This set of Aptitude Questions and Answers (MCQs) focuses on “Cylinder – Set 2”.
1. The radius of a roller is 42 cm and its length is 110 cm. It takes 200 complete revolutions to move once over to level a small playground. What is the area (in sq. m) of the playground?
a) 575.8
b) 592.6
c) 580.8
d) 567.9
View Answer
Explanation: Given,
r = 42 cm, h = 110 cm, rev. = 200
Area of playground = rev * curved surface area of roller
= rev * 2πrh
= 200 * 2 * (22 / 7) * 42 * 110 cm2
= 200 * 2 * 22 * 6 * 110
= 5808000 cm2
= 580.8 m2
2. A cylindrical pillar is 40 cm in diameter and 280 cm in height. What is the curved surface area of this pillar?
a) 3.52 m2
b) 35.2 m2
c) 0.352 m2
d) 352 m2
View Answer
Explanation: Given,
Diameter = 40 cm, r = diameter / 2 = 20 cm, height = 350 cm
Curved surface area = 2πrh
= 2 * (22 / 7) * 20 * 280 cm2
= 2 * 22 * 20 * 40 cm2
= 35200 cm2
= 3.52 m2
3. The inner diameter of circular well is 3.2 m and is 15 m deep. What will be its inner curved surface area in m2?
a) 136.76
b) 150.85
c) 167.55
d) 173.68
View Answer
Explanation: Given,
Diameter = 3.2 m, r = diameter / 2 = 3.2 / 2 = 1.6 m, h = 15 m
Curved surface area = 2πrh
= 2 * (22 / 7) * 1.6 * 15
= 150.85 m2
4. Five similar small rollers each having radius 7 cm and length as 10 cm are to be painted at a rate of Rs.10 / cm2. What will be the total cost of painting (in Rs.)?
a) 22000
b) 67.5 kg
c) 75.6 kg
d) 65.7 kg
View Answer
Explanation: Given,
No. = 5, r = 7 cm, l = 10 cm, rate = Rs. 10 / cm2
Cost of painting = 2πrl * No. * rate
= 2 * (22 / 7) * 7 * 10 * 5 * 10
= Rs. 22000
5. A cylindrical pipe has a radius of 4 cm and length of 2 m with a thickness of 1 cm. What will be the outer curved surface area of 3 such pipes?
a) 20900 cm2
b) 1.56 m2
c) 1.88 m2
d) 16700 cm2
View Answer
Explanation: Given,
No. = 3, r (outer) = 4 + 1 cm = 5 cm, length = 2m = 200 cm.
Outer curved surface area = No. * 2πrh
= 3 * 2 * (22 / 7) * 5 * 200
= 18,857 cm2
= 1.88 m2
6. A cylindrical vessel having radius 7 cm and height 10 cm are covered on both the ends. What will be the total curved surface area (in sq. cm) of this vessel?
a) 818
b) 645
c) 792
d) 748
View Answer
Explanation: Given,
r = 7 cm, h = 10 cm
Total curved surface area = 2πr2 + 2πrh
= 2 * (22 / 7) * 72 + 2 * (22 / 7) * 7 * 10
= 308 cm2 + 440 cm2
= 748 cm2
7. What will be the surface area (in sq. cm) of a cylindrical vessel having radius as 14 cm and height 20 cm covered at one end?
a) 2068
b) 3500
c) 1980
d) 2788
View Answer
Explanation: Given,
r = 14 cm, h = 20 cm.
Surface area = 2πrh + πr2
= 2 * (22 / 7) * 14 * 20 + (22 / 7) * 142
= 1760 cm2 + 308 cm2
= 2068 cm2
8. What will be the amount of water (in cubic cm) contained in a cylindrical cup having radius of 4 cm and height 5 cm?
a) 289.62
b) 346.92
c) 251.42
d) 324.62
View Answer
Explanation: Given,
r = 7 cm, h = 5 cm
Volume = πr2h
= (22 / 7) * 42 * 5
= 251.42 cm3
9. What is the amount of water (in cubic cm) contained in 5 similar pipes of radius 2 cm and length 150 cm?
a) 9428.57
b) 8867.52
c) 10078.56
d) 9867.52
View Answer
Explanation: Given,
No. = 5, r = 2 cm, l = 150 cm
Volume = No. * πr2l
= 5 * (22 / 7) * 22 * 150
= 9428.57 cm3
10. What is the amount contained in a cylindrical vessel having radius 8 cm and height 7 cm when it is two – third filled?
a) 938.66 cm3
b) 978.56 cm3
c) 892.46 cm3
d) 854.79 cm3
View Answer
Explanation: Given,
Two – third filled, r = 8 cm, h = 7 cm
Volume when two – third filled = 2 / 3 * πr2h
= 2 / 3 * (22 / 7) * 82 * 7
= 938.66 cm3
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