This set of Electromagnetic Theory Multiple Choice Questions & Answers (MCQs) focuses on “Coulomb law”.

1. Coulomb is the unit of which quantity?

a) Field strength

b) Charge

c) Permittivity

d) Force

View Answer

Explanation: The standard unit of charge is Coulomb. One coulomb is defined as the 1 Newton of force applied on 1 unit of electric field.

2. Coulomb law is employed in

a) Electrostatics

b) Magnetostatics

c) Electromagnetics

d) Maxwell theory

View Answer

Explanation: Coulomb law is applied to static charges. It states that force between any two point charges is proportional to the product of the charges and inversely proportional to square of the distance between them. Thus it is employed in electrostatics.

3. Find the force between 2C and -1C separated by a distance 1m in air(in newton).

a) 18 X 10^{6}

b) 18 X 10^{9}

c) 18 X 10^{-6}

d) 18 X 10^{8}

View Answer

Explanation: To find the force between two charges q1 and q2 separated by a distance r, we can use Coulomb’s law: F = k x |q1q2|/r

^{2}where k is coulomb’s constant (approx value 8.9875 x 10

^{9}), q1 and q2 are magnitudes of the charges, and r is the distance between them. So,

F = (8.9875 x 10

^{9}x |2 x -1|) /1

^{2}(we have to take absolute value of q1q2)

F = 17.975 x 10

^{9}≈ 18 x 10

^{9}

4. Two charges 1C and -4C exists in air. What is the direction of force?

a) Away from 1C

b) Away from -4C

c) From 1C to -4C

d) From -4C to 1C

View Answer

Explanation: Since the charges are unlike, the force will be attractive. Thus the force directs from 1C to -4C.

5. Find the force of interaction between 60 stat coulomb and 37.5 stat coulomb spaced 7.5cm apart in transformer oil(εr=2.2) in 10^{-4} N,

a) 8.15

b) 5.18

c) 1.518

d) 1.815

View Answer

Explanation: 1 stat coulomb = 1/(3 X 10

^{9}) C

F = (1.998 X 1.2488 X 10

^{-16})/(4∏ X 8.854 X 10

^{-12}X 2.2 X (7.5 X 10

^{-2})

^{2}) = 1.815 X 10

^{-4}N.

6. Find the force between two charges when they are brought in contact and separated by 4cm apart, charges are 2nC and -1nC, in μN.

a) 1.44

b) 2.44

c) 1.404

d) 2.404

View Answer

Explanation: Before the charges are brought into contact, F = 11.234 μN.

After charges are brought into contact and then separated, charge on each sphere is, (q1 + q2)/2 = 0.5nC

On calculating the force with q1 = q2 = 0.5nC, F = 1.404μN.

7. The Coulomb law is an implication of which law?

a) Ampere law

b) Gauss law

c) Biot Savart law

d) Lenz law

View Answer

Explanation: The Coulomb law can be formulated from the Gauss law, using the divergence theorem. Thus it is an implication of Gauss law.

8. Two small diameter 10gm dielectric balls can slide freely on a vertical channel. Each carry a negative charge of 1μC. Find the separation between the balls if the lower ball is restrained from moving.

a) 0.5

b) 0.4

c) 0.3

d) 0.2

View Answer

Explanation: F = mg = 10 X 10

^{-3}X 9.81 = 9.81 X 10

^{-2}N.

On calculating r by substituting charges, we get r = 0.3m.

9. A charge of 2 X 10^{-7} C is acted upon by a force of 0.1N. Determine the distance to the other charge of 4.5 X 10^{-7} C, both the charges are in vacuum.

a) 0.03

b) 0.05

c) 0.07

d) 0.09

View Answer

Explanation: F = q1q2/(4∏εor

^{2}) , substituting q1, q2 and F, r2 = q1q2/(4∏εoF) =

We get r = 0.09m.

10. For a charge Q1, the effect of charge Q2 on Q1 will be,

a) F1 = F2

b) F1 = -F2

c) F1 = F2 = 0

d) F1 and F2 are not equal

View Answer

Explanation: The force of two charges with respect with each other is given by F1 and F2. Thus F1 + F2 = 0 and F1 = -F2.

**Sanfoundry Global Education & Learning Series – Electromagnetic Theory.**

To practice all areas of Electromagnetic Theory, __here is complete set of 1000+ Multiple Choice Questions and Answers__.

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