This set of Class 8 Maths Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Mensuration”. These MCQs are created based on the latest CBSE syllabus and the NCERT curriculum, offering valuable assistance for exam preparation.
1. Find the area of the given rectangle.
a) 16 cm2
b) 100 cm2
c) 625 cm2
d) 50 cm2
View Answer
Explanation: Area of rectangle = l × b = 25 × 4 = 100 cm2.
2. Calculate the area of the given figure.
a) 150cm2
b) 125cm2
c) 225cm2
d) 100cm2
View Answer
Explanation: Area of square = (s)2 = (15)2 = 225cm2.
3. Find the area of the given figure.
a) 20cm2
b) 50cm2
c) 15cm2
d) 25cm2
View Answer
Explanation: Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 10 × 5 = 25cm2.
4. What is the area of the given circle? (π = 3.14)
a) 78.5cm2
b) 78cm2
c) 76.5cm2
d) 77cm2
View Answer
Explanation: Area of circle = π(r)2 = 3.14(5)2 = 78.5cm2.
5. Find the area of the given parallelogram.
a) 142cm2
b) 284cm2
c) 144cm2
d) 288cm2
View Answer
Explanation: Area of parallelogram = b × h = 12 × 24 = 288cm2.
6. Match the following: (π = \(\frac{22}{7}\))
| A (Figuers) | B (Area) |
|---|---|
i) |
a) 616cm2 |
ii) |
b) 143cm2 |
iii) |
c) 121cm2 |
iv) |
d) 5cm2 |
a) i – c; ii – d; iii – b; iv – d
b) i – c; ii – d; iii – b; iv – b
c) i – c; ii – d; iii – b; iv – c
d) i – c; ii – d; iii – b; iv – a
View Answer
Explanation: i) Area of parallelogram = b × h = 11 × 11 = 121cm2
ii) Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 2 × 5 = 5cm2
iii) Area of rectangle = l × b = 11 × 13 = 143cm2
iv) Area of circle = π(r)2 = \(\frac{22}{7}\) (14)2 = 616cm2.
7. Which of the following option is correct if a,b and c are the areas of the given figures (i), (ii) and (iii) respectively? (π = 22/7)
a) a < b < c
b) a > b > c
c) a < b > c
d) b < c > a
View Answer
Explanation: Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 2 × 5 = 5cm2
Area of rectangle = l × b = 5 × 2 = 10cm2
Area of circle = π(r)2 = \(\frac{22}{7}\) (7)2 = 154cm2.
8. Find the area of the given figure.
a) 15.7cm2
b) 31.4cm2
c) 314cm2
d) 157cm2
View Answer
Explanation: Area of semicircle = π \(\frac{(r)^2}{2}\) = 3.14(10)2/2 = 314/2 cm2 = 157 cm2.
9. Find the area of the Lawn.
a) 500m2
b) 101m2
c) 505m2
d) 504m2
View Answer
Explanation: Area of lawn can be found by subtracting the area of inner rectangle from square.
Hence, Area of lawn = Area of square – Area of rectangle = (25)2 – (15)(8) = 505m2.
10. Calculate the area of the given figure.
a) 14.28cm2
b) 12.28cm2
c) 7.14cm2
d) 15cm2
View Answer
Explanation: Area of the given figure = Area of semicircle – Area of triangle = π \(\frac{(r)^2}{2} + \frac{1}{2}\) × b × h
= π\(\frac{(2)^2}{2} + \frac
{1}{2}\) × 4 × 4 = 14.28cm2.
More MCQs on Class 8 Maths Chapter 11:
- Chapter 11 – Mensuration MCQ (Set 2)
- Chapter 11 – Mensuration MCQ (Set 3)
- Chapter 11 – Mensuration MCQ (Set 4)
- Chapter 11 – Mensuration MCQ (Set 5)
To practice all chapters and topics of class 8 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.
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