This set of Mathematics Multiple Choice Questions & Answers (MCQs) focuses on “Comparing Very Small and Large Number”.

1. Mass of object A is 120000 and that of B is 0.240. Compare their masses.

a) Mass of Object B is approximately is 10^{5} times larger than A

b) Mass of Object A is approximately is 10^{5} times larger than B

c) Mass of Object A is approximately is 10^{6} times larger than B

d) Mass of Object B is approximately is 10^{6} times larger than A

View Answer

Explanation: \(\frac{mass\, of\, object\, A}{mass\, of\, object\, B} = \frac{1.2 × 10^5}{2.4 × 10^{-1}} = \frac{1.2 × 10^6}{2.4}\)

⇒ Mass of Object A is approximately is 10

^{6}times larger than B.

2. Compare the radius of circle P (r_{1} = 10.2 × 10^{-6}) with the radius of circle B (r_{1} = 0.2 × 10^{-5}).

a) r_{1} = 6.1r_{2}

b) r_{2} = 5r_{1}

c) r_{1} = 5r_{2}

d) r_{1} = 5.1r_{2}

View Answer

Explanation: \(\frac{r_1}{r_2} = \frac{10.2 × 10^{-6}}{0.2 × 10^{-5}} = \frac{10.2 × 10^{-1}}{0.2}\) = \(\frac{1.02}{0.2}\) = 5.1.

3. Mass of a neutron is 1.675 × 10^{-27} and mass of proton is 1.672 × 10^{-27}. Find the total mass.

a) 3.347 × 10^{-27}

b) 3.337 × 10^{-27}

c) 3.447 × 10^{-27}

d) 3.357 × 10^{-27}

View Answer

Explanation: Total mass = mass of neutron + mass of proton = 1.675 × 10

^{-27}+ 1.672 × 10

^{-27}= (1.675 + 1.672) × 10

^{-27}= 3.347 × 10

^{-27}.

4. Distance between A to C is 2.1 × 10^{11} and that of A to B is 3.12 × 10^{9}. Find the distance between B and C.

a) 2.1312 × 10^{11}

b) 2.0412 × 10^{11}

c) 2.1312 × 10^{11}

d) 2.1312 × 10^{10}

View Answer

Explanation: Distance between B and C = AC – AB = 2.1 × 10

^{11}– 3.12 × 10

^{9}= (2.1 + 0.0312) × 10

^{11}= 2.1312 × 10

^{11}.

5. Compare volumes of cube A having side 2 × 10^{2} m and cube B having side 1 × 10^{1} m.

a) V_{1} = 800V_{2}

b) V_{1} = 8000V_{2}

c) V_{2} = 8000V_{1}

d) V_{2} = 800V_{1}

View Answer

Explanation: volume of cube A = (2 × 10

^{2})

^{3}= 8 × 10

^{6}m

^{3}.

⇒ Volume of cube B = (10

^{1})

^{3}= 10

^{3}

⇒ \(\frac{V_1}{V_2} = \frac{8 × 10^6}{10^3}\) = 8000.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 8**.

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