This set of Aptitude Questions and Answers (MCQs) focuses on “Simplification Word Problems – Set 3”.
1. Arun and Varun each has some money, If Arun gives Rs.10 to Varun, then Varun will have twice the money left with Arun. But, if Varun gives Rs.10 to Arun, then they both have equal amount of money. How much money does Arun have?
a) Rs.50
b) Rs.60
c) Rs.70
d) Rs.40
View Answer
Explanation: Let the money with Arun and Varun be Rs.x and Rs.y respectively.
By data, 2(x – 10) = y + 10 🡪 2x – y = 30 …… (i)
x + 10 = y – 10 🡪 x – y = -20 …… (ii)
Solving (i) and (ii), we get, x = 50 and y = 70.
Therefore, Arun has Rs.50.
2. The cost of 7 pens and 5 pencils is Rs.95. One half of the cost of one pen is equal to the cost of one pencil. What is the total cost of one pen and one pencil?
a) Rs.12
b) Rs.15
c) Rs.18
d) Rs.16
View Answer
Explanation: Let the cost of one pen and one pencil be ‘x’ and ‘y’ respectively.
By data, 7x + 5y = 95 …… (i)
And y = x/2 🡪 x – 2y = 0 …… (ii)
Solving (i) and (ii), we get, x = 10 and y = 5.
Therefore, the total cost of one pen and one pencil = 10 + 5 = Rs.15.
3. If an amount of Rs.202477 is distributed equally amongst 79 persons, how much amount would each get?
a) Rs.2653
b) Rs.2863
c) Rs.2563
d) Rs.2563
View Answer
Explanation: \(\frac{202477}{79}\)=2563.
Therefore, each person would get Rs.2563.
4. Rohan has Rs.5 more than Mohan and Rs.8 more than Sohan. All the three have Rs.47 in total. What is Rohan’s share?
a) Rs.24
b) Rs.15
c) Rs.18
d) Rs.20
View Answer
Explanation: Let the money with Rohan be Rs.x. Then, the money with Mohan and Sohan is (x-5) and (x-8) respectively.
By data, x + (x-5) + (x-8) = 47 🡪 x = 20.
Therefore, Rohan’s share is Rs.20.
5. The sum of the weights of P and Q is 168 kg. Half of the weight of P is equal to 3/8 times the weight of Q. Find the weight of Q.
a) 96 kg
b) 86 kg
c) 72 kg
d) 76 kg
View Answer
Explanation: By data, P + Q = 168 …… (i)
\(\frac{P}{2}\)=\(\frac{3Q}{8}\) 🡪 8P-6Q=0 …… (ii)
On solving (i) and (ii), we get, P = 72 and Q = 96.
Therefore, the weight of Q is 96 kg.
6. A pineapple costs Rs.13 each and a watermelon costs Rs.8 each. Ram spends Rs.157 on these fruits. How many pineapples did he purchase?
a) 8
b) 6
c) 7
d) 5
View Answer
Explanation: Let the cost of one pineapple and one watermelon be Rs.x and Rs.y respectively.
By data, 13x + 8y = 157 🡪 x=\(\frac{157-8y}{13}\).
Clearly, x is a whole number only when (157-8y) is divisible by 13. It is possible when y = 5 🡪 x = 9.
Therefore, ram purchased 9 pineapples.
7. Water boils at 212°F or 100°C and melts at 32°F or 0°C. If the temperature on a particular day is 40°C, then what is its equivalent temperature in Fahrenheit scale?
a) 112
b) 108
c) 104
d) 98
View Answer
Explanation: \(\frac{°F-32}{212-32}=\frac{°C-0}{100-0}\) 🡪 °F=\(\Big(\frac{°C}{100}*180\Big)\)+32.
When °C = 40 🡪 °F=\(\Big(\frac{40}{100}*180\Big)\)+32=104.
8. A group of 1600 people consisting of teachers and students are travelling in a train. If for every 15 students there is one teacher, then find the number of teachers in the group.
a) 80
b) 90
c) 120
d) 100
View Answer
Explanation: Let the number of teachers be x, then the number of students is 15x.
By data, x + 15x = 1600 🡪 x = 100.
Therefore, number of teachers in the group is 100.
9. A car company sold 200 cars in a special 5-day sale. Each day the company sold 8 more tan the previous day. How many cars were sold on 4th day?
a) 48
b) 40
c) 44
d) 52
View Answer
Explanation: Let the number of cars sold on 1st day be x. Then the number of cars sold on 2nd, 3rd, 4th and 5th day is (x+8), (x+16), (x+24), (x+32) and (x+40).
By data, x + (x+8) + (x+16) + (x+24) + (x+32) + (x+40) = 200 🡪 x = 16.
Therefore, the number of cars sold on 4th day is 16+32 = 48.
10. The total monthly salary of 5 men and 6 women is Rs.236000. If a man earns Rs1000 more than a woman, then what is the monthly salary of the woman?
a) Rs.22000
b) Rs.21000
c) Rs.24000
d) Rs.18000
View Answer
Explanation: Let the monthly salary of each woman be x, then the monthly salary of each man is (x+1000).
By data, 5(x+1000) + 6x = 236000 🡪 x = 21000.
Therefore, the monthly salary of the woman is Rs.21000.
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