Percentage Questions and Answers – Set 3

This set of Aptitude Questions and Answers (MCQs) focuses on “Percentage – Set 3”.

1. Find 11% of 13% of 17% of 1 million.
a) 2134
b) 2413
c) 3124
d) 2431
View Answer

Answer: d
Explanation: 17% of 1,000,000:
17 % of 1,000,000 = 17 * 1,000,000 / 100
170,000
13% of 170,000:
13 * 170,000 / 100 = 22,100
11% of 22,100:
11 * 22,100 / 100 = 2,431

2. A number if doubled, then tripled and this process is repeated twice. What is the percentage change?
a) 3500%
b) 3000%
c) 2500%
d) 1750%
View Answer

Answer: a
Explanation: Let the number be x.
The number is first doubled:
X * 2 = 2x
The number is then tripled:
2x * 3 = 6x
This process is repeated twice:
6x * 2 = 12x
12x * 3 = 36x
The change in value = 36x – x = 35x
The percentage change = 35x / x * 100 = 3500%

3. What percent of 50 is 0.005% of 10000?
a) 1%
b) 10%
c) 0.1%
d) 100%
View Answer

Answer: a
Explanation: 0.005% of 10,000 = 0.005 * 10,000 / 100 = 0.5
Percentage of 50 equivalent to 0.5 = 0.5 / 50 * 100 = 1%

4. By how much should 234 be reduced to make it 65% of itself?
a) 80.9
b) 81.9
c) 82.9
d) 83.9
View Answer

Answer: b
Explanation: To be equivalent to 65% of itself, the number 234 must be reduced by (100 – 35) % of itself.
234 must b reduced by 35 % of 234.
35% of 234 = 234 * 35 / 100 = 81.9
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5. A number when increased by 120 it becomes 300% of itself, find 200% of the number.
a) 100
b) 180
c) 120
d) 150
View Answer

Answer: c
Explanation: Let the number be x.
X + 120 = 300% of x
X + 120 = 300x / 100
100x + 12,000 = 300x
12,000 = 300x – 100x
12,000 = 200x
X = 60
To find 200% of x:
200% of x
200 * x / 100 = 200 * 60 / 100 = 120

6. What is 90% of 900% of 9000% of 9?
a) 7290
b) 729
c) 6156
d) 6561
View Answer

Answer: d
Explanation: 9000% of 9:
900% of 9 = 9000 * 9 / 100 = 810
900% of 810:
900% of 810 = 900 * 810 / 100 = 7290
90% of 7290:
90% of 7290 = 90 * 7290 / 100 = 6561

7. 25% of x is 70% of y. Find the value of x : y.
a) 5 : 49
b) 6 : 23
c) 8 : 41
d) 7 : 40
View Answer

Answer: d
Explanation: 25% of x = 25x / 100 = x / 4
70% of y = 7y / 10
x / 4 = 7y / 10
x / y = 7 / (4 * 10) = 7 / 40
x : y = 7 : 40
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8. A number is multiplied by 20% of itself, the sum is then doubled. If the final value is 490, find the number.
a) 35
b) 40
c) 45
d) 50
View Answer

Answer: a
Explanation: Let the number be x.
X is multiplied by 20% of itself and then doubled,
20% of x = x * 20 / 100 = x / 5
X * x / 5 = x2 / 5
The sum now is doubled: x2 * 2 / 5 = 490
2x2 = 490 * 5 = 2450
X2 = 2450 / 2 = 1225
X2 = 1225
X = 35

9. What is the result when 40% of 30% of 120 is multiplied by 20% of 80% of 220?
a) 588.06
b) 508.66
c) 506.88
d) 505.86
View Answer

Answer: c
Explanation: 30% of 120 = 30 * 120 / 100 = 36
40% of 36 = 40 * 36 / 100 = 14.4
80% of 220 = 80 * 220 / 100 = 176
20% of 176 = 20 * 176 / 100 = 35.2
14.4 * 35.2 = 506.88
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10. Out of 25 employees of a company, 13 are set of and the salaries of rest of the employees is increased by 24%. Find the total increase of decrease in company’s expenditure.
a) 40.48% decreased
b) 40.44% increased
c) 44.48% decreased
d) 44.84% increased
View Answer

Answer: a
Explanation: Let the initial salary of each employee be 100.
The initial expenditure of the company = 25 * 100 = 2,500
Salary of the remaining employees:
100 + 24% of 100 = 100 + 24 = 124
The number of employees who are still in the job = 25 – 13 = 12
The final expenditure of the company = 12 * 124 = 1488
The difference in company’s expenditure = 2500 – 1488 = 1012
Percentage change in company’s expenditure = 1012 / 2500 * 100 = 40.48% decreased

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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