This set of Class 8 Maths Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Mensuration – Surface Area of a Cube, Cuboid and Cylinder”.

1. Find the surface area of the given cuboid.

a) 44 cm^{2}

b) 22 cm^{2}

c) 40 cm^{2}

d) 88 cm^{2}

View Answer

Explanation: Surface area cuboid = 2(lb + bh + lh) = 2(6 × 4 + 4 × 2 + 2 × 6) = 88 cm

^{2}.

2. What is the surface area of the given cube?

a) 46 cm^{2}

b) 96 cm^{2}

c) 48 cm^{2}

d) 92 cm^{2}

View Answer

Explanation: Surface area cube = 6 a

^{2}= 6 (4

^{2}) = 96 cm

^{2}.

3. Find the surface area of the given cylinder.

a) 113.14 cm^{2}

b) 113.16 cm^{2}

c) 112.16 cm^{2}

d) 112.14 cm^{2}

View Answer

Explanation: Curved Surface area of cylinder = 2πrh + 2πr

^{2}= 2πr(r + h) = 2 × \(\frac{22}{7}\) × 2(2 + 7)

= 113.14 cm

^{2}.

4. A gift in the form of cube has to be wrapped with gift paper whose external measures are 15 cm. Find the area of gift paper needed.

a) 1250 cm^{2}

b) 1354 cm^{2}

c) 1350 cm^{2}

d) 1150 cm^{2}

View Answer

Explanation: Surface area cube = 6 a

^{2}= 6 (15

^{2}) = 1350 cm

^{2}.

5. The internal measurement of a cuboidal room 15m × 6m × 4m.The room has to be painted along with the ceiling. If cost of painting is Rs 17 per m^{2}, Find the total cost to be paid.

a) Rs 4916

b) Rs 3916

c) Rs 4686

d) Rs 4386

View Answer

Explanation: Surface area cuboid = 2(lb + bh + lh)

The floor of the room will not be painted.

∴ Surface area to be painted = 2(lb + bh + lh) – lb

= 2(15 × 6 + 4 × 6 + 4 × 15) – 15 × 6 = 258 m

^{2}

Total cost to be paid = 258 × 17 = Rs 4386.

6. A building has 6 cylindrical pillars whose radius is 2m and height is 12m. Each pillar has to be painted and the cost of painting is Rs 22 per meter sq. Find the cost of painting the curved surface area of the 6 pillars.

a) Rs. 3872

b) Rs. 13232

c) Rs. 7744

d) Rs. 23232

View Answer

Explanation: Curved Surface area of cylinder = 2πrh + 2πr

^{2}= 2πr(r + h) = 2 × \(\frac{22}{7}\) × 2(2 + 12)

= 176 m

^{2}

The total cost of painting 1 pillar = 176 × 22 = Rs. 3872.

The total cost of painting 6 pillars = 3872 × 6 = Rs. 23232.

7. Find the side of the cube whose surface area is 384m^{2}.

a) 5 m

b) 6 m

c) 8 m

d) 7 m

View Answer

Explanation: Surface area cube = 6 a

^{2}

⇒ 384 = 6 (a

^{2})

⇒ a = 8 m.

8. If the surface area of a cuboid is 108 cm^{2}, find the height of the cuboid. The length and breadth the cuboid is 6 and 3 cm respectively.

a) 8 cm

b) 4 cm

c) 2cm

d) 6 cm

View Answer

Explanation: Surface area cuboid = 2(lb + bh + lh)

⇒ 108 = 2(3 × 6 + h × 6 + h × 3)

⇒ h = 4 cm.

9. The curved surface of the cylinder is 88 cm^{2}. The height of the cylinder is 5 m, what is the radius of the cylinder?

a) 6 cm

b) 4 cm

c) 1 cm

d) 2 cm

View Answer

Explanation: Curved Surface area of cylinder = 2πrh + 2πr

^{2}= 2πr(r + h)

⇒ 88 = 2 × \(\frac{22}{7}\) × r(r + 5)

⇒ \(\frac{88×7}{2×22}\) = r(r+5).

⇒ 14 = r (r+5)

⇒ r = 2 cm.

10. Match the pairs.

A | B |
---|---|

1) |
a) 96 cm^{2} |

2) |
b) 132 cm^{2} |

3) |
c) 28 cm^{2} |

a) 1-c, 2-a, 3-b

b) 1-c, 2-a, 3-a

c) 1-c, 2-b, 3-b

d) 1-c, 2-b, 3-a

View Answer

Explanation: Surface area cuboid = 2(lb + bh + lh) = 2(1 × 4 + 4 × 2 + 2 × 1) = 28 cm

^{2}

Surface area cube = 6 a

^{2}= 6 (4

^{2}) = 96 cm

^{2}

Curved Surface area of cylinder = 2πrh + 2πr

^{2}= 2πr(r + h) = 2 × \(\frac{22}{7}\) × 3(3 + 4)

= 132 cm

^{2}.

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