Simplification Word Problems Questions and Answers – Set 4

This set of Aptitude Questions and Answers (MCQs) focuses on “Simplification Word Problems – Set 4”.

1. After measuring 100 meters of rope, it was discovered that the measuring meter rod was 2 cm longer. What is the true length of the rope measured?
a) 103 m
b) 105 m
c) 102 m
d) 106 m
View Answer

Answer: a
Explanation: True length = 100 m + 3*100 cm = 100 m + 3 m = 103 m.

2. A man’s investment doubles in every 10 years. If he invested Rs.10000 in each of the years of 1980, 1990 and 2000, then what was the total amount received by him in 2010?
a) 160000
b) 140000
c) 120000
d) 160000
View Answer

Answer: b
Explanation: Total amounted received by him in 2010 = (10000*23)+(10000*22)+(10000*2)=Rs.140000.

3. A flowers in a basket double every minute and the basket gets full in 30 minutes. In how much time, the basket was 1/16 full?
a) 27 minutes
b) 25 minutes
c) 26 minutes
d) 24 minutes
View Answer

Answer: c
Explanation: Since the number doubles every minute, so the basket was \(\frac{1}{2^n}\) full in (30-n) minutes.
Thus, it was \(\frac{1}{16}=\frac{1}{2^4}\) full in (30-4) = 26 minutes.
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4. Three-fifth of one-fourth of seven-ninth of a number is 84. What is half of that number?
a) 300
b) 240
c) 480
d) 360
View Answer

Answer: d
Explanation: Let the number be x.
\(\frac{3}{5}*\frac{1}{4}*\frac{7}{9}\)*x=84 🡪 x = 720.
Therefore, half of that number is 360.

5. 1/4 of a tank holds 175 liters of water. What part of tank is full if it contains 420 liters of water?
a) 3/5
b) 4/7
c) 3/10
d) 4/10
View Answer

Answer: a
Explanation: Let x be the capacity of tank.
By data, \(\frac{x}{4}\)=175 🡪 x = 700 liters.
Therefore, required fraction is \(\frac{420}{700}=\frac{3}{5}\).

6. A drum of kerosene is 3/4 full. When 50 liters of kerosene is drawn from it, it remains 11/16 full. What is the capacity of the drum?
a) 900 liters
b) 800 liters
c) 750 liters
d) 850 liters
View Answer

Answer: b
Explanation: Let the capacity of drum be x.
By data, \(\frac{3x}{4}-\frac{11x}{16}\)=50 🡪 \(\frac{x}{16}\)=50 🡪 x = 800.
Therefore, the capacity of drum is 800 liters.

7. In a family, the brother took 1/4 of the cake and he had 4 times as much as each of the other members had. How many members were there in the family?
a) 12
b) 10
c) 13
d) 15
View Answer

Answer: c
Explanation: Let the total members in the family be x.
By data, brother’s share = 1/4. Then, others share = \(\frac{3}{4x}\).
4*\(\frac{3}{4x}=\frac{1}{4}\) 🡪 x=12.
Therefore, total members in the family is 12+1 = 13.
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8. A computer printed 259200 words in a given day. If the printer is in operation for 8 hours during the day, how many words did it print per minute?
a) 720
b) 620
c) 480
d) 540
View Answer

Answer: d
Explanation: Number of words printed in one hour = \(\frac{259200}{8}\)=32400.
Number of words printed in one minute = \(\frac{32400}{60}\)=540.

9. In a party 20 people shake their hands with each other. How many times did the hand-shakes take place?
a) 210
b) 220
c) 200
d) 190
View Answer

Answer: d
Explanation: When 20 people shake their hands with each other, 1st person shakes hand with 19 others. 2nd person shakes hand with 18 others. 3rd person shakes hand with 17 others and so on.
Total number of hand-shakes = 19+18+17+16+……+3+2+1 = \(\frac{19*20}{2}\)=190.
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10. 12 people are planning to share equally the cost of a rental car. If one person withdraws from the arrangement and the others share equally the entire cost of the car, then by what fraction the share of each of the remaining persons share is increased?
a) 1/10
b) 1/11
c) 1/12
d) 1/9
View Answer

Answer: b
Explanation: Original share of 1 person = \(\frac{1}{12}\). New share of 1 person = \(\frac{1}{11}\).
Increase = \(\frac{1}{11}-\frac{1}{12}=\frac{1}{131}\).
Required fraction = \(\frac{1/131}{1/12}=\frac{1}{11}\).

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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