Separation Processes Questions and Answers – Melt Crystallization

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This set of Separation Processes Multiple Choice Questions & Answers (MCQs) focuses on “Melt Crystallization”.

1. What is the definition of melt crystallization?
a) Crystallization of melts from eutectic-forming or solid solution forming mixtures
b) Crystallization of melts from eutectic-forming or liquid solution forming mixtures
c) Crystallization of melts from eutectic-forming or constant boiling mixtures
d) Crystallization at very high temperatures

Explanation: Crystallization of melts from eutectic-forming or solid solution forming mixtures is called as melt crystallization.

2. What are the two major methods for melt crystallization?
a) Suspension, layer
b) Layer, multilayer
c) Suspension, colloidal
d) Layer, non-layer

Explanation: The two types of melt crystallization are suspension crystallization and melt crystallization.

3. If Kc=10
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=2
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 20
b) 22.4
c) 25.6
d) 27.8

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 22.4.

4. If Kc=10
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=4
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 14.6
b) 15.63
c) 15.81
d) 27.2

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 15.81.

5. If Kc=10
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=2
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 12.9
b) 15.7
c) 19.5
d) 27.8

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 12.9.

6. If Kc=20
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=2
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 25.6
b) 29.4
c) 31.6
d) 72.5

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 31.6.

7. If Kc=30
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=2
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 31.6
b) 34.6
c) 36.7
d) 38.7

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 38.7.

8. If Kc=20
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=4
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 20
b) 22.4
c) 25.6
d) 27.8

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 22.4.

9. If Kc=40
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=2
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 34.6
b) 39.6
c) 44.7
d) 78.4

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 44.7.

10. If Kc=30
Temperature difference Tm-Tc=50
Time taken = 3000s
Density d=4
Rate of heat released by freezing =1000
Calculate the crystal thickness
a) 20
b) 22.4
c) 25.6
d) 27.38

Explanation: Since crystal thickness= sqrt(2*( Tm-Tc)Kct/dH), hence crystal thickness= 27.38.

Sanfoundry Global Education & Learning Series – Separation Processes.

To practice all areas of Separation Processes, here is complete set of 1000+ Multiple Choice Questions and Answers.