This set of Aptitude Questions and Answers (MCQs) focuses on “Average – Set 2”.

1. The monthly income of 4 members of a family are 10000, 20000, 50000 and 60000. If 2 members of the family are retired and gets a pension of 120 per day and 1 member of the family does not earn, find the average income of the family for the month of February 2020.

a) 20994.28

b) 20998.24

c) 20992.48

d) 2099.428

View Answer

Explanation: Total income of the earning members of the family = 10000 + 20000 + 50000 + 60000 = 140000

Total pension received for the month of February (29 days) = 120 * 29 = 3480 per person

Total number of members in the family = 7 (4 earning, 2 on pension and 1 who does not earn)

Total income = 140000 + 3480 + 3480 = 146960

Average income per person = 146960 / 7 = 20994.28

2. There are 40 fruits in a basket which includes banana, apple, mango and orange. If the average weight of the fruits is 60, 120, 180 and 90 grams respectively and the quantity of fruits are in a ratio of 1:2:3:4 find the total weight of fruits in the basket.

a) 3.6 kg

b) 4.2 kg

c) 3.2 kg

d) 4.6 kg

View Answer

Explanation: Total number of respective fruits:

Banana = (1 / 10) * 40 = 4

Apple = (2 / 100) * 40 = 8

Mango = (3 / 10) * 40 = 12

Orange = (4 / 10) * 40 = 16

Total weight of the fruits:

4 * 60 + 8 * 120 + 12 * 180 + 16 * 90 = 240 + 960 + 2160 + 1440 = 4600 = 4.6 kg

3. Out of 10 employees in an office 5 drink 2 cups of coffee per day, 3 drinks 3 cups of hot chocolate per day and 2 drink 5 cups of tea per day. If it is known that on an average to make a cup of coffee 100 ml of milk is used, to make a cup of hot chocolate 180 ml of milk is used and to make a cup of tea 60 ml milk is used, find the monthly expenditure on milk of the company, if milk is 46 rupees per liter.

a) 4232

b) 2342

c) 4324

d) 4432

View Answer

Explanation: Total consumption of milk per day:

Hot chocolate = 3 * 3 * 180 = 1620 ml

Coffee = 5 * 2 * 100 = 1000 ml

Tea = 2 * 5 * 60 = 600 ml

Total = 1620 + 1000 + 600 = 3200 ml per day = 3200 * 30 = 96000 ml per month = 96 liters per month

Total expenditure = 96 * 46 = 4324

4. In a group of 20 women each like to go for shopping. On an average each of them goes for shopping 12 times per year. If 5 of them moved to another society and out of the remaining 5 increased their consistency to shop by 50 % and 10 decreased their consistency to shop by 25%, how many times will they visit the shopping mall in total?

a) 240

b) 180

c) 160

d) 140

View Answer

Explanation: Total number of times they visited the shop in previous year = 12 * 20 = 240

Number of women left = 15

New consistency of the 5 women with increased shopping consistency = 12 + 50% of 12

12 + 12 * 50 / 100 = 12 + 6 = 18

New consistency of the women with decreased consistency to shop = 12 – 25% of 12

12 – 12 * 25 / 100 = 12 – 3 = 9

Total = 5 women with 0 consistency, 5 women with a consistency of 18 times per annum and 10 women with a consistency of 9 times per annum = 5 * 0 + 5 * 18 + 10 * 9 = 0 + 90 + 90 = 180

New consistency = 180 times per annum.

5. Out of 30 days of a month the income of a stall for the first 5 days was 100 per day for the next 10 days the income was 200 per day and for the last 15 days the income was 300 per day. If there was a fixed expenditure of 5000 per month and a variable expenditure of 70 per week. Find the monthly profit of the stall.

a) 1700

b) 1800

c) 1900

d) 2000

View Answer

Explanation: Total income for 30 days = 5 * 100 + 10 * 200 + 15 * 300 = 500 + 2000 + 4500 = 7000

Total expenditure = 5000 fixed expenditure per month + variable expenditure of 70 per week

Per week = 70 per day = 70 / 7 = 10

For 30 days = 30 * 10 = 300

Total variable expenditure = 5000 + 300 = 5300

Total profit = 7000 – 5300 = 1700

6. The average of 20 results is 200. If the average of the first 12 results is 250 and the average of last 7 results is 90, find the 13^{th} result.

a) 300

b) 340

c) 360

d) 370

View Answer

Explanation: The total of the results = 20 * 200 = 4000

The total of the first 12 results = 12 * 250 = 3000

The total of the last 7 results = 7 * 90 = 630

13

^{th}term = sum of 20 results – sum of first 12 results – sum of last 7 results

4000 – 3000 – 630 = 370

7. Which of the following can never be an average of 3 consecutive odd numbers?

a) 3

b) 5

c) 3.5

d) 7

View Answer

Explanation: The average of 3 consecutive odd numbers can never be a decimal because the sum of any 3 consecutive odd numbers is always divisible by 3. X + (x + 2) + (x + 4) = 3x + 6 = 3(x + 2) which is always a multiple of 3.

8. Out of 30 employees of an office, 5 are retired this year 10 got a hike of 25% and the remaining 15 had the same pay as before. If the retired employees got the same pay as pension and the initial salary of each employee was 20000 per month what is the new expenditure of the company in relation to employee’s salaries?

a) 6,00,000

b) 6,50,000

c) 7,00,000

d) 7,50,000

View Answer

Explanation: Pension of the retired employees = 5 * 20000 = 1,00,000 per month in total

Total salary of the employees with raise = 20000 + 25% of 20000 = 20000 + 25 * 20000 / 100 = 20000 + 5000 = 25000. 25000 * 10 = 2,50,000 in total

Salaries of the employees with no raise = 20000 * 15 = 3,00,000 in total

Total expenditure of the company = 1,00,000 + 2,50,000 + 3,00,000 = 6,50,000

9. In a class of 50 students 45 passed the exam with an average of 45 marks. If the average marks of the students who failed was 20, find the average marks of the entire class.

a) 42.5

b) 42

c) 32.5

d) 45.5

View Answer

Explanation: Total marks of students who passed the exam = 45 * 45 = 2025

Total marks obtained by the students who failed = 20 * 5 = 100

Total score of the class = 2025 + 100 = 2125

Average score of the class = 2125 / 50 = 42.5

10. Out of 100 students of the class 20 scored an average of 40 marks, 30 scored an average of 50 marks, 50% of the remaining scored an average of 60 marks and the rest scored 100 marks. Find the average marks scored by the students.

a) 50

b) 52

c) 55

d) 57

View Answer

Explanation: Total marks obtained:

20 * 40 = 800

30 * 40 = 1200

50% of the remaining = 50 * 50 / 100 = 25

20 * 60 = 1200

Remaining = 25. 25 * 100 = 2500

Total marks obtained = 800 + 1200 + 1200 + 2500 = 5700

Average marks = 5700 / 100 = 57

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