Separation Processes Questions and Answers – Equilibrium Stage Model for Leaching and Washing

This set of Separation Processes online test focuses on “Equilibrium Stage Model for Leaching and Washing”.

1. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.2295
Calculate the number of ideal countercurrent washing stages required.
a) 2.5
b) 2.6
c) 2.8
d) 2.95
View Answer

Answer: d
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 2.95.

2. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.35
Calculate the number of ideal countercurrent washing stages required.
a) 2.5
b) 4.1
c) 2.2
d) 6.14
View Answer

Answer: b
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 4.1.

3. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.1165
Calculate the number of ideal countercurrent washing stages required.
a) 2.0
b) 2.6
c) 2.8
d) 2.95
View Answer

Answer: a
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 2.0.
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4. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.55
Calculate the number of ideal countercurrent washing stages required.
a) 4.6
b) 6.4
c) 7.2
d) 2.95
View Answer

Answer: c
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 7.2.

5. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.256
Calculate the number of ideal countercurrent washing stages required.
a) 3.18
b) 2.6
c) a)8
d) 3.67
View Answer

Answer: d
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 3.18.

6. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.318
Calculate the number of ideal countercurrent washing stages required.
a) 2.5
b) 2.6
c) 3.8
d) 3.18
View Answer

Answer: c
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 3.8.

7. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.108
Calculate the number of ideal countercurrent washing stages required.
a) 6.13
b) 2.45
c) 1.95
d) 2.95
View Answer

Answer: c
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 1.94.
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8. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.44
Calculate the number of ideal countercurrent washing stages required.
a) 2.5
b) 5.3
c) 5.4
d) 5.5
View Answer

Answer: b
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 5.3.

9. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.24
Calculate the number of ideal countercurrent washing stages required.
a) 3.0
b) 3.7
c) 2.8
d) 3.95
View Answer

Answer: a
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 3.0.
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10. If YN+1= 0.0005
XN= 0.001
Y2= 0.01174
YL=XL= 0.05
L/V= 0.29
Calculate the number of ideal countercurrent washing stages required.
a) 3.5
b) 3.6
c) 3.8
d) 3.95
View Answer

Answer: a
Explanation: N= log(XN-YN+1/YL-Y2)/log(L/V), hence N= 3.5.

Sanfoundry Global Education & Learning Series – Separation Processes.

To practice all areas of Separation Processes for online tests, here is complete set of 1000+ Multiple Choice Questions and Answers.

If you find a mistake in question / option / answer, kindly take a screenshot and email to [email protected]

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He lives in Bangalore, and focuses on development of Linux Kernel, SAN Technologies, Advanced C, Data Structures & Alogrithms. Stay connected with him at LinkedIn.

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