This set of Class 8 Maths Chapter 11 Multiple Choice Questions & Answers (MCQs) focuses on “Mensuration – Area of Trapezium – 2”.
1. Find the area of the given figure. (π = 3.14)
a) 30.28m2
b) 13.28m2
c) 26.28m2
d) 27.28m2
View Answer
Explanation: Area of the given figure = Area of square + semicircle + 2 × triangle
= (4)2 + π \(\frac{(2)^2}{2} + 2 × \frac{1}{2}\) × 4 × 2 = 30.28m2.
2. What is the area of the given figure? (π = \(\frac{22}{7}\))
a) 70m2
b) 35m2
c) 74m2
d) 60m2
View Answer
Explanation: Area = Area of rectangle – Area of circle = l × b – π(r)2 = 16 × 14 – \(\frac{22}{7}\) (7)2 = 70m2.
3. Find the area and perimeter of the given trapezium, respectively.
a) 30m2, 15m
b) 15m2, 30m
c) 15m2, 15m
d) 30m2, 30m
View Answer
Explanation: Area of trapezium = \(\frac{1}{2}\) × (p1 + p2) × h [(p1 + p2) = Σ of ∥sidesoftrapezium]
= \(\frac{1}{2}\) × (8 + 12) × 3 = 30m2
Perimeter = 4 + 8 + 6 + 12 = 30m.
4. Calculate the area of the given figure.
a) 7cm2
b) 7.5cm2
c) 6.5cm2
d) 8cm2
View Answer
Explanation: Area of general quadrilateral = \(\frac{1}{2}\) × (h1 + h2) × d [d is the length of diagonal]
= \(\frac{1}{2}\) × (1 + 1.5) × 6 = 7.5cm2.
5. The Area of trapezium shaped garden is 225m2. The distance between the two parallel sides is 25m. The length of one parallel side is 11m, what is the length of the other parallel side?
a) 7m
b) 8m
c) 6m
d) 5m
View Answer
Explanation: Area of trapezium = \(\frac{1}{2}\) × (p1 + p2) × h [(p1 + p2) = Σ of ∥ sidesoftrapezium]
⇒ 225m2 = \(\frac{1}{2}\) × (11 + p2) × 25
⇒ p2 = 7m.
6. The Area of trapezium is 800m2. The lenghts of the parallel sides is 28mand 12m. Find the height of the trapezium.
a) 22m
b) 42m
c) 40m
d) 20m
View Answer
Explanation: Area of trapezium = \(\frac{1}{2}\) × (p1 + p2) × h [(p1 + p2) = Σ of ∥ sidesoftrapezium]
⇒ 800m2 = \(\frac{1}{2}\) × (28 + 12) × h
⇒ h = 40m.
7. In a trapezium shaped ground, there is a square shaped lawn. The side of the lawn is 12m. The length of the parallel sides is 24m and 40m.The height of the ground is 30m. Find the area of the shaded portion.
a) 806m2
b) 336m2
c) 1776m2
d) 816m2
View Answer
Explanation: Area of the shaded portion = Area of trapezium(ground) – Area of square(lawn)
= \(\frac{1}{2}\) × (p1 + p2) × h – (s)2 = \(\frac{1}{2}\) × (40 + 24) × 30 – (12)2 = 816m2.
8. Find the area of the given Figure.
a) 42m2
b) 24m2
c) 14m2
d) 7m2
View Answer
Explanation: Area = Area of trapezium + Area of triangle = \(\frac{1}{2}\) × (p1 + p2) × h + \(\frac{1}{2}\) × b × h
= \(\frac{1}{2}\) × (5 + 3) × 2 + \(\frac{1}{2}\) × 4 × 3 = 14cm2.
9. What is the area of the given figure?
a) 10cm2
b) 13cm2
c) 12cm2
d) 11cm2
View Answer
Explanation: Area = Area of trapezium 1 + Area of trapezium 2
= \(\frac{1}{2}\) × (p1 + p2) × h1 + \(\frac{1}{2}\) × (p3 + p4) × h2 = \(\frac{1}{2}\) × (2 + 4) × 2 + \(\frac{1}{2}\) × (3 + 4) × 2 = 13cm2.
10. Find length of AE if area of the given figure is 15cm2.
a) 9 cm
b) 8 cm
c) 7 cm
d) 6 cm
View Answer
Explanation: Area of given figure = Area of trapezium + Area of triangle
⇒ 15cm2 = \(\frac{1}{2}\) × (p1 + p2) × h1 + \(\frac{1}{2}\) × b × h
⇒ 15cm2 = \(\frac{1}{2}\) × (4 + 3) × 2 + \(\frac{1}{2}\) × b × 2
⇒ b = 8 cm
⇒ length (AE) = 8 cm.
11. Compare the area of given trapezium.
a) B > A
b) B < A
c) B = A = 7cm2
d) B = A = 9cm2
View Answer
Explanation: Area of A = \(\frac{1}{2}\) × (p1 + p2) × h1 = \(\frac{1}{2}\) × (3 + 4) × 2 = 7cm2
Area of B = \(\frac{1}{2}\) × (p1 + p2) × h1 = \(\frac{1}{2}\) × (3 + 4) × 2 = 7cm2
⇒ Area of B = Area of A.
Sanfoundry Global Education & Learning Series – Mathematics – Class 8.
To practice all chapters and topics of class 8 Mathematics, here is complete set of 1000+ Multiple Choice Questions and Answers.
