = x% of 200 = 2x

The quantity of acid in the final mixture = 30% of 500 = 150 liters

2x + 105 liters = 150 liters, 2x = 45 liters, x = 45 / 2 = 22.5

8. A mixture containing 70% of water is mixed in another mixture containing x% of water in the ratio 1 : 10. If the percentage of water in the mixture so formed is 20%, find the value of x.

a) 15

b) 20

c) 25

d) 30

View Answer

Explanation: The mixtures are mixed in a ratio 1 : 10.

Let the mixtures mixed be 100 liters and 1000 liters.

The quantity of water in the first mixture = 70% of 100 = 70 liters

The quantity of water in the second mixture = x% of 1000 = 10x

The quantity of water in the final mixture = 20% of 1100 = 220

70 + 10x = 220, 10x = 150, x = 15

9. A mixture containing 65% of ethanol is mixed with another mixture containing x% of ethanol in the ratio 8 : 13. If the percentage of ethanol in the final mixture is 50%, find the value of x.

a) 40.76

b) 42.67

c) 44.76

d) 46.67

View Answer

Explanation: The mixtures are mixed in a ratio 8 : 13.

Let the quantities of mixture mixed be 800 liters and 1300 liters, respectively.

The quantity of ethanol in the first mixture = 65% of 800 = 520 liters

The quantity of ethanol in the second mixture = x% of 1300 = 13x

The quantity of ethanol in the final mixture = 50% of 2100 = 1050

13x + 520 = 1050, 13x = 530, x = 530 / 13 = 40.76

10. A mixture containing 45% of oil is mixed with another mixture containing x% of oil in a ratio 3 : 5. If the quantity of oil in the final mixture is 50% of the mixture, find the value of x.

a) 51

b) 52

c) 53

d) 55

View Answer

Explanation: The mixtures are mixed in a ratio 3 : 5.

Let the quantities of the mixture mixed be 300 liters and 500 liters, respectively.

The amount of oil in the first mixture = 45% of 300 = 135 liters

The quantity of oil in the second mixture = x% of 500 = 5x

The quantity of oil in the final mixture = 50% of 800 = 400 liters

5x + 135 = 400, 5 = 400 – 135 = 265, x = 265 / 5 = 53

X = 53

11. A solution containing 95% of oil is mixed with another mixture containing x% of oil in a ratio 3 : 2. If the mixture so formed contains 60% of oil, find the value of x.

a) 7.5

b) 10

c) 12.5

d) 15

View Answer

Explanation: The mixtures are mixed in a ratio 3 : 2.

Let the quantities of mixture mixed be 300 liters and 200 liters, respectively.

The amount of oil in first mixture = 95% = 95% of 300 = 285 liters

The amount of oil in the second mixture = x% = x% of 200 = 2x

The mixture formed by mixing the two given mixtures contains 60% of oil = 60% of 500 = 300 liters

300 liters = 285 liters + 2x

2x = 15, x = 7.5

12. A mixture containing 30% of water is mixed with another mixture x% of water in the ratio 5 : 2. If the percentage of water in the new mixture is 30%, find the value of x.

a) 20

b) 30

c) 40

d) 50

View Answer

Explanation: The mixtures are mixed in a ratio 5 : 2.

Let the quantities of the mixture mixed be 500 liters and 200 liters, respectively.

The percentage of water in first mixture = 30% = 30% of 500 = 150 liters

The quantity of water in the second mixture = x% of 200 = 2x

The quantity of water in the final mixture = 30% of 700 = 210 liters

2x + 150 liters = 210 liters

2x = 210 – 150 = 60 liters

X = 60 / 2 = 30

X = 30

13. A mixture containing 75% acid is mixed in another liquid containing x% acid in a ratio 1 : 3. If the percentage of acid in the final solution is 37.5%, find the value of x.

a) 17

b) 22

c) 25

d) 27

View Answer

Explanation: The mixtures are mixed in a ratio 1 : 3.

Let the quantity of the mixtures mixed be 100 liters and 300 liters, respectively.

The quantity of acid in the first mixture = 75% of 100 = 75 liters

The quantity of acid in the second mixture = x% of 300 = 3x

The quantity of acid in the final mixture = 37.5% of 400 = 150 liters

3x + 75 liters = 150 liters, 3x = 75 liters, x = 75 / 3 = 25

14. A mixture containing 10% of water is mixed in another mixture containing x% of water in the ratio 2 : 3. If the percentage of water in the mixture so formed is 22%, find the value of x.

a) 15

b) 20

c) 25

d) 30

View Answer

Explanation: The mixtures are mixed in a ratio 2 : 3.

Let the mixtures mixed be 200 liters and 300 liters.

The quantity of water in the first mixture = 10% of 200 = 20 liters

The quantity of water in the second mixture = x% of 300 = 3x

The quantity of water in the final mixture = 22% of 500 = 110

20 + 3x = 110, 3x = 90, x = 30

15. A mixture containing 25% of ethanol is mixed with another mixture containing x% of ethanol in the ratio 7 : 8. If the percentage of ethanol in the final mixture is 17%, find the value of x.

a) 5

b) 7

c) 10

d) 13

View Answer

Explanation: The mixtures are mixed in a ratio 7 : 8.

Let the quantities of mixture mixed be 700 liters and 800 liters, respectively.

The quantity of ethanol in the first mixture = 25% of 700 = 175 liters

The quantity of ethanol in the second mixture = x% of 800 = 8x

The quantity of ethanol in the final mixture = 17% of 1500 = 255 liters

8x + 175 = 255, 8x = 80, x = 80 / 8 = 10

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