Problems on Trains Questions and Answers – Train and Station – Set 2

This set of Aptitude Questions and Answers (MCQs) focuses on “Train and Station – Set 2”.

1. A train 250 m in length crossed a station 500 m in length in 45 seconds, find the time needed by the train to cover 50 km.
a) 0.75 hours
b) 0.83 hours
c) 1 hour
d) 1.12 hours
View Answer

Answer: b
Explanation: The speed of the train = distance / time = 750 / 45 = 16.66 m / s
The speed in kmph = 60 kmph
The time taken to cover 50 km = 50 / 60 = 0.83 hours.

2. A train 350m long crossed a station of equal length in 105 seconds. Find the time required by the train to cover 1270 km.
a) 52.91 hours
b) 52.92 hours
c) 52.93 hours
d) 52.94 hours
View Answer

Answer: b
Explanation: The speed of the train = distance / time = 700 / 105 = 6.66 m / s = 24 kmph
Time taken to cover 1270 km = 1270 / 24 = 52.916 hours.

3. The speed of a train is 45 kmph. Find the time required by the train to cross a station of 500m if the train is 340m long.
a) 1.02 hours
b) 1.12 hours
c) 1.20 hours
d) 1.21 hours
View Answer

Answer: b
Explanation: The speed of the train = 45 kmph = 12.5 m / s
The time required = (500 + 340) / 12.5 = 840 / 12.5 = 67.2 minutes = 1.12 hours.
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4. A train is x meters long. The train crosses a station 5x meters long in 40 seconds. Find the speed of the train in terms of x.
a) 25x / 47 kmph
b) 27x / 50 kmph
c) 30x / 53 kmph
d) 33x / 56 kmph
View Answer

Answer: b
Explanation: The speed of the train = distance covered / time taken = (5x + x) / 40 = 6x / 40 m / s = 6x * 18 / 40 * 5 = 108x / 200 kmph = 27x / 50 kmph.

5. A train with a speed of 12.5 kmph crosses a station 125 m long in 125 seconds. Find the length of the train.
a) 209 m
b) 259 m
c) 309 m
d) 359 m
View Answer

Answer: c
Explanation: The total distance covered = speed * time
Speed of the train = 12.5 kmph = 3.472 m / s
The distance = 3.472 * 125 = 434 m
The length of the train = 434 – 125 = 309 m.

6. The distance covered by a train in 87 minutes is 108.75 km. find the time taken by the train to cross a platform equal to its length. The train is 450 m long.
a) 40.2 seconds
b) 40.4 seconds
c) 40.02 seconds
d) 40.04 seconds
View Answer

Answer: a
Explanation: The speed of the train:
The speed = distance / time = 108.75 / 87 = 1.25 km per minute = 75 kmph = 20.83 m / s
The total distance to be covered = 450 * 2 = 900m
The time taken = 900 / 20.83 = 40.206 seconds.

7. The time taken by a train to cover a distance equal to its length is 120 seconds. If the speed of the train is 45 kmph, find the length of the train.
a) 3000 m
b) 1500 m
c) 750 m
d) 37.5 m
View Answer

Answer: c
Explanation: The speed of the train = 45 kmph = 12.5 m / s
The distance covered = Let it be 2x.
The distance = Speed * time = 120 * 12.5 = 1500
2x = 1500 m
X = 1500 / 2 = 750 m
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8. The distance covered by a train in 6 hours is 1260 km. Find the time taken by the train to cross a station 3 km long. The train is 245m long.
a) 55.63 seconds
b) 44.63 seconds
c) 66.63 seconds
d) 65.63 seconds
View Answer

Answer: a
Explanation: The speed of the train = distance / time = 1260 / 6 = 210 kmph
The speed = 210 kmph = 58.33 m / s
The distance to be covered = 3000m + 245m = 3245m
The time taken = 3245 / 58.33 = 55.63 seconds.

9. A train 750m long travels through a tunnel 12 km long in 1250 seconds. Find the speed of the train.
a) 37.62 kmph
b) 36.72 kmph
c) 26.73 kmph
d) 27.63 kmph
View Answer

Answer: b
Explanation: The speed of the train = distance / time
The distance = 1200m + 750m = 12750 m or 12.75 km
The speed of the train = 12750 / 1250 = 10.2 m / s = 36.72 kmph.
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10. A train 120 m in length crosses a tunnel 9 km long in 1338 seconds. Find the speed of the train.
a) 22.5 kmph
b) 23.5 kmph
c) 24.5 kmph
d) 25.5 kmph
View Answer

Answer: c
Explanation: the total distance to be covered = 9000m + 120m = 9120m
The time taken = 9120
The speed of the train = 9120 / 1338 = 6.816 m / s = 24.5 kmph.

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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