# Mathematics Questions and Answers – Multiplication of Algebraic Expressions

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This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Multiplication of Algebraic Expressions”.

1. Find the value when the given polynomials 3p and (24x + 14y2) are multiplied.
a) 72px + 42y2
b) 72px + 42y2p
c) 72px + 42yp
d) 114py2x

Explanation: In the given question, a monomial is multiplied with a binomial.
3p(24x + 14y2) = 3p(24x) + 3p(42y2)
= 72px + 42y2p.

2. What is the resultant polynomial obtained when the given polynomials (a3) and (51cb2 + 14abc) are multiplied?
a) 51cb2a3 + 14a4bc
b) 51a3cb + 14a4bc
c) 51cba2 + 14a3bc
d) 51abc + 14a3bc

Explanation: In the given question, a monomial is multiplied with a binomial.
a3(51cb2 + 14abc) = 51cb2 (a3) + 14abc(a3)
= 51cb2a3 + 14a4bc.

3. Find the product of the polynomials 82x and (2y + 2x2yz + 5x).
a) 164(xy + x3yz) + 410x
b) 164(xy2 + x3yz) + 410x2
c) 164(xy + x2yz) + 410x2
d) 164(xy + x3yz) + 410x2

Explanation: In the given question, a monomial is multiplied with a trinomial.
82x(2y + 2x2yz + 5x) = 82x(2y) + 82x(2x2yz) + 82x(5x)
= 164(xy + x3yz) + 410x2.

4. Find the product of the polynomials 2pq and (9x + 2yx + 2x).
a) 18pqx + 4pqxy + 4px
b) 22pqx + 4pqxy
c) 18pqx + 4pqxy + 4pq
d) 22pqx + 4pqx

Explanation: In the given question, a monomial is multiplied with a trinomial.
2pq(9x + 2yx + 2x) = 2pq(9x) + 2pq(2yx) +2pq(2x)
= 18pqx + 4pqxy + 4pqx
= 22pqx + 4pqxy.

5. What is the value obtained when [a(24b – 12c)] is subtracted from 2b(12a + 8c)?
a) 28ab
b) 48ab + 28bc
c) 28bc
d) -48ab + 28bc

Explanation: In the given question, the terms are operated according to BODMAS Rule.
[2b(12a + 8c) – a(24b – 12c)] = [24ab + 16bc – 24ab + 12ac] = 28bc.

6. What is the value obtained when 48x2 – 22z + 13xz is subtracted from 12x(2y – 8x)?
a) 24xy – 13xz + 144x2
b) 24xy + 13xz – 144x2
c) 24xy + 13xz + 144x2
d) 24xy – 13xz – 144x2

Explanation: In the given question, the terms are operated according to BODMAS Rule.
[12x(2y – 8x) – (48x2 – 22z + 13xz)] = 24xy – 96x2 – 48x2 + 22z – 13xz = 24xy – 13xz – 144x2.

7. Find the polynomial obtained by adding (90s – 108ps)2q and (22q – 14s)14s.
a) 488qp + 216pqs – 196s2
b) 488qp – 216pqs – 196s2
c) 488qs – 216pqs – 196s2
d) 488qs + 216pqs – 196s2

Explanation: In the given question, the terms are operated according to BODMAS Rule.
(90s – 108ps)2q + (22q – 14s)14s = 180sq – 216pqs + 308qs – 196s2
= 488qs – 216pqs – 196s2.

8. What is the resultant polynomial if 12x2y + 22 and (24xy – 2x2)4y are added?
a) 4x2y – 96x2 + 22
b) 108x2y + 4x2 + 22
c) 108x2y + 4x2 – 22
d) 4x2y + 96x2 + 22

Explanation: In the given question, the terms are operated according to BODMAS Rule.
12x2y + 22 + (24xy – 2x2)4y = 12x2y – 8 x2y + 96x2 + 22 = 4x2y + 96x2 + 22.

9. Find the result of the addition of the polynomials 12x(4y – 16y2) and (34y – 22) (12y + x2).
a) 48xy – 192xy2 + 408y2 – 34x2y – 264y – 22x2
b) 48xy – 158xy2 + 408y2 – 264y – 22x2
c) 48xy – 192xy2 + 408y2 + 34x2y – 264y – 22x2
d) 48xy + 192xy2 + 408y2 + 34x2y – 264y – 22x2

Explanation: In the given question, the terms are operated according to BODMAS Rule.
12x(4y – 16y2) + (34y – 22) (12y + x2) = 48xy – 192xy2 + 408y2 + 34x2y – 264y – 22x2.

10. What is the value attained when (6w2 + 4) (22z – 2) is subtracted from (2z – 3) (4w2 – z)?
a) 124w2z + 85z + 2z2 – 3z
b) 140w2z – 24w2 + 91z – 2z2 – 8
c) 124w2z – 85z + 2z2 – 3z
d) 140w2z – 24w2 – 91z – 2z2 – 8

Explanation: In the given question, the terms are operated according to BODMAS Rule.
(6w2 + 4) (22z – 2) – (2z – 3) (4w2 – z) = 132w2z – 12w2 + 88z – 8 – [8w2z – 2z2 – 12w2 + 3z]
= 132w2z – 8w2z – 12w2 + 12w2 + 88z – 3z – 8 + 2z2 = 124w2z + 85z + 2z2 – 3z.

Sanfoundry Global Education & Learning Series – Mathematics – Class 8.

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