This set of Aptitude Questions and Answers (MCQs) focuses on “Operations – Set 2”.
1. Given 486*23=11178, then find the value of \(\frac{11.178}{0.0486}\).
a) 230
b) 23
c) 46
d) 2.3
View Answer
Explanation: 486*23=11178.
\(\frac{11178}{486}\)=23.
\(\frac{11.178}{0.0486}\)=230.
2. Find the value of (0.4*0.4+0.01)(0.1*0.1+0.04)-1.
a) 17/7
b) 17/5
c) 13/8
d) 19/9
View Answer
Explanation: (0.4*0.4+0.01)(0.1*0.1+0.04)-1 = \(\frac{0.4*0.4+0.01}{0.1*0.1+0.04}=\frac{17}{5}\).
3. Find the value of \(\frac{0.8*0.08}{0.64}\).
a) 1
b) 10
c) 0.1
d) 1.1
View Answer
Explanation: \(\frac{0.8*0.08}{0.64}=\frac{0.8*0.08}{0.8*0.8}=\frac{1}{10}\)= 0.1.
4. Find the value of 0.47*135.2 + 4.7*45.65 – 3.896*47.
a) 97.257
b) 82.457
c) 86.687
d) 94.987
View Answer
Explanation: 0.47*135.2 + 4.7*45.65 – 3.896*47 = 4.7*(13.52+45.65-38.96) = 4.7*20.21 = 94.987.
5. Find the value of 0.73*0.73 + 0.27*0.27 + 0.3942.
a) 1
b) 1.96
c) 0.0169
d) 1.141
View Answer
Explanation: 0.73*0.73 + 0.27*0.27 + 0.3942 = 0.732 + 0.272 – 2*0.73*0.27 = (0.73 + 0.27)2 = 1.
6. Find the fraction equivalent to 4\(\frac{4}{5}\)%.
a) 3/250
b) 6/125
c) 6/225
d) 9/125
View Answer
Explanation: 4\(\frac{4}{5}\)%=\(\frac{24}{5}\)%=\(\frac{24}{5*100}\)=\(\frac{6}{125}\).
7. Find the value of \(2\frac{1}{5}+3\frac{3}{10}+4\frac{4}{15}-5\frac{7}{20}\).
a) 29/15
b) 31/12
c) 53/12
d) 19/12
View Answer
Explanation: \(2\frac{1}{5}+3\frac{3}{10}+4\frac{4}{15}-5\frac{7}{20}=\frac{11}{5}+\frac{33}{10}+\frac{64}{15}-\frac{107}{20}=\frac{53}{12}\).
8. Find the value of \(\Big(\frac{2}{13} of \frac{3}{7} of \frac{1}{9} of 546\Big)\).
a) 6
b) 8
c) 3
d) 4
View Answer
Explanation: \(\frac{2}{13} \, of \frac{3}{7} \, of \, \frac{1}{9}\) of 546=\(\frac{2}{13}*\frac{3}{7}*\frac{1}{9}\)*546=4.
9. Find the value of 2\(\frac{2}{5}\)% of 25.
a) 0.6
b) 0.3
c) 0.9
d) 1
View Answer
Explanation: 2\(\frac{2}{5}\)% of 25=\(\frac{12}{5}\)% of 25=\(\frac{12}{5*100}\)*25=\(\frac{3}{5}\)=0.6.
10. If 53.4585 =5A+\(\frac{3}{B}\)+0.2C+\(\frac{0.5}{D}\)+0.02E+0.002F, then find the value of A-B+C-D+E-F.
a) 1.5
b) 1.15
c) 0.15
d) 1.125
View Answer
Explanation: 53.4585 =5A+\(\frac{3}{B}\)+0.2C+\(\frac{0.5}{D}\)+0.02E+0.002F.
50 + 3 + 0.4 + 0.05 + 0.008 + 0.0005 = 5A+\(\frac{3}{B}\)+0.2C+\(\frac{0.5}{D}\)+0.02E+0.002F.
On comparing LHS and RHS, we get,
A=10, B=1, C=2, D=10, E=0.4 and F=0.25.
Therefore, A-B+C-D+E-F = 1.15.
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