This set of Mathematics Assessment Questions for IIT JEE Exam focuses on “Probability – Random Experiments-2”.

1. If n coins are tossed simultaneously what is the total number of outcomes?

a) 2^{n-2}

b) 2^{n-1}

c) 2^{n}

d) 2^{n+1}

View Answer

Explanation: If n coins are tossed simultaneously total number of possible outcomes are 2

^{n}.

For 2 coins, it is 4. For 3 coins it is 8 etc.

2. If four dice are rolled simultaneously then what is the total number of possible outcomes?

a) 6

b) 36

c) 216

d) 1296

View Answer

Explanation: If four dice are rolled simultaneously then total number of possible outcomes is 6

^{4}=1296.

3. If two dice are simultaneously rolled then what is probability of getting sum 4?

a) 1/6

b) 1/4

c) 1/12

d) 1/9

View Answer

Explanation: If two dice are simultaneously rolled then total number of possible outcomes is 6*6 =36.

We can get 4 as sum in these cases {(1,3), (2,2), (3,1)}. So, probability of getting sum 4 is 3/36 = 1/12.

4. If two dice are simultaneously rolled then what is probability of getting sum 11?

a) 1/6

b) 1/4

c) 1/9

d) 1/18

View Answer

Explanation: If two dice are simultaneously rolled then total number of possible outcomes is 6*6 =36.

We can get 11 as sum in these cases {(5,6), (6,5)}. So, probability of getting sum 11 is 2/36 = 1/18.

5. A coin is tossed and a dice is rolled simultaneously what is total number of possible outcomes?

a) 2

b) 6

c) 12

d) 24

View Answer

Explanation: If a coin is tossed and a dice is rolled simultaneously then total number of possible outcomes will be 2*6 =12.

6. A coin is tossed and if head come then a red dice is rolled and if tail come then a blue dice is rolled then what is the possible number of outcomes?

a) 6

b) 12

c) 24

d) 72

View Answer

Explanation: If head come on coin then red dice can have 6 outcomes so total 1*6 = 6 outcomes. And if tail come on coin then blue dice can have 6 outcomes so total 1*6 = 6 outcomes.

So, total number of possible outcomes = 6 + 6 = 12.

7. If 4 bulbs are there each of which can be defective or non-defective then what is the total number of possible outcomes?

a) 8

b) 16

c) 4

d) 2

View Answer

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 2

^{4}= 16.

8. If 4 bulbs are there each of which can be defective or non-defective then what is the probability that all the bulbs are defective?

a) 1/8

b) 1/16

c) 1/4

d) 1/2

View Answer

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 2

^{4}= 16.

So, the probability that all the bulbs are defective is 1/16.

9. If 4 bulbs are there each of which can be defective or non-defective then what is the probability that at least one bulb is non- defective?

a) 7/8

b) 15/16

c) 3/4

d) 1/2

View Answer

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 2

^{4}= 16.

Probability that all the bulbs are defective is 1/16.

So, the probability that at least one bulb is non-defective is 1-1/16 = 15/16.

10. The probability can be negative.

a) True

b) False

View Answer

Explanation: Since probability is the ratio of number of outcomes in favour to total number of possible outcomes and number (counting) cannot be negative so, probability cannot be negative.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 11**.

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