This set of Separation Processes Questions and Answers for Aptitude test focuses on “The MSMPR Crystallization Model”.
1. In crystallization, solvent should dissolve large amount of solute at:
a) Room temperature
b) Boiling point
c) Freezing point
d) Slip melting point
View Answer
Explanation: Solvent should dissolve large amount of solute at boiling point of solvent.
2. Insoluble impurities during crystallization are removed by:
a) Decantation
b) Filtration
c) Distillation
d) Fractional crystallization
View Answer
Explanation: Since the impurities are insoluble they can be easily removed by filtration and no other methods are required.
3. The crystals obtained in crystallization are dried by:
a) Dryer
b) Oven
c) Filter paper
d) Exposing to sun
View Answer
Explanation: The moisture is sucked with the help of a filter paper and the crystals are dried.
4. Which of the following is not an assumption of MSMPR model?
a) Perfect mixing of the magma
b) No crystal breakage
c) Continuous, steady-flow, steady-state operation
d) Crystals are of various sizes.
View Answer
Explanation: The crystals are assumed to be of same size in the MSMPR model.
5. What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 5
a) 0.01
b) 0.7
c) 0.6
d) 0.8
View Answer
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=0.01.
6. What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.05
a) 0.01
b) 0.7
c) 0.6
d) 100000
View Answer
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=1000000.
7. What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.78
a) 1.56
b) 2.34
c) 2.56
d) 0.8
View Answer
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=2.56.
8. What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.56
a) 5.67
b) 6.78
c) 7.11
d) 9.56
View Answer
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=7.11.
9. What is the number of crystals per unit mass of crystals if
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.67
a) 1.56
b) 7.89
c) 4.22
d) 4.15
View Answer
Explanation: Number of crystals per unit mass of crystals= 4.5/fvρL3, hence N=4.15.
10. What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 0.5
b) 1.5
c) 1.8
d) 2.7
View Answer
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 1.8.
11. What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 0.5m3
a) 5.4
b) 3.6
c) 1.8
d) 2.7
View Answer
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 3.6.
12. What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.6
volume of mother liquor in magma V= 1m3
a) 1.45
b) 1.5
c) 1.07
d) 1.04
View Answer
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 1.04.
13. What is the nucleation rate if
Mass of production of crystals C=0.5kg
Volume shape factor fv= 0.5
Density of particle= 0.5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 0.5
b) 15
c) 1.8
d) 18
View Answer
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 18.
14. What is the nucleation rate if
Mass of production of crystals C=10kg
Volume shape factor fv= 0.5
Density of particle= 5kg/m3
Characteristic size of crystal L= 0.5
volume of mother liquor in magma V= 1m3
a) 9
b) 18
c) 180
d) 36
View Answer
Explanation: The nucleation rate=4.5C/fvρL3V, hence rate= 180.
Sanfoundry Global Education & Learning Series – Separation Processes.
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