This set of Aptitude Questions and Answers (MCQs) focuses on “Two People”.
1. When my sister was born, I was 1/10th of my father’s age. This year my sister voted for the first time and I celebrated my 22nd birthday. Find my father’s age when my sister was born.
a) 34 years
b) 37 years
c) 40 years
d) 42 years
View Answer
Explanation: My sister’s age now : She voted for the first time that means she turned 18 years old.
My present age = 22 (given)
My age 18 years before = 22 – 18 = 4 years
When my sister was born, I was 1/10th of my father’s age that means my father was 10 times of my age.
My father’s age when my sister was born = my age * 10 = 4 * 10 = 40 years
2. When my parents married their age was in a ratio 11 : 10 (father’s age : mother’s age). This year they celebrated 15th anniversary. If the total of their ages at their silver jubilee anniversary will be 113, find my father’s age now.
a) 33 years
b) 40 years
c) 42 years
d) 43 years
View Answer
Explanation: The total of my parent’s age at their silver jubilee = 113 years (given)
The total of my parent’s age when they got married = Total age after 25 years of marriage – 2 * 25
113 – 50 = 63
Total age 15 years before = 63 years
Individual age 15 years before:
Ratio of their ages then = 11 : 10
Let their ages then be in terms of x.
11x + 10x = 63
21x = 63
X = 63 / 21 = 3
Father’s age then = 11x = 11 * 3 = 33
Father’s age now = 33 + 15 = 48 years
3. My age in my sister’s wedding was half my age now. My sister’s age in her wedding was equal to my age now. If my sister got wedded 18 years back, find the ratio of my sister’s age to my age 12 years later.
a) 8 : 5
b) 7 : 4
c) 3 : 2
d) 5 : 3
View Answer
Explanation: Let my present age be x.
My age at my sister’s wedding = x / 2
My sister’s age at her wedding = my current age = x
The wedding was 18 years back that means, x – x / 2 = 18
X – x / 2 = 18
2x – x = 18 * 2
X = 18 years
My current age = 18 years
My sister’s age at her wedding = my current age = x = 18 years
My sister’s current age = 18 + 18 = 36 years
My age after 12 years = 18 + 12 = 30 years
My sisters age after 12 years = 36 + 12 = 48 years
Ratio = 48 : 30 = 8 : 5
4. Ratio of ages of 2 people is 2 : 1. After 10 years the ratio of their ages is 3 : 2. Find their current ages.
a) 10, 5
b) 12, 6
c) 18, 9
d) 20, 10
View Answer
Explanation: Let their ages b in terms of x.
Their current ages = 2x, x
Their ages 10 years later = 2x + 10, x + 10
Ratio of their ages 10 years later = 3 : 2
(2x + 10) / 3 = (x + 10) / 2
2 * (2x + 10) = 3 * (x + 10)
4x + 20 = 3x + 30
4x – 3x = 30 – 20
X = 10
Their current ages = 2x, x = 10 * 2, 10 = 20, 10
5. T and E are sisters. The ratio of their ages when their brother was born was 6 : 5. The ratio of their ages when their brother was 12 years was 10 : 9. Find the age of T when her brother got married at the age of 28.
a) 45, 42 years
b) 44, 41 years
c) 46, 43 years
d) 47, 44 years
View Answer
Explanation: Ratio of ages of T and E at the time of their brother’s birth = 6 : 5
Let these ages be in terms of x.
Their ages then = 6x, 5x
Ratio of their ages 12 years later = 10 : 9
Their ages after 12 years = 6x + 12, 5x + 12
(6x + 12) : (5x + 12) = 10 : 9
(6x + 12) / 10 = (5x + 12) / 9
9 * (6x + 12) = 10 * (5x + 12)
54x + 108 = 50x + 120
54x – 50x = 120 – 108
4x = 12
X = 12 / 4 = 3 years
Their age when brother was born = 6x, 5x = 18, 15 years
Their ages when their brother got married = Their ages at the time of brother’s birth + 28
18 + 28, 15 + 28 = 46, 43 years
To practice all aptitude questions, please visit “1000+ Quantitative Aptitude Questions”, “1000+ Logical Reasoning Questions”, and “Data Interpretation Questions”.
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