# Separation Processes Questions and Answers – Kremser Group Method

This set of Separation Processes Multiple Choice Questions & Answers (MCQs) focuses on “Kremser Group Method”.

1. Many separators are cascades where two contacting phases flow __________
a) Co-currently
b) Counter-currently
c) Same direction
d) In any direction

Explanation: Most of the cascades have contacting liquids flowing counter-currently.

2. Why the approximate calculations of composition of input and output field are called group methods?
a) Because they are found only in groups
b) Because only input-output group is there
c) Because they deal only with input-output calculation and don’t consider what exactly happens
d) It’s just a name

Explanation: The approximate calculations of composition of input and output field are called group methods because they deal only with input-output calculation and don’t consider what exactly happens.

3. If KD = 2, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3

Explanation: Since E= KDV/L, 2*100/300=0.67.

4. If KD = 2, amount of solvent (V)= 200kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1.3
c) 2.4
d) 3

Explanation: Since E= KDV/L, 2*200/300=1.33.

5. If KD = 0.5, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 0.167
d) 3

Explanation: Since E= KDV/L, 0.5*100/300=0.167.
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6. If KD = 2, amount of solvent (V)= 100kg and amount of feed liquid is 100, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3

Explanation: Since E= KDV/L, 2*100/100=2.

7. If KD = 0.5, amount of solvent (V)= 500kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1.33
c) 2
d) 0.833

Explanation: Since E= KDV/L, 0.5*500/300=0.833.

8. If KD = 3, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 2
d) 3

Explanation: Since E= KDV/L, 3*100/300=1.

9. If KD = 2.5, amount of solvent (V)= 100kg and amount of feed liquid is 100, what is the extraction factor?
a) 0.67
b) 1
c) 2.5
d) 3

Explanation: Since E= KDV/L, 2*100/300=0.67.

10. If KD = 1, amount of solvent (V)= 100kg and amount of feed liquid is 300, what is the extraction factor?
a) 0.67
b) 1
c) 1.33
d) 0.33

Explanation: Since E= KDV/L, 1*100/300=0.33.

Sanfoundry Global Education & Learning Series – Separation Processes.

To practice all areas of Separation Processes, here is complete set of 1000+ Multiple Choice Questions and Answers.

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