Probability Questions and Answers – Coins – Set 2

This set of Aptitude Questions and Answers (MCQs) focuses on “Coins – Set 2”.

1. Three unbiased coins are tossed. What are the total number of outcomes possible?
a) 16
b) 10
c) 8
d) 4
View Answer

Answer: c
Explanation:
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Thus, total number of outcomes are 8.

2. What is the correct expression for finding the total number of outcomes when n coins are tossed at a time?
a) 2n
b) n2
c) n
d) 2n/4
View Answer

Answer: a
Explanation: Given,
Number of coins = n.
Total number of possible outcomes = 2n.

3. Three unbiased coins are tossed. What is the probability of getting only one H?
a) 1/4
b) 3/8
c) 5/8
d) 1/2
View Answer

Answer: b
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (THT, HTT, TTH)
Thus, probability = 3/8.
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4. Three unbiased coins are tossed. What is the probability of getting at most one H?
a) 1/2
b) 1/4
c) 5/8
d) 3/8
View Answer

Answer: a
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (THT, HTT, TTH, TTT)
Thus, probability = 4/8 = 1/2.

5. Three unbiased coins are tossed. What is the probability of getting at most two tail?
a) 1/8
b) 5/8
c) 7/8
d) 3/8
View Answer

Answer: c
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (THT, HTT, TTH, HHH, HHT, HTH, THH)
Thus, probability = 7/8.

6. Three unbiased coins are tossed. What is the probability of getting three tail?
a) 7/8
b) 5/8
c) 3/8
d) 1/8
View Answer

Answer: d
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (TTT)
Thus, probability = 1/8.

7. Three unbiased coins are tossed. What is the probability of getting minimum two head?
a) 1/2
b) 3/4
c) 1/8
d) 7/8
View Answer

Answer: a
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (HHT, HTH, THH, HHH)
Thus, probability = 4/8 = 1/2.
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8. Three unbiased coins are tossed. What is the probability of getting same event in all the three throws?
a) 1/2
b) 1/8
c) 1/4
d) 3/8
View Answer

Answer: c
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (HHH, TTT)
Thus, probability = 2/8 = 1/4.

9. Ten unbiased coins are tossed. What are the total number of outcomes possible?
a) 1004
b) 1024
c) 1086
d) 1056
View Answer

Answer: b
Explanation: Given,
n = 10
Total number of outcomes = 2n
= 210
= 1024
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10. Three unbiased coins are tossed. What is the probability of getting complement of having a tail?
a) 3/4
b) 1/2
c) 3/8
d) 1/8
View Answer

Answer: d
Explanation: Given, coins = 3
Possible outcomes = (HHH, HHT, HTH, THH, THT, HTT, TTH, TTT)
Favorable outcomes = (HHH)
Thus, probability = 1/8.

To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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