This set of Aptitude Questions and Answers (MCQs) focuses on “Simplification Word Problems – Set 2”.

1. A man divides Rs.129000 among 4 sons, 5 daughters and 3 nephews. If each daughter receives four times as much as each nephew and each son receives five times as much as each nephew, how much does each daughter receive?

a) 1500

b) 2500

c) 1200

d) 1720

View Answer

Explanation: Let the share of each nephew be Rs.x.

So, 5*4x + 4*5x + 3x = 12900

43x = 12900 🡪 x = 300.

Therefore, share of each daughter is 4*300 = Rs.1200.

2. Rs.9000 were divided equally among a certain number of persons. Had there been 15 more persons, each would have got Rs.100 less. Find the original number of persons.

a) 30

b) 25

c) 32

d) 35

View Answer

Explanation: Let the original number of persons be x.

Then, \(\frac{9000}{x}-\frac{9000}{x+15}\)=100 🡪 9000 \(\Big(\frac{x+15-x}{x(x+15)}\Big)\)=100 🡪 9000*15=100x(x+15)

x

^{2}+15x-1350=0

(x+45)(x-30)=0

x = 30.

Hence, the original number of persons were 30.

3. Village P has a population of 74000 which is decreasing at the rate of 1400 per year. Village Q has a population of 50000, which is increasing at the rate of 600 per year. In how many years will the population of wo villages be equal?

a) 14

b) 15

c) 12

d) 10

View Answer

Explanation: Let the population of villages P and Q be equal after x years.

Then, 74000 – 1400p = 50000 + 600p 🡪 p = 12.

So, their population will be equal after 12 years.

4. A zoo keeper counted the heads of the animals in the zoo and found it to be 90. When he counted the legs of the animals, he found it to be 290. If the zoo had either peacock or horses, how many horses were there in the zoo?

a) 55

b) 35

c) 50

d) 60

View Answer

Explanation: Let the total number of peacocks be x and total number of horses be y.

Then the total number of heads = x + y = 90 …… (i)

And the total number of legs = 2x + 4y = 290 …… (ii)

Solving (i) and (ii), we get, y = 55 and x = 35.

Hence, the number of horses in the zoo is 55.

5. In a caravan, in addition to 40 hens there are 55 goats and 12 camels with some keepers. If the total number of feet be 268 more than the number of heads, find the number of keepers.

a) 12

b) 16

c) 18

d) 15

View Answer

Explanation: Let the number of keepers be x.

Total number of heads = 40 + 55 + 12 + x = 107 + x.

Total number of legs = 40*2 + 55*4 + 15*4 + x*2 = 2x + 360.

By data, (2x + 360) – (107 + x) = 268 🡪 x = 15.

Hence, the number of keepers is 15.

6. Suresh is on a tour and he has Rs.12000 for his expenses. If he exceeds his tour by 5 days, he must cut down his daily expenses by Rs.120. For how many days is Suresh on tour?

a) 18

b) 20

c) 24

d) 16

View Answer

Explanation: Let Suresh is on tour for x days.

Then, \(\frac{12000}{x}-\frac{12000}{x+5}\)=120 🡪 \(\frac{1}{x}-\frac{1}{x+5}=\frac{1}{100}\) 🡪 5*100=x*(x+5)

x

^{2}+5x-500=0 🡪 (x+25)(x-20)=0 🡪 x = 20.

Hence, Suresh is on tour for 20 days.

7. Neha has 115 currency notes in all, some of which were of Rs.10 denomination and the remaining of Rs.20 denomination. The total amount of all these currency notes was Rs.1770. How much amount did she have in the denomination of Rs.20?

a) 1440

b) 530

c) 1240

d) 630

View Answer

Explanation: Let the number of 20-rupee notes be x. Then, the number of 10-rupee notes is (115-x).

By data, 20*x + 10*(115-x) = 1770 🡪 x = 62.

So, the required amount = 20*62 = Rs.1240.

8. In an objective examination of 120 questions, 4 marks are allotted for every correct answer and 1 mark is deducted for every wrong answer. After attempting all 120 questions a student got a total of 290 marks. Find the number of questions he attempted wrong.

a) 38

b) 42

c) 36

d) 45

View Answer

Explanation: Let the number of questions attempted wrong be x. Then the number of questions attempted correct is (120-x).

By data, 4*(120-x) – 1*x = 290 🡪 x = 38.

Therefore, the number of questions he attempted wrong is 38.

9. A railway half-ticket costs half the full fare. But the reservation charge on half-ticket is the same as that on full ticket. One reserved first-class ticket for a journey between two stations is Rs.820 and the cost of one full and one half reserved first-class tickets is Rs.1240. What is the reservation charge?

a) Rs.25

b) Rs.30

c) Rs.20

d) Rs.40

View Answer

Explanation: Let the full fare be Rs.x and reservation charge per ticket be Rs.y.

By data, x + y = 820 …… (i)

x+y+\(\frac{x}{2}\)+y=1240 🡪 \(\frac{3x}{2}\)+2y=1240 🡪 3x+4y=2480 …… (ii)

Solving (i) and (ii), we get, x = 800 and y = 20.

Therefore, reservation charge per ticket is Rs.20.

10. When an amount was distributed among 12 boys, each of them got Rs.225 more than the amount received by each boy when the same amount is distributed equally among 18 boys. What was the amount?

a) Rs.9500

b) Rs.8100

c) Rs.8900

d) Rs.7200

View Answer

Explanation: Let the total amount be Rs.x.

\(\frac{x}{12}-\frac{x}{18}\)=225 🡪 \(\frac{x}{36}\)=225 🡪 x = 8100.

Hence, the total amount is Rs.8100.

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