Problems on Ages Questions and Answers – Multiple People – Set 2

This set of Aptitude Questions and Answers (MCQs) focuses on “Multiple People – Set 2”.

1. Age of 7 people are in a ratio 9 : 12 : 13 : 14 : 5 : 9 : 10. If the total of their ages is 432, find the age of the eldest person.
a) 72 years
b) 84 years
c) 70 years
d) 86 years
View Answer

Answer: b
Explanation: Let the ages of the people be in terms of x.
Their ages = 9x, 12x, 13x, 14x, 5x, 9x and 10x
Total of their ages = 9x + 12x + 13x + 14x + 5x + 9x + 10x = 72x
72x = 432 years
X = 432/72 = 6years
Age of the eldest person = 6 * 14 = 84 years

2. The age of 5 people are in a ratio 1 : 3 : 5 : 7 : 9. If the difference between the age of each individual when arranged in ascending order is 12 years, find their average age.
a) 20 years
b) 25 years
c) 30 years
d) 35 years
View Answer

Answer: c
Explanation: Let their ages be in terms of x.
Their ages in terms of x = x, 3x, 5x, 7x and 9x
Difference between their ages = 12 years
3x – x = 5x – 3x = 7x – 5x = 9x – 7x = 12 years
3x – x = 2x = 12 years
2x = 12 years
X = 12/2 = 6 years
X = 6 years
3x = 6 * 3 = 18 years
5x = 6 * 5 = 30 years
6x = 6 * 7 = 42 years
9x = 6 * 9 = 54 years
Total age of the group = 6 + 18 + 30 + 42 + 54 = 150 years
Average age = 150/5 = 30 years

3. If the average age of a group of 4 students is 20% more than the average age of a group of 7 students whose total age is 119 years, find the total age of the first group.
a) 80 years
b) 81.6 years
c) 82.2 years
d) 83.8 years
View Answer

Answer: b
Explanation: The total age of group 2 of students = 119 years
The average age of students of group 2 = total age/number of students
119/7 = 17 years
Average age of students of first group = 17 years + 20% of 17 years
17 years + 17 * 20/100 years = 17 + 3.4 years = 20.4 years
Total age of the students of the first group = 20.4 * 4
20.4 * 4 = 81.6 years
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4. My sister is twice the age of my brother. My brother is 1/7th the age of my father. If the ratio of ages of my father to my mother is 17.5 : 18, find my sister’s age. It Is known that my mother is 36 years old.
a) 20 years
b) 12 years
c) 8 years
d) 10 years
View Answer

Answer: d
Explanation: Age of my mother = 36 years (given)
Age of my father = (36/18) * 17.5 = 2 * 17.5
2 * 17.5 = 35
My father’s age is 35 years old.
Brother’s age = 1/7th of my father’s age
Brother’s age = 35/7 = 5 years
Sister’s age is twice my brother’s age.
Sister’s age = 5 * 2 = 10 years

5. The ages of 6 friends are in a ratio 5 : 6 : 7 : 7 : 8 : 9. If the eldest of them is 8 years more than the mean of their ages, find the age of the 2nd youngest friend.
a) 20 years
b) 24 years
c) 35 years
d) 28 years
View Answer

Answer: b
Explanation: Let their ages be in terms of x.
Their ages are 5x, 6x, 7x, 7x, 8x and 9x.
The mean of their age in terms of x:
(5x + 6x + 7x + 7x + 8x + 9x)/6 = 42x/6 = 7x
Mean of the ages = 7x
Age of the eldest person = 9x
Difference between the ages of the eldest person and the mean of their ages:
Difference = 9x – 7x = 8 years
2x = 8 years
X = 8/2 = 4 years
X = 4 years
Age of the 2nd youngest = 6x
6x = 6 * 4 = 24 years

6. The median of age of 5 friends is 12 years. If their ages are in a ratio 6 : 5 : 8 : 3 : 4, find the age of the eldest friend.
a) 17 years
b) 15.5 years
c) 18 years
d) 19.2 years
View Answer

Answer: d
Explanation: Let their ages be in terms of x.
Their ages are 6x, 5x, 8x, 3x and 4x.
To find the median of their ages in terms we must arrange their ages in ascending order.
3x < 4x < 5x < 6x < 8x
Median of the series = 5x = 12 years given
X = 12/5 = 2.4 years
Age of the eldest friend = 8x
8x = 8 * 2.4 = 19.2 years

7. The total age of a group of 9 students is 171 years. The average age of another group half of the average age of first group. If there are 6 people in group, find the average age of both the groups put together.
a) 15 years
b) 15.2 years
c) 15.4 years
d) 15.5 years
View Answer

Answer: b
Explanation: The total age of group 1 = 171 years
The average age of first group:
171/9 = 19 years
The average age of the second group = half of the average age of the first group.
19/2 = 9.5 years
Total age of the second group:
9.5 * 6 = 57 years
Total age of the 2 groups = 57 + 171 = 228 years
Average age of both the groups = 228/15 = 15.2 years
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8. There are 7 members in a clan. Out of them 3 shares an average age of 20 years. The average age of the rest 4 members is 18 years. Find the average age of the clan after a championship of 365 days.
a) 19.80 years
b) 19.70 years
c) 19.85 years
d) 19.75 years
View Answer

Answer: c
Explanation: Total age of the clan = age of the 1st group + age of the 2nd group
Total age of the first group = 3 * 20 years = 60 years
Total age of the second group = 4 * 18 years = 72 years
Total age of the clan = 60 + 72 = 132 years
Total age of the clan after 365 days = 132 + 7 * 1 = 132 + 7 = 139 years
Average age of the clan after a year = 139/7 = 19.85 years

9. A group has 4 friends named p, q, r and s. It is known that p = 2q, q = 2r and r = 2s. If the total of their ages is 105, find the total of the age of q.
a) 28 years
b) 29 years
c) 30 years
d) 32 years
View Answer

Answer: a
Explanation: Let the age of every individual be in terms of a constant x.
Now, assuming s = x, r = 2s = 2x, q = 2r = 4x, p = 2q = 8x.
Total of their ages = x + 2x + 4x + 8x = 15x
Given total of their age = 105 years
15x = 105 years
X = 105/15 = 7 years
Age of q = 4x = 7 * 4 = 28 years
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10. Out of 7 members of a family a, b, c, d, e, f and g, a and b share an average age 20, c and d share an average age 35 and e, f and g share an average age of 50 years. Find the average age of the family nearest to 2nd place of decimal.
a) 36.14 years
b) 36.16 years
c) 37.14 years
d) 37.15 years
View Answer

Answer: c
Explanation: Total age of the family = sum of all the groups
Total age of group 1 = 20 * 2 = 40 years
Total age of group 2 = 35 * 2 = 70 years
Total age of the third group = 50 * 3 = 150 years
Total age of the entire family = 40 + 70 + 150 = 260 years
Average age of the entire family = 260/7 = 37.142 years ≈ 37.14 years

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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