This set of Soil Mechanics Multiple Choice Questions & Answers (MCQs) focuses on “Determination of Coefficient of Consolidation – 1”.

1. The coefficient of consolidation can be determined by comparing characteristics of _______

a) time factor T_{v} and degree of consolidation U

b) degree of consolidation U and pore pressure u

c) pore pressure u and effective pressure σ’

d) effective pressure σ’ and total pressure σ

View Answer

Explanation: The coefficient of consolidation can be determined by comparing characteristics of the theoretical relationship between time factor T

_{v}and degree of consolidation U to the relationship between the elapsed time and degree of consolidation of specimen as obtained in the laboratory.

2. The coefficient of consolidation can be found by _____________

a) square root of time fitting method only

b) logarithm of time fitting method only

c) both square root of time fitting and logarithm of time fitting method

d) no method is available

View Answer

Explanation: Out of the many methods available, the two important methods are:

- square root of time fitting method
- logarithm of time fitting method.

3. The square root of time fitting method the theoretical graph is plotted between _____

a) \(\sqrt{T_v}\) is abscissa and U is ordinate

b) U is abscissa and \(\sqrt{T_v}\) is abscissa

c) Tv is abscissa and U is ordinate

d) \(\sqrt[3]{T_v}\) is abscissa and U is ordinate

View Answer

Explanation: The square root of time fitting method the theoretical graph is plotted between \(\sqrt{T_v}\) as abscissa and U as ordinate.

4. The curve is straight up to _______________

a) U = 60%

b) U = 65%

c) U = 70%

d) U = 55%

View Answer

Explanation: The square root of time fitting method the theoretical graph is plotted between \(\sqrt{T_v}\) as abscissa and U as ordinate and the curve is straight is up to U = 60%.

5. The abscissa at U=90% is roughly equal to ________ times the abscissa at U=60%.

a) 0

b) 1.10

c) 1.15

d) 1.00

View Answer

Explanation: The abscissa at U=90% is roughly equal to 1.15 times the abscissa at U=60%. It is represented in the diagram.

b/a=1.15.

6. The use of square root of fitting method was suggested by ________

a) Terzaghi

b) Taylor

c) Darcy

d) Skempton

View Answer

Explanation: The use of square root of fitting method was suggested by Taylor in 1948. Darcy did his research in the permeability of soils. Skempton is Known for his pore pressure coefficients A and B.

7. From the practical data, in square root of time fitting, ______ curve is plotted.

a) time t in abscissa and dial reading R in Ordinate

b) t^{2} in abscissa and dial reading R in Ordinate

c) root of time √t in abscissa and dial reading R in Ordinate

d) t^{3} in abscissa and dial reading R in Ordinate

View Answer

Explanation: From the practical data, in square root of time fitting, root of time √t in abscissa and dial reading R in Ordinate curve is plotted. The dial reading represents the compression of the specimen.

8. In the graph, point R_{c} represents ________

a) initial consolidation

b) corrected zero reading

c) secondary consolidation

d) initial zero reading

View Answer

Explanation: When the straight portion of the line is produced back to meet the ordinate, then the reading in the ordinate corresponding to the intersection of the line, it is known as corrected zero reading.

9. The consolidation between R_{o} and R_{c} is called ______________

a) initial consolidation

b) corrected zero reading

c) secondary consolidation

d) initial zero reading

View Answer

Explanation: The consolidation between R

_{o}and R

_{c}is called initial consolidation. Iinitial consolidation is when a load is applied to a partially saturated soil, a decrease in volume occurs due to expulsion and compression of air in the voids. A small decrease in volume occurs due to compression of solid particles.

10. The coefficient of consolidation from square root of time fitting method is calculated from the equation _________

a) \(c_v=\frac{(T_v)_{90} d^2}{t_{90}} \)

b) \(c_v=\frac{(t_{90})_{90} d^2}{T_{90}} \)

c) \(c_v=\frac{(T_v)_{90} d}{T_{90}} \)

d) \(c_v=\frac{(T_v)_{90} d^3}{t_{90}} \)

View Answer

Explanation: The coefficient of consolidation is calculated from the equation of,

\(c_v=\frac{(T_v)_{90} d^2}{t_{90}}, \)

where, c

_{v}=coefficient of consolidation

(T

_{v})

_{90}=time factor corresponding to 90% consolidation

t

_{90}=elapsed time for 90% consolidation

d=average drainage path for pressure increment.

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