# Mathematics Questions and Answers – Probability – Random Experiments-2

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This set of Mathematics Assessment Questions for IIT JEE Exam focuses on “Probability – Random Experiments-2”.

1. If n coins are tossed simultaneously what is the total number of outcomes?
a) 2n-2
b) 2n-1
c) 2n
d) 2n+1

Explanation: If n coins are tossed simultaneously total number of possible outcomes are 2n.
For 2 coins, it is 4. For 3 coins it is 8 etc.

2. If four dice are rolled simultaneously then what is the total number of possible outcomes?
a) 6
b) 36
c) 216
d) 1296

Explanation: If four dice are rolled simultaneously then total number of possible outcomes is 64=1296.

3. If two dice are simultaneously rolled then what is probability of getting sum 4?
a) 1/6
b) 1/4
c) 1/12
d) 1/9

Explanation: If two dice are simultaneously rolled then total number of possible outcomes is 6*6 =36.
We can get 4 as sum in these cases {(1,3), (2,2), (3,1)}. So, probability of getting sum 4 is 3/36 = 1/12.

4. If two dice are simultaneously rolled then what is probability of getting sum 11?
a) 1/6
b) 1/4
c) 1/9
d) 1/18

Explanation: If two dice are simultaneously rolled then total number of possible outcomes is 6*6 =36.
We can get 11 as sum in these cases {(5,6), (6,5)}. So, probability of getting sum 11 is 2/36 = 1/18.

5. A coin is tossed and a dice is rolled simultaneously what is total number of possible outcomes?
a) 2
b) 6
c) 12
d) 24

Explanation: If a coin is tossed and a dice is rolled simultaneously then total number of possible outcomes will be 2*6 =12.

6. A coin is tossed and if head come then a red dice is rolled and if tail come then a blue dice is rolled then what is the possible number of outcomes?
a) 6
b) 12
c) 24
d) 72

Explanation: If head come on coin then red dice can have 6 outcomes so total 1*6 = 6 outcomes. And if tail come on coin then blue dice can have 6 outcomes so total 1*6 = 6 outcomes.
So, total number of possible outcomes = 6 + 6 = 12.

7. If 4 bulbs are there each of which can be defective or non-defective then what is the total number of possible outcomes?
a) 8
b) 16
c) 4
d) 2

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 24 = 16.

8. If 4 bulbs are there each of which can be defective or non-defective then what is the probability that all the bulbs are defective?
a) 1/8
b) 1/16
c) 1/4
d) 1/2

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 24 = 16.
So, the probability that all the bulbs are defective is 1/16.

9. If 4 bulbs are there each of which can be defective or non-defective then what is the probability that at least one bulb is non- defective?
a) 7/8
b) 15/16
c) 3/4
d) 1/2

Explanation: Each bulb can have two cases i.e. either defective or non-defective. Then total number of outcomes will be 24 = 16.
Probability that all the bulbs are defective is 1/16.
So, the probability that at least one bulb is non-defective is 1-1/16 = 15/16.

10. The probability can be negative.
a) True
b) False

Explanation: Since probability is the ratio of number of outcomes in favour to total number of possible outcomes and number (counting) cannot be negative so, probability cannot be negative.

Sanfoundry Global Education & Learning Series – Mathematics – Class 11.

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