Mathematics Questions and Answers – Laws of Exponents

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Laws of Exponents”.

1. Find the value of \(\frac{1}{8^{-2}}\).
a) \(\frac{1}{16}\)
b) \(\frac{1}{64}\)
c) 16
d) 64
View Answer

Answer: d
Explanation: \(\frac{1}{a^{-m}}\) = am
⇒ \(\frac{1}{8^{-2}}\) = 82 = 64.
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2. What is 2-3?
a) \(\frac{1}{4}\)
b) \(\frac{1}{8}\)
c) 4
d) 8
View Answer

Answer: b
Explanation: a-m = \(\frac{1}{a^m}\)
⇒ 2-3 = \(\frac{1}{2^3}\) = \(\frac{1}{8}\).

3. Find the value of 16-2 × 1614.
a) 1612
b) 16-12
c) 1614
d) 16-14
View Answer

Answer: a
Explanation: am × an = am + n
⇒ 16-2 × 1614 = 16-2 + 14 = 1612.
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4. Evaluate \((\frac{21^{29}}{21^5})\).
a) 2125
b) 21-25
c) 2124
d) 21-24
View Answer

Answer: c
Explanation: \(\frac{a^m}{a^n}\) = am – n
⇒ \((\frac{21^{29}}{21^5})\) = 2129 – 5 = 2124.

5. Match the pairs.

A B
1) 23 × 83 a. 1
2) \(\frac{8^3}{2^3}\) b. 163
3) (23)0 c. 43
d. 8
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a) 1-b, 2-c, 3-d
b)1-b, 2-c, 3-a
c) 1-c, 2-b, 3-a
d) 1-c, 2-b, 3-d
View Answer

Answer: b
Explanation: am × bm = (ab)m
⇒ 23 × 83 = (2 × 8)3 = 163
Now, \(\frac{a^m}{b^m} = (\frac{a}{b})^m\)
⇒ (\(\frac{8}{2})^3\) = 43
Also, (am)n = amn, a0 = 1
⇒ (23)0 = 23 × 0 = 20 = 1.

6. Find the value of (23)2.
a) 128
b) 16
c) 32
d) 64
View Answer

Answer: d
Explanation: (am)n = amn
⇒ (23)2 = 26 = 64.
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Sanfoundry Global Education & Learning Series – Mathematics – Class 8.

To practice all areas of Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.

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Manish Bhojasia - Founder & CTO at Sanfoundry
Manish Bhojasia, a technology veteran with 20+ years @ Cisco & Wipro, is Founder and CTO at Sanfoundry. He is Linux Kernel Developer & SAN Architect and is passionate about competency developments in these areas. He lives in Bangalore and delivers focused training sessions to IT professionals in Linux Kernel, Linux Debugging, Linux Device Drivers, Linux Networking, Linux Storage, Advanced C Programming, SAN Storage Technologies, SCSI Internals & Storage Protocols such as iSCSI & Fiber Channel. Stay connected with him @ LinkedIn | Youtube | Instagram | Facebook | Twitter