Area Questions and Answers

This set of Aptitude Questions and Answers (MCQs) focuses on “Area”. These questions are beneficial for various competitive exams, placement interviews, and entrance tests.

1. What will be the circumference of a circle in cm given its area is 40 cm2?
a) 32.42
b) 25.68
c) 22.37
d) 30.00
View Answer

Answer: c
Explanation: Given,
Area of circle = 40 cm2
➩ πr2 = 40
➩ r2 = 40 / π
➩ r2 = 40 * 7 / 22
➩ r2 = 12.72 or r = 3.56 cm
➩ Circumference = 2πr = 2 * (22 / 7) * 3.56
➩ Circumference = 22.37 cm

2. What will be the area of a square in cm2 that can be inscribed in a circle of radius 6 cm?
a) 72
b) 288
c) 144
d) 256
View Answer

Answer: a
Explanation: Given,
Radius of circle (r) = 6 cm. According to the question the diameter (D) of the square will be equal to the diagonal of the square.
➩ D = 2 * r = 2 * 6 = 12 cm
➩ Area of the square = (1 / 2) * D2 = (1 / 2) * 12 * 12 = 72 cm2

3. If the area of a circle is equal to the area of a square, then what will be the ratio of their perimeters?
a) π:2
b) √π:2
c) 1:2
d) 2:π
View Answer

Answer: b
Explanation: Let the radius of the circle be r and side of the square be a.
Then, πr2 = a2
a = r (π)1/2
Ratio of perimeters = 2 πr / 4a
= 2 πr / 4(r (π)1/2)
= √π:2
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4. A piece of wire 40cm long is bent into the form of an arc subtending an angle of 120 degree at the centre. What will be the radius (in cm) of the circle so formed?
a) 60 / π
b) 20 / π
c) 120 / π
d) 30 / π
View Answer

Answer: a
Explanation: According to the question,
Length of arc = 40 cm
Angle in degree = 120
➩ Length of arc = (Angle in degree / 360) * 2πr
➩ 40 = (120 / 360) * 2πr
➩ r = (40 * 360) / (120 * 2π)
➩ r = 60 / π cm

5. What will be the area of a sector (in sq. cm.) of a circle with radius 42 cm and sector angle 240 degrees?
a) 3350
b) 4623
c) 3696
d) 5128
View Answer

Answer: c
Explanation: Area of sector = (angle in degree / 360) * πr2
➩ Area of sector = (240 / 360) * (22 / 7) * 42 * 42
➩ Area of sector = 3696 cm2

6. What will be the area of the circle (in sq. cm.) that can be inscribed in a square of side 20cm?
a) 150π
b) 75π
c) 200π
d) 100π
View Answer

Answer: d
Explanation: According to the question, the radius of the circle would be half of the side of the square.
➩ r = 20 / 2 = 10 cm
Area of circle = πr2
➩ Area of circle = π * 10 * 10
= 100π cm2

7. What will be the radius of the circle (in cm) for which the circumference and the area are numerically equal?
a) 2
b) 4
c) π
d) 2π
View Answer

Answer: a
Explanation: Let the radius of the circle be r cm.
➩ πr2 = 2πr
➩ r2 = 2r
➩ r = 2 cm
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8. If the radius of a circle is increased by 500%, then by what % does it’s area increases?
a) 3200%
b) 4000%
c) 3500%
d) 3800%
View Answer

Answer: c
Explanation: Area of circle with radius r = πr2.
New radius = r + 500% of r = r + 5r = 6r.
New area = π (6r)2 = 36πr2
Increased area = 36πr2 – πr2 = 35πr2
% increase in area = ((35πr2) / (πr2)) * 100
= 3500%

9. The circumference of a circle exceeds it’s diameter by 120 cm, then what will be the value of its area in sq. cm?
a) 3040
b) 2464
c) 1125
d) 1892
View Answer

Answer: b
Explanation: Let the radius be r cm.
According to the question,
2πr = 2r + 120
➩ 2πr – 2r = 120
➩ 2r (π – 1) = 120
➩ r = 120 / 2(π – 1)
➩ r = 120 * 7 / (15 * 2)
➩ r = 28 cm
Area = πr2 = (22 / 7) * 28 * 28
= 2464 cm2
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10. What will be the area (in sq. cm) of the quadrant of a circle whose circumference is 88cm?
a) 154
b) 144
c) 128
d) 165
View Answer

Answer: a
Explanation: Circumference = 2πr = 88
➩ r = 44 / π cm
➩ Area of the quadrant = (1 / 4) πr2
= (1 / 4) π (44 / π)2
= 154 cm2

More Aptitude Questions and Answers on Area:

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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