This set of Separation Processes Question Bank focuses on “Design of Solid Liquid Cake-Filtration Devices Based on Pressure Gradients”.

1. What do the pressure filtration devices consist that remains suspended while allowing the fluid in which the solids are suspended to pass through?

a) Semipermeable membrane

b) Mesh barrier

c) No barrier

d) Column

View Answer

Explanation: The pressure filtration devices consist of Mesh barrier that remains suspended while allowing the fluid in which the solids are suspended to pass through.

2. The filtration models are based on which laws?

a) Pascals law

b) Roult’s law

c) Avogadro’s law

d) Darcy’s law

View Answer

Explanation: The filtration models are based on darcy’s law deve;oped in 1855 to describe flow of water in sand beds.

3. Which of the following is the correct representation of the darcy’s law?

a) (-k/µ)(dp/dz)

b) (-kµ)(dp/dz)

c) (k/µ)(dp/dz)

d) (kµ)(dp/dz)

View Answer

Explanation: The correct representation of the darcy’s law is (-k/µ)(dp/dz) since it is inversely proportional to the viscosity of the medium.

4. Why a pump that delivers slurry to a filtration unit at constant pressure not a positive displacement pump?

a) Because it operates at variable floe rate

b) Because it operates at constant flow rates

c) Because the time of flow is different

d) Because the time of flow is same

View Answer

Explanation: A pump that delivers slurry to a filtration unit at constant pressure not a positive displacement pump because it operates at constant flow rates.

5. If the reported filter area A= 1m^{2}

Viscosity µ = 5*10^{-4}

Pressure difference = 100

And the intercept is 500

What is the value of medium’s resistance to flow?

a) 1*10^{8}

b) 5*10^{8}

c) 6*10^{8}

d) 2.5*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=1*10

^{8}.

6. If the reported filter area A= 1m^{2}

Viscosity µ = 1*10^{-4}

Pressure difference = 100

And the intercept is 500

What is the value of medium’s resistance to flow?

a) 1*10^{8}

b) 5*10^{8}

c) 6*10^{8}

d) 2.5*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=5*10

^{8}.

7. If the reported filter area A= 1m^{2}

Viscosity µ = 5*10^{-4}

Pressure difference = 100

And the intercept is 3000

What is the value of medium’s resistance to flow?

a) 1*10^{8}

b) 5*10^{8}

c) 6*10^{8}

d) 2.5*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=6*10

^{8}.

8. If the reported filter area A= 1m^{2}

Viscosity µ = 2*10^{-4}

Pressure difference = 100

And the intercept is 500

What is the value of medium’s resistance to flow?

a) 1*10^{8}

b) 5*10^{8}

c) 6*10^{8}

d) 2.5*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=2.5*10

^{8}.

9. If the reported filter area A= 1m^{2}

Viscosity µ = 10*10^{-4}

Pressure difference = 100

And the intercept is 500

What is the value of medium’s resistance to flow?

a) 0.5*10^{8}

b) 23*10^{8}

c) 11*10^{8}

d) 5.3*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=0.5*10

^{8}.

10. If the reported filter area A= 1m^{2}

Viscosity µ = 5*10^{-4}

Pressure difference = 100

And the intercept is 700

What is the value of medium’s resistance to flow?

a) 12*10^{8}

b) 5.5*10^{8}

c) 9.5*10^{8}

d) 1.4*10^{8}

View Answer

Explanation: Since R

_{m}= ΔPA(intercept)/µ, hence R

_{m}=1.4*10

^{8}.

**Sanfoundry Global Education & Learning Series – Separation Processes.**

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