Class 8 Maths Chapter 11 Mensuration MCQ

This set of Class 8 Maths Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Mensuration”. These MCQs are created based on the latest CBSE syllabus and the NCERT curriculum, offering valuable assistance for exam preparation.

1. Find the area of the given rectangle.

a) 16 cm²
b) 100 cm²
c) 625 cm²
d) 50 cm²
View Answer

Answer: b
Explanation: Area of rectangle = l × b = 25 × 4 = 100 cm².

2. Calculate the area of the given figure.

a) 150cm²
b) 125cm²
c) 225cm²
d) 100cm²
View Answer

Answer: c
Explanation: Area of square = (s)² = (15)² = 225cm².

3. Find the area of the given figure.

a) 20cm²
b) 50cm²
c) 15cm²
d) 25cm²
View Answer

Answer: d
Explanation: Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 10 × 5 = 25cm².

4. What is the area of the given circle? (π = 3.14)

a) 78.5cm²
b) 78cm²
c) 76.5cm²
d) 77cm²
View Answer

Answer: a
Explanation: Area of circle = π(r)² = 3.14(5)² = 78.5cm².

5. Find the area of the given parallelogram.

a) 142cm²
b) 284cm²
c) 144cm²
d) 288cm²
View Answer

Answer: d
Explanation: Area of parallelogram = b × h = 12 × 24 = 288cm².

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6. Match the following: (π = \(\frac{22}{7}\))

A (Figuers)	B (Area)
i)	a) 616cm²
ii)	b) 143cm²
iii)	c) 121cm²
iv)	d) 5cm²

a) i – c; ii – d; iii – b; iv – d
b) i – c; ii – d; iii – b; iv – b
c) i – c; ii – d; iii – b; iv – c
d) i – c; ii – d; iii – b; iv – a
View Answer

Answer: d
Explanation: i) Area of parallelogram = b × h = 11 × 11 = 121cm²
ii) Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 2 × 5 = 5cm²
iii) Area of rectangle = l × b = 11 × 13 = 143cm²
iv) Area of circle = π(r)² = \(\frac{22}{7}\) (14)² = 616cm².

7. Which of the following option is correct if a,b and c are the areas of the given figures (i), (ii) and (iii) respectively? (π = 22/7)

a) a < b < c
b) a > b > c
c) a < b > c
d) b < c > a
View Answer

Answer: a
Explanation: Area of triangle = \(\frac{1}{2}\) × b × h = \(\frac{1}{2}\) × 2 × 5 = 5cm²
Area of rectangle = l × b = 5 × 2 = 10cm²
Area of circle = π(r)² = \(\frac{22}{7}\) (7)² = 154cm².

8. Find the area of the given figure.

a) 15.7cm²
b) 31.4cm²
c) 314cm²
d) 157cm²
View Answer

Answer: d
Explanation: Area of semicircle = π \(\frac{(r)^2}{2}\) = 3.14(10)²/2 = 314/2 cm² = 157 cm².

9. Find the area of the Lawn.

a) 500m²
b) 101m²
c) 505m²
d) 504m²
View Answer

Answer: c
Explanation: Area of lawn can be found by subtracting the area of inner rectangle from square.
Hence, Area of lawn = Area of square – Area of rectangle = (25)² – (15)(8) = 505m².

10. Calculate the area of the given figure.

a) 14.28cm²
b) 12.28cm²
c) 7.14cm²
d) 15cm²
View Answer

Answer: a
Explanation: Area of the given figure = Area of semicircle – Area of triangle = π \(\frac{(r)^2}{2} + \frac{1}{2}\) × b × h
= π\(\frac{(2)^2}{2} + \frac
{1}{2}\) × 4 × 4 = 14.28cm².

More MCQs on Class 8 Maths Chapter 11:

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