This set of Class 12 Maths Chapter 9 Multiple Choice Questions & Answers (MCQs) focuses on “General and Particular Solutions of Differential Equation”.
1. Which of the following functions is the solution of the differential equation \(\frac{dy}{dx}\)+2y=0?
a) y=-2e-x
b) y=2ex
c) y=e-2x
d) y=e2x
View Answer
Explanation: Consider the function y=e-2x
Differentiating both sides w.r.t x, we get
\(\frac{dy}{dx}=-2e^{-2x}\)
\(\frac{dy}{dx}\)=-2y
⇒\(\frac{dy}{dx}\)+2y=0.
2. The function y=8 sin2x is a solution of the differential equation \(\frac{d^2 y}{dx^2}\)+4y=0.
a) True
b) False
View Answer
Explanation: The given statement is true.
Consider the function y=8 sin2x
Differentiating w.r.t x, we get
\(\frac{dy}{dx}\)=16 cos2x –(1)
Differentiating (1) w.r.t x, we get
\(\frac{d^2 y}{dx^2}\)=-32 sin2x
\(\frac{d^2 y}{dx^2}\)=-4(8 sin2x )=-4y
⇒\(\frac{d^2 y}{dx^2}\)+4y=0.
3. Which of the following functions is a solution for the differential equation xy’-y=0?
a) y=4x
b) y=x2
c) y=-4x
d) y=2x
View Answer
Explanation: Consider the function y=2x
Differentiating w.r.t x, we get
y’=\(\frac{dy}{dx}\)=2
Substituting in the equation xy’-y, we get
xy’-y=x(2)-2x=2x-2x=0
Therefore, the function y=2x is a solution for the differential equation xy’-y=0.
4. Which of the following differential equations has the solution y=3x2?
a) \(\frac{d^2 y}{dx^2}\)-6x=0
b) \(\frac{dy}{dx}\)-3x=0
c) x \(\frac{d^2 y}{dx^2}\)–\(\frac{dy}{dx}\)=0
d) \(\frac{d^2 y}{dx^2}-\frac{3dy}{dx}\)=0
View Answer
Explanation: Consider the function y=3x2
Differentiating w.r.t x, we get
\(\frac{dy}{dx}\)=6x –(1)
Differentiating (1) w.r.t x, we get
\(\frac{d^2 y}{dx^2}\)=6
∴\(\frac{xd^2 y}{dx^2}-\frac{6dy}{dx}\)=6x-6x=0
Hence, the function y=3x2 is a solution for the differential equation x \(\frac{d^2 y}{dx^2}\)–\(\frac{dy}{dx}\)=0.
5. Which of the following functions is a solution for the differential equation y”+6y=0?
a) y=5 cos3x
b) y=5 tan3x
c) y=cos3x
d) y=6 cos3x
View Answer
Explanation: Consider the function y=5 cos3x
Differentiating w.r.t x, we get
y’=\(\frac{dy}{dx}\)=-15 sin3x
Differentiating again w.r.t x, we get
y”=\(\frac{d^2 y}{dx^2}\)=-30 cos3x
⇒y”+6y=0.
Hence, the function y=5 cos3x is a solution for the differential equation y”+6y=0.
6. Which of the following functions is a solution for the differential equation \(\frac{dy}{dx}\)-14x=0?
a) y=7x2
b) y=7x3
c) y=x7
d) y=14x
View Answer
Explanation: Consider the function y=7x2
Differentiating w.r.t x, we get
\(\frac{dy}{dx}\)=14x
∴\(\frac{dy}{dx}\)-14x=0
Hence, the function y=7x2 is a solution for the differential equation \(\frac{dy}{dx}\)-14x=0
7. Which of the following differential equations given below has the solution y=logx?
a) \(\frac{d^2 y}{dx^2}\)-x=0
b) \(\frac{d^2 y}{dx^2}+(\frac{dy}{dx})^2\)=0
c) \(\frac{d^2 y}{dx^2}\)–\(\frac{dy}{dx}\)=0
d) x \(\frac{d^2 y}{dx^2}\)-logx=0
View Answer
Explanation: Consider the function y=logx
Differentiating w.r.t x, we get
\(\frac{dy}{dx}=\frac{1}{x} \)–(1)
Differentiating (1) w.r.t x, we get
\(\frac{d^2 y}{dx^2}=-\frac{1}{x^2} \)
∴\(\frac{d^2 y}{dx^2}+(\frac{dy}{dx})^2=-\frac{1}{x^2}+(\frac{1}{x})^2\)
=-\(\frac{1}{x^2}+\frac{1}{x^2}\)=0.
8. How many arbitrary constants will be there in the general solution of a second order differential equation?
a) 3
b) 4
c) 2
d) 1
View Answer
Explanation: The number of arbitrary constants in a general solution of a nth order differential equation is n.
Therefore, the number of arbitrary constants in the general solution of a second order D.E is 2.
9. The number of arbitrary constants in a particular solution of a fourth order differential equation is __________________
a) 1
b) 0
c) 4
d) 3
View Answer
Explanation: The number of arbitrary constants for a particular solution of nth order differential equation is always zero.
10. The function y=3 cosx is a solution of the function \(\frac{d^2 y}{dx^2}-3\frac{dy}{dx}\)=0.
a) True
b) False
View Answer
Explanation: The given statement is false.
Given differential equation: \(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=0 –(1)
Consider the function y=3 cosx
Differentiating w.r.t x, we get
\(\frac{dy}{dx}\)=-3 sinx
Differentiating again w.r.t x, we get
\(\frac{d^2 y}{dx^2}\)=-3 cosx
Substituting the values of \(\frac{dy}{dx}\) and \(\frac{d^2 y}{dx^2}\) in equation (1), we get
\(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=-3 cosx-3(-3 sinx)
=9 sinx-3 cosx≠0.
Hence, y=3 cosx, is not a solution of the equation \(\frac{d^2 y}{dx^2}\)-3 \(\frac{dy}{dx}\)=0.
Sanfoundry Global Education & Learning Series – Mathematics – Class 12.
To practice all chapters and topics of class 12 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.
