Multiplication of Algebraic Expressions - Class 8 Maths MCQ

This set of Class 8 Maths Chapter 9 Multiple Choice Questions & Answers (MCQs) focuses on “Multiplication of Algebraic Expressions”.

1. Find the value when the given polynomials 3p and (24x + 14y²) are multiplied.
a) 72px + 42y²
b) 72px + 42y²p
c) 72px + 42yp
d) 114py²x
View Answer

Answer: b
Explanation: In the given question, a monomial is multiplied with a binomial.
3p(24x + 14y²) = 3p(24x) + 3p(42y²)
= 72px + 42y²p.

2. What is the resultant polynomial obtained when the given polynomials (a³) and (51cb² + 14abc) are multiplied?
a) 51cb²a³ + 14a⁴bc
b) 51a³cb + 14a⁴bc
c) 51cba² + 14a³bc
d) 51abc + 14a³bc
View Answer

Answer: a
Explanation: In the given question, a monomial is multiplied with a binomial.
a³(51cb² + 14abc) = 51cb² (a³) + 14abc(a³)
= 51cb²a³ + 14a⁴bc.

3. Find the product of the polynomials 82x and (2y + 2x²yz + 5x).
a) 164(xy + x³yz) + 410x
b) 164(xy² + x³yz) + 410x²
c) 164(xy + x²yz) + 410x²
d) 164(xy + x³yz) + 410x²
View Answer

Answer: d
Explanation: In the given question, a monomial is multiplied with a trinomial.
82x(2y + 2x²yz + 5x) = 82x(2y) + 82x(2x²yz) + 82x(5x)
= 164(xy + x³yz) + 410x².

4. Find the product of the polynomials 2pq and (9x + 2yx + 2x).
a) 18pqx + 4pqxy + 4px
b) 22pqx + 4pqxy
c) 18pqx + 4pqxy + 4pq
d) 22pqx + 4pqx
View Answer

Answer: b
Explanation: In the given question, a monomial is multiplied with a trinomial.
2pq(9x + 2yx + 2x) = 2pq(9x) + 2pq(2yx) +2pq(2x)
= 18pqx + 4pqxy + 4pqx
= 22pqx + 4pqxy.

5. What is the value obtained when [a(24b – 12c)] is subtracted from 2b(12a + 8c)?
a) -12ab + 16bc
b) 48ab + 28bc
c) 12ac + 16bc
d) -48ac + 28bc
View Answer

Answer: c
Explanation: In the given question, the terms are operated according to BODMAS Rule.
[2b(12a + 8c) – a(24b – 12c)] = [24ab + 16bc – 24ab + 12ac] = 12ac + 16bc.

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6. What is the value obtained when 48x² – 22z + 13xz is subtracted from 12x(2y – 8x)?
a) 24xy – 13xz + 144x²
b) 24xy + 13xz – 144x²
c) 24xy + 13xz + 144x²
d) 24xy – 13xz – 144x²
View Answer

Answer: d
Explanation: In the given question, the terms are operated according to BODMAS Rule.
[12x(2y – 8x) – (48x² – 22z + 13xz)] = 24xy – 96x² – 48x² + 22z – 13xz = 24xy – 13xz – 144x².

7. Find the polynomial obtained by adding (90s – 108ps)2q and (22q – 14s)14s.
a) 488qp + 216pqs – 196s²
b) 488qp – 216pqs – 196s²
c) 488qs – 216pqs – 196s²
d) 488qs + 216pqs – 196s²
View Answer

Answer: c
Explanation: In the given question, the terms are operated according to BODMAS Rule.
(90s – 108ps)2q + (22q – 14s)14s = 180sq – 216pqs + 308qs – 196s²
= 488qs – 216pqs – 196s².

8. What is the resultant polynomial if 12x²y + 22 and (24xy – 2x²)4y are added?
a) 4x²y – 96x² + 22
b) 108x²y + 4x² + 22
c) 108x²y + 4x² – 22
d) 4x²y + 96x² + 22
View Answer

Answer: d
Explanation: In the given question, the terms are operated according to BODMAS Rule.
12x²y + 22 + (24xy – 2x²)4y = 12x²y – 8 x²y + 96x² + 22 = 4x²y + 96x² + 22.

9. Find the result of the addition of the polynomials 12x(4y – 16y²) and (34y – 22) (12y + x²).
a) 48xy – 192xy² + 408y² – 34x²y – 264y – 22x²
b) 48xy – 158xy² + 408y² – 264y – 22x²
c) 48xy – 192xy² + 408y² + 34x²y – 264y – 22x²
d) 48xy + 192xy² + 408y² + 34x²y – 264y – 22x²
View Answer

Answer: c
Explanation: In the given question, the terms are operated according to BODMAS Rule.
12x(4y – 16y²) + (34y – 22) (12y + x²) = 48xy – 192xy² + 408y² + 34x²y – 264y – 22x².

10. What is the value attained when (2z – 3) (4w² – z) is subtracted from (6w² + 4) (22z – 2)?
a) 124w²z + 85z + 2z² – 3z – 8
b) 140w²z – 24w² + 91z – 2z² – 8
c) 124w²z – 85z + 2z² – 3z
d) 140w²z – 24w² – 91z – 2z² – 8
View Answer

Answer: a
Explanation: In the given question, the terms are operated according to BODMAS Rule.
(6w² + 4) (22z – 2) – (2z – 3) (4w² – z) = 132w²z – 12w² + 88z – 8 – [8w²z – 2z² – 12w² + 3z]
= 132w²z – 8w²z – 12w² + 12w² + 88z – 3z – 8 + 2z² = 124w²z + 85z + 2z² – 3z – 8.

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