This set of Class 9 Maths Chapter 13 Multiple Choice Questions & Answers (MCQs) focuses on “Volume of a Cylinder”.

1. Volume of a cylinder having radius r and height h is given by __________

a) r * h^{2}

b) h * r^{2}

c) πr^{2}h

d) \(\frac{1}{3}\)πr^{2}h

View Answer

Explanation: Volume of a cylinder can be given by multiplying base area with its height.

Hence, volume of a cylinder having radius r and height h is equal to πr

^{2}h where πr

^{2}is base area and h is height.

2. A cylinder has radius of 7cm and its volume is 1540cm^{3}, what is the height of the cylinder? (Take π = \(\frac{22}{7}\))

a) 10cm

b) 14cm

c) 11cm

d) 15cm

View Answer

Explanation: Volume of a cylinder having radius r and height h is equal to πr

^{2}h.

πr

^{2}h = 1540

\(\frac{22}{7}\) * 7 * 7 * h = 1540

h = 10cm.

3. A cylinder has volume of 176cm^{3} and height equal to 14cm, what is the diameter of the cylinder? (Take π = \(\frac{22}{7}\))

a) 6cm

b) 8cm

c) 2cm

d) 4cm

View Answer

Explanation: Volume of a cylinder having radius r and height h is equal to πr

^{2}h.

πr

^{2}h = 176

\(\frac{22}{7}\) * 14 * r

^{2}= 176

r

^{2}= 4

Therefore, r = 2cm

We know that diameter = 2 * radius

= 2 * 2

= 4cm.

4. A glass of cylindrical shape has radius of 3.5cm and height equal to 8cm. A water jug has a volume equal to 1540cm^{3}. How many times the water has to be poured from glass to fill the jug completely? (Take π = \(\frac{22}{7}\))

a) 6

b) 5

c) 4.5

d) 4

View Answer

Explanation: Volume of a cylindrical glass = πr

^{2}h

= \(\frac{22}{7}\) * 3.5 * 3.5 * 8

= 308cm

^{3}

Volume of a water jug = 1540cm

^{3}

Therefore, number of times the water has to be poured from glass to fill the jug completely

= \(\frac{Volume \,of \,a \,water \,jug}{Volume \,of \,a \,cylindrical \,glass} = \frac{1540}{308}\)

= 5.

5. Cylindrical pillars are to be made for a flat whose radius is 15cm and height is 3.5m. What is the total amount of concrete (in cm^{3}) required to make 15 identical pillars? (Take π = \(\frac{22}{7}\))

a) 3513600

b) 3712500

c) 4125300

d) 3917800

View Answer

Explanation: Volume of one cylindrical pillar = πr

^{2}h

= \(\frac{22}{7}\) * 15 * 15 * 350

= 247500cm

^{3}

Hence, total volume of 15 pillars = 15 * 247500

= 3712500cm

^{3}

Therefore, the total amount of concrete required to make 15 identical pillars = 3712500cm

^{3}.

6. A cylinder has a base area equal to 21cm^{2} and height equal to 11cm. What is the volume of the cylinder? (Take π = \(\frac{22}{7}\))

a) 230cm^{3}

b) 220cm^{3}

c) 225cm^{3}

d) 231cm^{3}

View Answer

Explanation: We know that base area of a cylinder is equal to πr

^{2}.

Volume of a cylinder = πr

^{2}h

= 21 * 11

= 231cm

^{3}.

7. A steel pipe has outer radius equal to 3cm and inner radius equal to 2cm. Its length is equal to 5m. What is the mass of the pipe if one cm^{3} of steel is 8.05 gram? (Take π = \(\frac{22}{7}\))

a) 63.25 kg

b) 65 kg

c) 67 kg

d) 61 kg

View Answer

Explanation: Let the outer radius = r

_{o}= 3cm

Inner radius = r

_{i}= 2cm

Height (here length) = l = 5m = 500cm

Volume of pipe = π * (r

_{o}

^{2}– r

_{i}

^{2}) * l

= \(\frac{22}{7}\) * (3

^{2}– 2

^{2}) * 500

= 7857.14cm

^{3}

Mass of 1cm

^{3}is 8.05 gram

Therefore, mass of 7857.14cm

^{3}is equal to 8.05 * 7857.14

= 63249.97gm

≈ 63250 gm

= 63.25 kg.

**Sanfoundry Global Education & Learning Series – Mathematics – Class 9**.

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